Problem 46
Question
Solve each equation. Do not use a calculator. $$e^{3-x}=\left(e^{3}\right)^{-x}$$
Step-by-Step Solution
Verified Answer
The solution is \( x = -\frac{3}{2} \).
1Step 1: Analyze the Equation Form
The given equation is \( e^{3-x} = (e^3)^{-x} \). Recognize that \( (e^3)^{-x} \) can be rewritten as \( e^{-3x} \) since the property of exponents states \( a^{-b} = \frac{1}{a^b} \). Thus, rewriting the equation, we have \( e^{3-x} = e^{-3x} \).
2Step 2: Set the Exponents Equal
Since the bases are the same (\(e\)), we set the exponents equal to one another to solve the equation: \( 3 - x = -3x \).
3Step 3: Simplify the Equation
Rearrange the equation \( 3 - x = -3x \) to isolate \( x \). First, add \( 3x \) to both sides: \( 3 - x + 3x = 0 \) which simplifies to \( 3 + 2x = 0 \).
4Step 4: Solve for x
Solve the equation \( 3 + 2x = 0 \) for \( x \). Subtract 3 from both sides to get \( 2x = -3 \). Then, divide both sides by 2, giving \( x = -\frac{3}{2} \).
Key Concepts
Exponential FunctionsProperties of ExponentsSolving Algebraic Equations
Exponential Functions
Exponential functions are an essential mathematical concept, characterized by a variable exponent like in the expression \( e^{x} \). In an exponential function, the base remains constant while the exponent varies, which allows these functions to model many real-world phenomena such as population growth, radioactive decay, and interest calculation.
- The general form of an exponential function is \( f(x) = a \, b^{x} \), where \( a \) is a constant coefficient, \( b \) is the base of the exponential, and \( x \) is the variable exponent.
- For the specific case involving the natural exponential function \( e \), which is approximately 2.718, often referred to as Euler's number, many natural logarithms and calculations become simplified.
- In exponential equations, the same base on both sides of an equation allows us to set exponents equal, simplifying the problem significantly.
Properties of Exponents
The properties of exponents are rules that simplify calculations and expressions involving powers. These rules are crucial for solving equations like \( e^{3-x} = (e^3)^{-x} \). Knowing these properties allows mathematicians and students to transform and solve equations by manipulating exponents.
- **Power of a Power:** \((a^m)^n = a^{m \cdot n}\). This means raising an exponent to another power multiplies the exponents.
- **Product of Powers:** \(a^m \cdot a^n = a^{m+n}\). When multiplying like bases, simply add the exponents.
- **Quotient of Powers:** \(\frac{a^m}{a^n} = a^{m-n}\). When dividing like bases, subtract the exponents.
- **Negative Exponent:** \(a^{-b} = \frac{1}{a^b}\). This is used to change negative exponents to positive by placing it as a denominator.
Solving Algebraic Equations
Algebraic equations require finding the value of variables that make the equation true. In the context of exponential equations, solving involves reducing the equation to isolate the unknown variable. Consider the equation \( e^{3-x} = e^{-3x} \), where both sides have the same base:
- After expressing both sides with the same base, equate the exponents: \( 3 - x = -3x \).
- Solve the equation through typical algebraic manipulation. An important step includes collecting all terms involving \( x \) onto one side:
- Add \( 3x \) to both sides to make calculation easier, resulting in \( 3 + 2x = 0 \).
- Isolate \( x \) by performing subtraction and then division: subtract 3 to get \( 2x = -3 \), then divide by 2 to solve for \( x = -\frac{3}{2} \).
Other exercises in this chapter
Problem 46
Use a calculator to find a decimal approximation for each common or natural logarithm. $$\log 1247$$
View solution Problem 46
Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$1-4 \ln (2 x-1)=-5$$
View solution Problem 47
Evaluate each logarithm in three ways: (a) Use the definition of logarithm to find the exact value analytically. (b) Support the result of part (a) by using the
View solution Problem 47
Use a calculator to find a decimal approximation for each common or natural logarithm. $$\log 0.783$$
View solution