Problem 46
Question
Solve each proportion. $$ \frac{y}{4}=\frac{4}{y} $$
Step-by-Step Solution
Verified Answer
The values of \( y \) are \( 4 \) and \( -4 \).
1Step 1: Cross-Multiply the Proportion
Start by cross-multiplying the terms of the proportion: \( \frac{y}{4} = \frac{4}{y} \). This means multiplying the numerator of one fraction by the denominator of the other and setting the products equal: \( y \cdot y = 4 \cdot 4 \).
2Step 2: Simplify the Equation
Perform the multiplications from Step 1 to simplify the equation. You get: \( y^2 = 16 \).
3Step 3: Solve for y
Take the square root of both sides of the equation from Step 2 to solve for \( y \). \( y = \pm \sqrt{16} \).
4Step 4: Find the Values of y
Calculate the square root from Step 3: \( y = \pm 4 \). This means that \( y \) can be either \( 4 \) or \( -4 \).
Key Concepts
Cross-MultiplicationSolving EquationsSquare Roots
Cross-Multiplication
Cross-multiplication is a powerful tool often used in solving proportions. It is especially useful when you have two fractions set equal to each other, as in the original exercise. Cross-multiplication involves multiplying across the equals sign in a criss-cross manner. This means you multiply the numerator of the first fraction by the denominator of the second fraction, and vice versa.
For example, with the proportion \( \frac{y}{4} = \frac{4}{y} \), you multiply \( y \) (the numerator of the first fraction) by \( y \) (the denominator of the second fraction), and \( 4 \) by \( 4 \). This results in the equation \( y \cdot y = 4 \cdot 4 \).
For example, with the proportion \( \frac{y}{4} = \frac{4}{y} \), you multiply \( y \) (the numerator of the first fraction) by \( y \) (the denominator of the second fraction), and \( 4 \) by \( 4 \). This results in the equation \( y \cdot y = 4 \cdot 4 \).
- Cross-multiplication transforms a proportion into a simple equation, making it easier to solve.
- It is crucial to ensure that neither side of the equation equals zero, as dividing by zero is undefined.
Solving Equations
Once you have applied cross-multiplication, the next step is to solve the resulting equation. In our case, after cross-multiplying, we obtained \( y^2 = 16 \). Solving equations generally involves isolating the variable, in this case, \( y \).
You simplify this equation by completing the multiplications, as was done in the solution, where \( y \cdot y \) simplifies to \( y^2 \), and \( 4 \cdot 4 \) simplifies to 16.
You simplify this equation by completing the multiplications, as was done in the solution, where \( y \cdot y \) simplifies to \( y^2 \), and \( 4 \cdot 4 \) simplifies to 16.
- The goal is to get the variable on one side of the equation while everything else is on the other side.
- Simplifying an equation is often about performing arithmetic operations like multiplication or division on both sides to maintain equality.
Square Roots
Taking square roots is a method used to solve equations involving squared terms. Once we have simplified the equation to \( y^2 = 16 \), the challenge is to find \( y \). The square root function helps us step away from the squared variable to find potential solutions for \( y \).
When you take the square root of both sides of an equation, such as here, we perform \( y = \pm \sqrt{16} \). This step is crucial because every positive number has two square roots: one positive and one negative.
When you take the square root of both sides of an equation, such as here, we perform \( y = \pm \sqrt{16} \). This step is crucial because every positive number has two square roots: one positive and one negative.
- The symbol \( \pm \) indicates that both the positive and negative square roots are valid solutions.
- For \( \sqrt{16} \), the results are 4 and -4, reflecting the two possible values of \( y \).
Other exercises in this chapter
Problem 45
Divide, and then simplify, if possible. \(\frac{27 p^{4}}{35 q} \div \frac{9 p}{21 q}\)
View solution Problem 46
Perform the operations. Simplify, if possible. $$ \frac{6}{s^{2}-9}-\frac{5}{s^{2}-s-6} $$
View solution Problem 46
Simplify each complex fraction. See Example 6 $$ \frac{\frac{1}{x-1}}{1-\frac{1}{x-1}} $$
View solution Problem 46
Solve each equation and check the result. If an equation has no solution, so indicate. $$ \frac{4 x}{x^{2}+2 x-3}+\frac{3}{x+3}=1 $$
View solution