Problem 46
Question
NASA is giving serious consideration to the concept of \(solar\) \(sailing\). A solar sailcraft uses a large, low-mass sail and the energy and momentum of sunlight for propulsion. (a) Should the sail be absorbing or reflective? Why? (b) The total power output of the sun is 3.9 \(\times\) 10\(^{26}\) W. How large a sail is necessary to propel a 10,000-kg spacecraft against the gravitational force of the sun? Express your result in square kilometers. (c) Explain why your answer to part (b) is independent of the distance from the sun.
Step-by-Step Solution
Verified Answer
(a) The sail should be reflective for momentum effect. (b) Sail area: 50 km². (c) Force dependence cancels distance effect.
1Step 1: Reflective or Absorbing Sail
A solar sail should be reflective because it can effectively use the momentum of sunlight. When sunlight hits a reflective surface, it bounces off and imparts more momentum to the sail, compared to an absorbing surface where energy might be lost in heat.
2Step 2: Calculate Force from Solar Radiation
The force exerted by sunlight on a perfectly reflective surface is given by the formula: \[ F = 2\frac{P}{c} \]where \( P = 3.9 \times 10^{26} \text{ W} \) is the power output of the sun, and \( c = 3 \times 10^8 \text{ m/s} \) is the speed of light. Calculating this gives:\[ F = 2 \times \frac{3.9 \times 10^{26}}{3 \times 10^8} = 2.6 \times 10^{18} \text{ N/m}^2 \]
3Step 3: Calculate Required Sail Area
The gravitational force on the spacecraft due to the sun is given by:\[ F_g = \frac{G M m}{r^2} \]where \( G = 6.674 \times 10^{-11} \text{ Nm}^2/\text{kg}^2 \), \( M = 1.989 \times 10^{30} \text{ kg} \) (mass of sun), \( m = 10,000 \text{ kg} \) (mass of spacecraft). Since we need the light force equal to the gravitational force:\[ F = F_g = m g_s \]Then solving for the area \( A \) gives:\[ A = \frac{m g_s c}{2P} = \frac{10,000 \times 9.8 \times 3 \times 10^8}{7.8 \times 10^17} = 5 \times 10^7 \text{ m}^2 \] or \( 50 \text{ km}^2 \).
4Step 4: Independence from Distance
The answer is independent of distance from the sun because the power per unit area received from the sun, when multiplied by the area and distance from sun, cancels out the effect of distance in the calculation of physics of light pressure. The inverse square law of gravitation and radiation pressure balances, making the required sail area independent of distance.
Key Concepts
Solar Radiation PressureGravitational ForceReflective SurfacesMomentum Transfer
Solar Radiation Pressure
The concept of solar radiation pressure is linked to the force exerted by sunlight on objects it encounters. Sunlight is not just light; it carries energy and momentum, which can exert pressure on surfaces it hits. This pressure is used in solar sailing as propulsion for spacecraft.
When sunlight hits a surface, the radiation pressure can be calculated using the formula: \[ F = \frac{P}{c} \]where:
When sunlight hits a surface, the radiation pressure can be calculated using the formula: \[ F = \frac{P}{c} \]where:
- \( P \) is the power with which sunlight hits the surface (in watts), and
- \( c \) is the speed of light (approximately \( 3 \times 10^8 \) meters per second).
Gravitational Force
In solar sailing, it's crucial to understand the gravitational force that acts on the spacecraft. This force is due to the sun's massive gravitational pull. It's calculated using Newton's law of universal gravitation: \[ F_g = \frac{G M m}{r^2} \]where:
- \( G \) is the gravitational constant \( (6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2) \),
- \( M \) is the mass of the sun \((1.989 \times 10^{30} \text{ kg})\),
- \( m \) is the mass of the spacecraft, and
- \( r \) is the distance between the center of the sun and the spacecraft.
Reflective Surfaces
Reflective surfaces are key to solar sailing. A reflective sail is designed to bounce sunlight off its surface, increasing the momentum transfer compared to absorbing surfaces.
An absorbing surface would primarily turn the light energy into heat, which is not useful for propulsion. Whereas, a reflective surface sends the photons away, which means:
An absorbing surface would primarily turn the light energy into heat, which is not useful for propulsion. Whereas, a reflective surface sends the photons away, which means:
- The momentum imparted by the reflected photons to the sail is doubled, enhancing the thrust.
- This maximizes the efficiency of the sail, making solar sailing a feasible propulsion method.
Momentum Transfer
Momentum transfer is a critical concept in understanding how solar sails work. When light hits a surface, it carries momentum even though it doesn't have mass. This momentum can be transferred to the object it strikes.
- For a reflective surface, the process is more efficient because the light photons rebound, essentially "pushing" the sail twice with the same energy.
- This continuous exchange of momentum from photons to the sail generates a constant force that propels the spacecraft forward.
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