Problem 46
Question
Indicate whether each situation involves a combination or a permutation. 5 runners crossing the finish line
Step-by-Step Solution
Verified Answer
The situation involves a permutation since the order of runners finishing is important.
1Step 1: Understand the Difference Between Combinations and Permutations
Combinations are selections where the order does not matter. Permutations are arrangements where the order does matter. In permutations, the same set of items can be arranged in different orders, and in combinations, only the choice of items is important, not the arrangement.
2Step 2: Analyze the Given Situation
The given situation is about 5 runners crossing the finish line. Crossing the finish line is inherently an ordered process because each runner finishes in a specific order.
3Step 3: Determine If the Situation Involves a Permutation or Combination
Since the order in which the runners finish matters (i.e., who finishes first, second, third, etc.), this situation involves a permutation.
Key Concepts
Mathematics PermutationsCombinations vs PermutationsProbability and Counting
Mathematics Permutations
When tackling problems in mathematics, understanding the concept of permutations is key. In essence, permutations deal with the different ways in which a set of items can be arranged in a sequence where the order is significant. Think of it as a puzzle where every piece must fit into a specific position.
For instance, if we take a simple scenario with three different colored balls: red, blue, and green, the permutations we could create would look like this—RGB, RBG, BGR, BRG, GBR, and GRB. It's like creating every possible combination of leads in a play; the actor playing the king must always come before the queen and the jester, and each different order counts as a distinct permutation.
To calculate the number of permutations for a set of items, we use the formula:
\( P(n, k) = \frac{n!}{(n-k)!} \)
where \(n\) is the total number of items, \(k\) is the number of items to choose from, and \(n!\) (n factorial) represents the product of all positive integers up to \(n\). It’s important to dive deep into permutations, as they are the backbone for understanding more complex problems in probability and statistics.
For instance, if we take a simple scenario with three different colored balls: red, blue, and green, the permutations we could create would look like this—RGB, RBG, BGR, BRG, GBR, and GRB. It's like creating every possible combination of leads in a play; the actor playing the king must always come before the queen and the jester, and each different order counts as a distinct permutation.
To calculate the number of permutations for a set of items, we use the formula:
\( P(n, k) = \frac{n!}{(n-k)!} \)
where \(n\) is the total number of items, \(k\) is the number of items to choose from, and \(n!\) (n factorial) represents the product of all positive integers up to \(n\). It’s important to dive deep into permutations, as they are the backbone for understanding more complex problems in probability and statistics.
Combinations vs Permutations
Distinguishing between combinations and permutations is akin to knowing the difference between a shopping list and a to-do list. A shopping list (combinations) doesn't care about the order of items, as long as you buy everything on it, while a to-do list (permutations) requires tasks to be completed in a specific order.
In mathematics, combinations refer to the selection of items where the order does not matter. Unlike permutations, here we are not concerned with the arrangement of the items. For example, if you're choosing two appetizers from a menu of five, it doesn't matter whether you choose the soup first or the salad; the combination is the same.
The formula for calculating combinations is given by:
\( C(n, k) = \frac{n!}{k!(n-k)!} \)
where \(n\) is the total number of items and \(k\) is the number of items to select. Notice how this formula divides out the extra permutations to only count each unique set of items once, regardless of order.
In mathematics, combinations refer to the selection of items where the order does not matter. Unlike permutations, here we are not concerned with the arrangement of the items. For example, if you're choosing two appetizers from a menu of five, it doesn't matter whether you choose the soup first or the salad; the combination is the same.
The formula for calculating combinations is given by:
\( C(n, k) = \frac{n!}{k!(n-k)!} \)
where \(n\) is the total number of items and \(k\) is the number of items to select. Notice how this formula divides out the extra permutations to only count each unique set of items once, regardless of order.
Probability and Counting
Probability and counting are tightly knit concepts in mathematics. Probability measures the likelihood of a specific outcome when there's various possible outcomes, and counting plays a foundational role in determining these probabilities.
Counting principles, such as the Fundamental Counting Principle, express that if there are \(a\) ways to do something and \(b\) ways to do another thing, then there are \(a \times b\) ways to do both. Permutations and combinations are advanced counting techniques that give us sophisticated ways to count possibilities without having to list them all out.
In a probability problem, for example, if you're dealt two cards from a standard deck, permutations and combinations help you count the potential pairs, which is essential before you can calculate the probability of drawing, say, two aces. Hence, mastering the art of counting is a stepping stone to harnessing the power of probability.
Counting principles, such as the Fundamental Counting Principle, express that if there are \(a\) ways to do something and \(b\) ways to do another thing, then there are \(a \times b\) ways to do both. Permutations and combinations are advanced counting techniques that give us sophisticated ways to count possibilities without having to list them all out.
In a probability problem, for example, if you're dealt two cards from a standard deck, permutations and combinations help you count the potential pairs, which is essential before you can calculate the probability of drawing, say, two aces. Hence, mastering the art of counting is a stepping stone to harnessing the power of probability.
Other exercises in this chapter
Problem 45
Simplify. Classify each result by number of terms. $$ \left(3 a^{2}-a b-7\right)+\left(5 a^{2}+a b+8\right)-\left(-2 a^{2}+3 a b-9\right) $$
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The term 126\(c^{4} d^{5}\) appears in the expansion of \((c+d)^{n} .\) Find \(n\)
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According to the Rational Root Theorem, what is the relationship between the polynomial equation \(2 x^{4}-x^{3}-7 x^{2}+3 x+3=0\) and rational roots of the for
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Write each function in factored form. Check by multiplication. $$ y=\frac{1}{2} x^{3}-\frac{1}{8} x $$
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