Problem 46
Question
Sketching graphs of functions Sketch the graph of a function with the given properties. You do not need to find a formula for the function. $$f(1)=0, f(2)=4, f(3)=6, \lim _{x \rightarrow 2^{-}} f(x)=-3, \lim _{x \rightarrow 2^{+}} f(x)=5$$
Step-by-Step Solution
Verified Answer
Answer: The function approaches -3 as a left-hand limit and 5 as a right-hand limit at x=2, showing a discontinuity (jump) at x=2.
1Step 1: Plot the given points
First, let's plot the points given for x=1, x=2, and x=3. We have the following coordinates (1, 0), (2, 4), and (3, 6). Plot these points.
2Step 2: Analyze the left-hand limit at x=2
The exercise asks for the left-hand limit (limit as x approaches 2 from the left) to be -3. This means that, as x approaches 2 from the left, the function should approach -3. So the graph of the function should go towards the y-coordinate of -3 as it moves close to x=2 from the left side.
3Step 3: Analyze the right-hand limit at x=2
Similarly, the exercise asks for the right-hand limit (limit as x approaches 2 from the right) to be 5. As x approaches 2 from the right, the function should approach 5. So the graph of the function should go towards the y-coordinate of 5 as it moves close to x=2 from the right side.
4Step 4: Sketch the graph around x = 2
Taking into consideration the given limits, sketch the graph around x=2 such that it approaches -3 on the left side of x=2 and it approaches 5 on the right side of x=2. The graph should have a discontinuity (jump) at x=2.
5Step 5: Connect the remaining points
Now, connect the plotted points smoothly while adhering to the behavior of the graph around x=2. You should draw a continuous graph between the points (1, 0) and (3, 6), but with a jump (discontinuity) at x=2.
You should now have a graph that satisfies the requirements given in the exercise.
Key Concepts
Left-Hand LimitRight-Hand LimitDiscontinuity
Left-Hand Limit
When we discuss the left-hand limit of a function, we're focusing on how the function behaves as the input value, denoted as \(x\), approaches a specific point from the left side. This is particularly useful when studying points of potential discontinuity or rapid change.
For the given example in the exercise, consider \( \lim _{x \rightarrow 2^{-}} f(x)=-3 \). This notation tells us that as \(x\) gets closer to 2 from values less than 2, the value of the function \(f(x)\) approaches -3.
For the given example in the exercise, consider \( \lim _{x \rightarrow 2^{-}} f(x)=-3 \). This notation tells us that as \(x\) gets closer to 2 from values less than 2, the value of the function \(f(x)\) approaches -3.
- "Approaching from the left" means selecting values such as 1.9, 1.99, 1.999, etc., which are incrementally closer to 2 but still less than 2.
- Here, the function's curve should dip down towards a y-value of -3 as it gets near \(x=2\) from the left.
Right-Hand Limit
The concept of the right-hand limit mirrors that of the left-hand limit, but here we focus on approaching a point from values greater than the point of interest. This helps us understand how the function behaves as \(x\) approaches a certain value from the right side.
For instance, with \( \lim _{x \rightarrow 2^{+}} f(x)=5 \), we're instructed that as \(x\) approaches 2 from numbers like 2.1, 2.01, 2.001, and so on, the function \(f(x)\) heads towards 5.
For instance, with \( \lim _{x \rightarrow 2^{+}} f(x)=5 \), we're instructed that as \(x\) approaches 2 from numbers like 2.1, 2.01, 2.001, and so on, the function \(f(x)\) heads towards 5.
- "Approaching from the right" involves selecting values greater than 2 but getting closer to 2, indicating the tendency or behavior of the graph's right approach.
- Therefore, on this side of the curve, the graph must shift towards a y-value of 5 as it nears \(x=2\).
Discontinuity
Discontinuity in a graph tells us about sudden jumps, breaks, or gaps in the function's behavior. It plays a critical role when graphing functions with distinct left and right-hand limits at a point.
In our exercise scenario, the term discontinuity arises around \(x=2\) where the left-hand limit yields a value of -3, and the right-hand limit gives 5.
In our exercise scenario, the term discontinuity arises around \(x=2\) where the left-hand limit yields a value of -3, and the right-hand limit gives 5.
- This results in a "jump" discontinuity, where between the left and right approaches, the function breaks instead of remaining smooth or connected.
- At \(x=2\), instead of transitioning smoothly from one part to another, the graph rapidly jumps from one y-value to another.
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