Problem 46
Question
Transformations Use transformations of the graph of either \(f(x)=\frac{1}{x}\) or \(h(x)=\frac{1}{x^{2}}\) to sketch a graph of \(y=g(x)\) by hand. Show all asymptotes. Write \(g(x)\) in terms of either \(f(x)\) or \(h(x)\) $$ g(x)=\frac{1}{x+2} $$
Step-by-Step Solution
Verified Answer
The graph of \(g(x)\) is \(f(x+2)\), shifted left by 2 units, with asymptotes at \(x=-2\) and \(y=0\).
1Step 1: Identify the Base Function
The given function is \(g(x) = \frac{1}{x+2}\). This resembles the function \(f(x) = \frac{1}{x}\). Therefore, we'll use \(f(x)\) as our base function.
2Step 2: Determine the Transformation
The function \(g(x) = \frac{1}{x+2}\) can be rewritten in terms of \(f(x)\) by identifying the transformation as a horizontal shift. \(g(x)\) can be expressed as \(f(x+2)\). This represents a shift of the graph of \(f(x)\) left by 2 units.
3Step 3: Analyze the Asymptotes
For \(f(x) = \frac{1}{x}\), the vertical asymptote is at \(x = 0\). After shifting 2 units left, for \(g(x)\), the vertical asymptote moves to \(x = -2\). There is no horizontal asymptote shifting, so it remains at \(y = 0\).
4Step 4: Sketch the Graph
Draw the axes and plot the vertical asymptote at \(x = -2\) and the horizontal asymptote at \(y = 0\). Sketch the hyperbola that approaches these asymptotes as \(x\) moves away from \(-2\) and 0.
Key Concepts
Rational FunctionsAsymptotesHorizontal Shifts
Rational Functions
Rational functions are a special type of function represented by the ratio of two polynomials. The simplest form of a rational function is \( f(x) = \frac{1}{x} \), where the numerator is 1 and the denominator is the polynomial \( x \).
This type of function inherently has certain "rules" it follows, like undefined points, which are points where the function does not have a real number output.
In our example, we're considering \( g(x) = \frac{1}{x+2} \), clearly a transformation of our base rational function \( f(x) = \frac{1}{x} \).
This type of function inherently has certain "rules" it follows, like undefined points, which are points where the function does not have a real number output.
In our example, we're considering \( g(x) = \frac{1}{x+2} \), clearly a transformation of our base rational function \( f(x) = \frac{1}{x} \).
- Mainly, rational functions have a classic hyperbola shape when graphed.
- They tend to have very specific transformations influenced by their equations, which can help when sketching.
Asymptotes
Asymptotes are like invisible boundary lines that guide the behavior of a graph.
In the context of rational functions, these are lines that the graph approaches but never really "touches".
There are typically two types we care about:
In the context of rational functions, these are lines that the graph approaches but never really "touches".
There are typically two types we care about:
- Vertical asymptotes: Occur where the denominator of the rational function becomes zero, meaning the function itself is undefined at these points. For \( f(x) = \frac{1}{x} \), the vertical asymptote is at \( x = 0 \), but when transformed to \( g(x) = \frac{1}{x+2} \), the vertical asymptote shifts to \( x = -2 \).
- Horizontal asymptotes: These represent the value that a function approaches as \( x \) becomes very large or very small. In both \( f(x) = \frac{1}{x} \) and \( g(x) = \frac{1}{x+2} \), there is a horizontal asymptote at \( y = 0 \).
Horizontal Shifts
A horizontal shift in graph transformations involves moving the graph of a function left or right along the x-axis without affecting its shape.
For an original function \( f(x) \), a transformation written as \( f(x + c) \) would imply a leftward shift by \( c \) units, where \( c \) is a positive number.
In our example, transforming \( f(x) = \frac{1}{x} \) to \( g(x) = \frac{1}{x+2} \) represents a shift to the left by 2 units.
This is because the \( x \) in the denominator is replaced with \( x+2 \), indicating each point on the graph moves leftwards.
For an original function \( f(x) \), a transformation written as \( f(x + c) \) would imply a leftward shift by \( c \) units, where \( c \) is a positive number.
In our example, transforming \( f(x) = \frac{1}{x} \) to \( g(x) = \frac{1}{x+2} \) represents a shift to the left by 2 units.
This is because the \( x \) in the denominator is replaced with \( x+2 \), indicating each point on the graph moves leftwards.
- Horizontal shifts are straightforward to identify as they always affect the function indirectly through the input variable, \( x \).
- They help us understand how individual points of the function adjust across the Cartesian plane without changing the function's general structure or orientation.
Other exercises in this chapter
Problem 46
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