Problem 46
Question
The heat experienced by a hiker at a campfire is proportional to the amount of wood on the fire and inversely proportional to the cube of his distance from the fire. If the hiker is \(20 \mathrm{ft}\) from the fire and someone doubles the amount of wood burning, how far from the fire would he have to be so that he feels the same heat as before?
Step-by-Step Solution
Verified Answer
The hiker should be 25 ft from the fire.
1Step 1: Understanding the Relationship
The heat experienced, let's call it \( H \), is proportional to the amount of wood \( W \) and inversely proportional to the cube of the distance \( d \) from the fire. This can be expressed as \( H \propto \frac{W}{d^3} \), or more specifically, \( H = k \frac{W}{d^3} \) where \( k \) is a constant of proportionality.
2Step 2: Initial Situation Model
Initially, the hiker experiences a certain heat at 20 ft with a certain amount of wood. Let's represent this initial condition as \( H_1 = k \frac{W}{20^3} \).
3Step 3: After Doubling the Wood
The amount of wood is doubled, so the new heat \( H_2 \) is \( H_2 = k \frac{2W}{d_2^3} \). We want \( H_1 = H_2 \).
4Step 4: Set Equations Equal
Set the expressions for \( H_1 \) and \( H_2 \) equal to each other to find \( d_2 \): \( k \frac{W}{20^3} = k \frac{2W}{d_2^3} \).
5Step 5: Solve for New Distance
Cancel the constant \( k \) and the wood \( W \) from each side: \( \frac{1}{20^3} = \frac{2}{d_2^3} \). Solve for \( d_2^3 \): \( d_2^3 = 2 imes 20^3 \). Therefore, \( d_2 = \sqrt[3]{2 imes 20^3} \).
6Step 6: Calculate the Value
Calculate \( 20^3 = 8000 \). Then \( d_2^3 = 16000 \), thus \( d_2 = \sqrt[3]{16000} \), which is 25.
Key Concepts
Inverse ProportionalityCube RelationshipDistance and Heat Relationship
Inverse Proportionality
When we talk about inverse proportionality, we're dealing with two quantities that change in opposite directions. This means if one quantity increases, the other decreases, and vice versa. A simple example to understand this is through the equation: \( y \propto \frac{1}{x} \), which can also be written as \( y = \frac{k}{x} \). Here, \( k \) is a constant. As \( x \) grows larger, \( y \) becomes smaller because they are inversely related.
In the context of the hiker and the campfire, the heat (\( H \)) the hiker feels is inversely proportional to the cube of the distance (\( d^3 \)) he's standing from the fire. Simply put, as the hiker moves away, the heat reduces because \( d^3 \) increases, making \( H \) decrease if all other factors stay constant.
In the context of the hiker and the campfire, the heat (\( H \)) the hiker feels is inversely proportional to the cube of the distance (\( d^3 \)) he's standing from the fire. Simply put, as the hiker moves away, the heat reduces because \( d^3 \) increases, making \( H \) decrease if all other factors stay constant.
- The concept helps define how variables relate when one diminishes as the other rises.
- It models behaviors in natural phenomena, like how heat diminishes with distance.
Cube Relationship
The cube relationship concept is key when the rate of change affects three dimensions simultaneously. In mathematical terms, a cube relationship refers to a variable being proportional to the cube of another variable. For example, \( y \propto x^3 \) can be expressed as \( y = kx^3 \), where \( k \) is a constant.
In our campfire scenario, the cube of the distance (\( d^3 \)) impacts how heat is perceived by the hiker. The heat primarily depends on the ratio of the wood's amount and the distance cubed. The formula \( H = k \frac{W}{d^3} \) showcases how the cube affects heat inversely.
In our campfire scenario, the cube of the distance (\( d^3 \)) impacts how heat is perceived by the hiker. The heat primarily depends on the ratio of the wood's amount and the distance cubed. The formula \( H = k \frac{W}{d^3} \) showcases how the cube affects heat inversely.
- This relationship implies a rapid change: shift a bit in distance, and the heat changes drastically.
- The effect is that moving away doubles the cube of the distance, noticeably reducing heat felt.
Distance and Heat Relationship
The distance and heat relationship illustrates how physical distance from a source affects heat intensity. As found in the problem statement, the heat (\( H \)) experienced is directly proportional to the amount of wood and inversely proportional to the cube of the distance (\( d^3 \)) from the fire. This relationship is crucial because it highlights two simultaneous dependencies:
- Direct Proportionality with Wood: More wood results in more heat, assuming distance is constant.
- Inverse Cubic Proportionality with Distance: Moving further away decreases the heat, as the distance exponentially reduces the heat intensity received.
Other exercises in this chapter
Problem 46
Perform the indicated operations and simplify. $$(x+1)\left(2 x^{2}-x+1\right)$$
View solution Problem 46
Perform the addition or subtraction and simplify. $$\frac{5}{2 x-3}-\frac{3}{(2 x-3)^{2}}$$
View solution Problem 46
Express the interval in terms of inequalities, and then graph the interval. $$(2,8]$$
View solution Problem 46
Simplify the expression and eliminate any negative exponents(s). (a) \(\frac{2 x^{3} y^{4}}{x^{5} y^{3}}\) (b) \(\frac{\left(2 v^{3} w\right)^{2}}{v^{3} w^{2}}\
View solution