Problem 46
Question
Plot the points \(P(-2,1)\) and \(Q(12,-1) .\) Which (if either) of the points \(A(5,-7)\) and \(B(6,7)\) lies on the perpendicular bisector of the segment \(P Q ?\)
Step-by-Step Solution
Verified Answer
Point B(6, 7) lies on the perpendicular bisector of segment PQ.
1Step 1: Calculate the Midpoint of Segment PQ
To find the midpoint of the segment connecting points \( P(-2, 1) \) and \( Q(12, -1) \), we use the midpoint formula: \[\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right).\]Substituting the coordinates of \( P \) and \( Q \), we get: \[\left( \frac{-2 + 12}{2}, \frac{1 + (-1)}{2} \right) = \left( \frac{10}{2}, \frac{0}{2} \right) = (5, 0).\]
2Step 2: Calculate the Slope of Segment PQ
The slope of the line segment between \( P(-2, 1) \) and \( Q(12, -1) \) is calculated as: \[m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 - 1}{12 - (-2)} = \frac{-2}{14} = -\frac{1}{7}.\]
3Step 3: Determine the Slope of the Perpendicular Bisector
The slope of the perpendicular bisector is the negative reciprocal of the slope of the line segment. Thus, the slope of the perpendicular bisector is \[7\].
4Step 4: Write the Equation of the Perpendicular Bisector
Using the midpoint \((5, 0)\) and the slope \(7\), we write the equation of the line using the point-slope form: \[y - y_1 = m(x - x_1),\]where \((x_1, y_1) = (5, 0)\) and \(m = 7\). So, \[y - 0 = 7(x - 5).\]Simplifying, we get:\[y = 7x - 35.\]
5Step 5: Check if Point A Lies on the Perpendicular Bisector
Substitute point \(A(5, -7)\) into the equation \(y = 7x - 35\) to check:\[-7 = 7(5) - 35.\]Simplifying the right side gives:\[35 - 35 = 0,\]which is not equal to \(-7\). Thus, \(A\) does not lie on the line.
6Step 6: Check if Point B Lies on the Perpendicular Bisector
Substitute point \(B(6, 7)\) into the equation \(y = 7x - 35\):\[7 = 7(6) - 35.\]Simplifying the right side gives:\[42 - 35 = 7,\]which matches the left side. Thus, point \(B\) does lie on the line.
Key Concepts
Midpoint FormulaSlope CalculationPoint-Slope FormCoordinate Geometry
Midpoint Formula
The midpoint formula is a crucial tool for finding the center point of a line segment in coordinate geometry. To compute the midpoint of a segment defined by endpoints \((x_1, y_1)\) and \((x_2, y_2)\), you use the formula:
- Midpoint = \( \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \).
- \( \left( \frac{-2 + 12}{2}, \frac{1 + (-1)}{2} \right) = (5, 0) \)
Slope Calculation
The slope of a line indicates its steepness and direction. Slope is often denoted as "\( m \)" and calculated using the formula:
- Slope \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
- \( m = \frac{-1 - 1}{12 - (-2)} = \frac{-2}{14} = -\frac{1}{7} \)
Point-Slope Form
Point-slope form is another way to represent the equation of a line, particularly useful when you know a point on the line and its slope. The formula is:
- \( y - y_1 = m(x - x_1) \)
- \( y - 0 = 7(x - 5) \)
- \( y = 7x - 35 \)
Coordinate Geometry
Coordinate geometry, or analytic geometry, allows us to use algebraic formulas to solve geometric problems on a coordinate plane. Key concepts include points, lines, and their relationships, assessed through calculations like the distance, midpoint, and slope. This discipline merges algebra's clear numerical properties with the visual understanding of geometry.
- Helps solve problems relating to shapes and measurements.
- Involves analyzing figures made up of points in the plane.
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