Problem 46
Question
Show that if \(\sum_{n=1}^{\infty} a_{n}\) is absolutely convergent, then \(\left|\sum_{n=1}^{\infty} a_{n}\right| \leq \Sigma_{n=1}^{\infty}\left|a_{n}\right|\)
Step-by-Step Solution
Verified Answer
Using the triangle inequality, we can show that the absolute value of the sum of a convergent series is bounded by the sum of the absolute values of its terms. For partial sums, we have \( \left|\sum_{n=1}^{N} a_n\right| \leq \sum_{n=1}^{N} |a_n|\). Taking the limit as \(N\) goes to infinity, we get \(\left|\sum_{n=1}^{\infty} a_n\right| \leq \sum_{n=1}^{\infty} |a_n|\).
1Step 1: Definition of absolute convergence
A series \(\sum_{n=1}^{\infty} a_n\) is absolutely convergent if the series \(\sum_{n=1}^{\infty} |a_n|\) is convergent. In other words, given that the series is absolutely convergent, we know that \(\sum_{n=1}^{\infty} |a_n| < \infty\).
2Step 2: Triangle Inequality
Recall the triangle inequality: for any real numbers \(x\) and \(y\), we have that \(|x + y| \leq |x| + |y|\). In the context of our series, the triangle inequality tells us that
$$
|a_n + a_{n+1}| \leq |a_n| + |a_{n+1}|.
$$
3Step 3: Apply Triangle Inequality to Partial Sums
We want to prove that \(\left|\sum_{n=1}^{\infty} a_n\right| \leq \sum_{n=1}^{\infty}\left|a_n\right|\). We will do this by showing that this is true for all partial sums up to a term \(N\). From the triangle inequality, we have that
$$
\left|\sum_{n=1}^{N} a_n\right| \leq \sum_{n=1}^{N} |a_n|.
$$
Since this is true for all partial sums up to \(N\), we can take the limit as \(N\) goes to infinity.
4Step 4: Take Limit of Inequality
Taking the limit on both sides of the inequality as \(N\) goes to infinity, we have that
$$
\lim_{N \to \infty} \left|\sum_{n=1}^{N} a_n\right| \leq \lim_{N \to \infty} \sum_{n=1}^{N} |a_n|.
$$
5Step 5: Replace Limit with Infinite Sums
Since the limit of partial sums is just the sum of the infinite series, we can rewrite the inequality as
$$
\left|\sum_{n=1}^{\infty} a_n\right| \leq \sum_{n=1}^{\infty} |a_n|,
$$
which is the result that we wanted to prove. In conclusion, if a series \(\sum_{n=1}^{\infty} a_n\) is absolutely convergent, its absolute value is less than or equal to the sum of its absolute values.
Key Concepts
triangle inequalitylimit of partial sumsinfinite series
triangle inequality
The triangle inequality is a fundamental concept in mathematics, particularly in analysis and geometry. It provides a way to compare the size of a sum to the size of its parts. Specifically, for any real numbers or vectors, the triangle inequality states: \(|x + y| \leq |x| + |y|\).
This inequality implies that the absolute value of a sum is always less than or equal to the sum of the absolute values. It's a useful tool when dealing with series and sequences.
This inequality implies that the absolute value of a sum is always less than or equal to the sum of the absolute values. It's a useful tool when dealing with series and sequences.
- For any two elements: It helps in understanding how the sum behaves in terms of magnitude.
- In series: Allows us to apply this concept to partial sums \(|a_n + a_{n+1}| \leq |a_n| + |a_{n+1}|\).
limit of partial sums
In the study of series, partial sums play a crucial role in understanding convergence. A partial sum is simply the sum of the first \(N\) terms of a series, expressed as \(S_N = \sum_{n=1}^{N} a_n\). As \(N\) increases, these partial sums approach a certain value, called the limit of the series.
This concept is critical when determining whether a series converges. A series \(\sum_{n=1}^{\infty} a_n\) converges if the sequence of its partial sums \(S_N\) converges to a limit \(L\).
This concept is critical when determining whether a series converges. A series \(\sum_{n=1}^{\infty} a_n\) converges if the sequence of its partial sums \(S_N\) converges to a limit \(L\).
- Helps in proving convergence: If \(\lim_{N \to \infty} S_N = L\), the series converges to \(L\).
- Tool in inequalities: Used to take the limit on both sides of an inequality involving series or sequences.
infinite series
An infinite series is the sum of the terms of an infinite sequence, expressed as \(\sum_{n=1}^{\infty} a_n\). These series are a key concept in calculus and analysis, helping to explain various functions and mathematical phenomena.
Convergence of an infinite series means that as you add more and more terms, the total approaches a specific value. There are several tests and techniques to determine whether a series converges.
Convergence of an infinite series means that as you add more and more terms, the total approaches a specific value. There are several tests and techniques to determine whether a series converges.
- Absolute convergence: If \(\sum_{n=1}^{\infty} |a_n|\) converges, the series \(\sum_{n=1}^{\infty} a_n\) is absolutely convergent, which generally ensures the series converges.
- Conditional convergence: Occurs if \(\sum_{n=1}^{\infty} a_n\) converges but \(\sum_{n=1}^{\infty} |a_n|\) does not.
Other exercises in this chapter
Problem 45
(a) graph the sequence \(\left\\{a_{n}\right\\}\) with a graphing utility, (b) use your graph to guess at the convergence or divergence of the sequence, and (c)
View solution Problem 46
Find a power series representation for the indefinite integral. \(\int e^{-\sqrt{x}} d x\)
View solution Problem 46
Determine whether the given series converges or diverges. If it converges, find its sum. \(\sum_{n=0}^{\infty}\left[\left(-\frac{3}{\pi}\right)^{n}+\left(\frac{
View solution Problem 46
(a) graph the sequence \(\left\\{a_{n}\right\\}\) with a graphing utility, (b) use your graph to guess at the convergence or divergence of the sequence, and (c)
View solution