Problem 46
Question
The dimensions of matrices \(A\) and \(B\) are given. Find the dimensions of the product \(A B\) and of the product BA if the products are defined. If they are not defined, say so. $$A \text { is } 1 \times 6 ; B \text { is } 2 \times 4$$
Step-by-Step Solution
Verified Answer
Neither \(AB\) nor \(BA\) is defined.
1Step 1: Understanding Matrix Multiplication
Matrix multiplication is defined when the number of columns in the first matrix equals the number of rows in the second matrix. The resulting product has dimensions equal to the number of rows in the first matrix and the number of columns in the second matrix.
2Step 2: Checking Multiplicability of AB
Matrix \(A\) is \(1 \times 6\) and matrix \(B\) is \(2 \times 4\). For the multiplication \(AB\) to be defined, the number of columns in \(A\) (6) must equal the number of rows in \(B\) (2). Since they do not match, the product \(AB\) is not defined.
3Step 3: Checking Multiplicability of BA
Matrix \(B\) is \(2 \times 4\) and matrix \(A\) is \(1 \times 6\). For the multiplication \(BA\) to be defined, the number of columns in \(B\) (4) must equal the number of rows in \(A\) (1). Since they do not match, the product \(BA\) is not defined.
Key Concepts
Matrix DimensionsMultiplicabilityUndefined Product
Matrix Dimensions
When dealing with matrices, it's essential to understand the concept of their dimensions. A matrix is essentially an array of numbers arranged in rows and columns. The size or dimensions of a matrix are described in terms of its number of rows and columns.
For example, if a matrix has 1 row and 6 columns, we call it a \(1 \times 6\) matrix. Similarly, a \(2 \times 4\) matrix includes 2 rows and 4 columns.
For example, if a matrix has 1 row and 6 columns, we call it a \(1 \times 6\) matrix. Similarly, a \(2 \times 4\) matrix includes 2 rows and 4 columns.
- The first number in the dimension indicates the number of rows.
- The second number indicates the number of columns.
Multiplicability
Matrix multiplicability depends strictly on the dimensions of the matrices involved. To determine if two matrices can be multiplied, you should compare the dimensions. Matrix multiplication is permissible only if the number of columns in the first matrix is the same as the number of rows in the second matrix.
For instance, to multiply matrix \(A\) with dimensions \(1 \times 6\) by matrix \(B\) with dimensions \(2 \times 4\), you check the match between the number of columns in \(A\) (which is 6) and the number of rows in \(B\) (which is 2). Since 6 does not equal 2, matrices \(A\) and \(B\) cannot be multiplied in the order \(AB\).
For instance, to multiply matrix \(A\) with dimensions \(1 \times 6\) by matrix \(B\) with dimensions \(2 \times 4\), you check the match between the number of columns in \(A\) (which is 6) and the number of rows in \(B\) (which is 2). Since 6 does not equal 2, matrices \(A\) and \(B\) cannot be multiplied in the order \(AB\).
- The multiplication \(AB\) is not defined since the necessary condition \(\text{columns of } A = \text{rows of } B\) is not satisfied.
- This rule helps prevent errors when working with matrix operations and ensures that the multiplication process is meaningful and correct.
Undefined Product
An undefined matrix product occurs when the matrices involved do not satisfy the necessary condition for multiplication, specifically the matched dimensions rule.
In our example, both matrix products, \(AB\) and \(BA\), are undefined because their dimensions do not allow for multiplication.
In our example, both matrix products, \(AB\) and \(BA\), are undefined because their dimensions do not allow for multiplication.
- For \(AB\) to be defined, the number of columns in \(A\)\( (6) \) would need to match the number of rows in \(B\)\( (2) \), which they do not.
- For \(BA\) to be defined, the number of columns in \(B\)\( (4) \) would have to equal the number of rows in \(A\)\( (1) \), which again, they do not.
Other exercises in this chapter
Problem 46
Solve each system by using the matrix inverse method. $$\begin{aligned} 3 x+2 y-w &=0 \\ 2 x+z+2 w &=5 \\ x+2 y-z &=-2 \\ 2 x-y+z+w &=2 \end{aligned}$$
View solution Problem 46
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} x+y &=1 \\ 2 x-z &=
View solution Problem 46
Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{array}{r} x+3 y+z=6 \\ 3 x+y-z=6
View solution Problem 46
Solve each system by elimination. $$\begin{aligned}&\frac{x+6}{5}+\frac{2 y-x}{10}=1\\\&\frac{x+2}{4}+\frac{3 y+2}{5}=-3\end{aligned}$$
View solution