Problem 46
Question
In the theory of relativity, the energy of a particle is $$E=\sqrt{m_{0}^{2} c^{4}+h^{2} c^{2} / \lambda^{2}}$$ where \(m_{0}\) is the rest mass of the particle, \(\lambda\) is its wave length, and \(h\) is Planck's constant. Sketch the graph of \(E\) as a function of \(\lambda .\) What does the graph say about the energy?
Step-by-Step Solution
Verified Answer
The graph shows energy asymptotically approaches rest mass energy at large \( \lambda \) and increases sharply at small \( \lambda \).
1Step 1: Understand the relation
The given formula is \( E = \sqrt{m_0^2 c^4 + \frac{h^2 c^2}{\lambda^2}} \). This is a function of wavelength \( \lambda \), which depicts how energy \( E \) changes with respect to changes in wavelength \( \lambda \).
2Step 2: Identify Asymptotic Behavior
As \( \lambda \rightarrow \infty \), the term \( \frac{h^2 c^2}{\lambda^2} \rightarrow 0 \). Thus, \( E \rightarrow \sqrt{m_0^2 c^4} = m_0 c^2 \), indicating energy approaches a constant value equal to the rest mass energy.
3Step 3: Analyze for Small \(\lambda\)
As \( \lambda \rightarrow 0 \), the term \( \frac{h^2 c^2}{\lambda^2} \) grows large. Therefore, \( E \rightarrow \frac{hc}{\lambda} \), showing that energy increases sharply as wavelength decreases.
4Step 4: Sketch the Graph
Start the curve from the asymptotic limit at \( m_0 c^2 \) for large \( \lambda \) and let the curve sharply increase as \( \lambda \) decreases. This shows a steep upward trend as energy increases without bound as \( \lambda \to 0 \).
5Step 5: Interpret the Graph
The graph indicates that for very large wavelengths, energy approaches a constant equal to the rest mass energy, \( m_0 c^2 \). However, as the wavelength decreases, energy significantly increases, indicating a high-energy regime as wavelength approaches zero.
Key Concepts
WavelengthEnergy as a function of wavelengthAsymptotic behavior of energy
Wavelength
Wavelength is a fundamental concept in the study of wave phenomena, including light and other types of radiation. It is defined as the distance between consecutive peaks of a wave. Represented by the symbol \( \lambda \), it is crucial in understanding different properties of waves, such as energy and frequency.
Here are few key things to remember about wavelength:
Here are few key things to remember about wavelength:
- It determines the type of wave. For instance, longer wavelengths can correspond to radio waves, while shorter ones relate to gamma rays.
- Inversely related to frequency, which means shorter wavelengths have higher frequencies and vice versa.
- Plays an important role in energy, as described by the equation \( E = \sqrt{m_{0}^{2} c^{4}+\frac{h^{2} c^{2}}{\lambda^{2}}} \), linking it directly to energy.
Energy as a function of wavelength
Energy, in the context of relativity, can be intricately affected by the wavelength of a particle. The given equation \( E = \sqrt{m_{0}^{2} c^{4}+\frac{h^{2} c^{2}}{\lambda^{2}}} \) provides an insight into how energy \( E \) changes concerning the wavelength \( \lambda \).
Let's break it down:
Let's break it down:
- The squaring operation under the square root ensures that energy is always a positive value, reflecting physical realities.
- As wavelength \( \lambda \) changes, it affects the second term \( \frac{h^{2} c^{2}}{\lambda^{2}} \) in the equation, which directly affects the value of energy \( E \).
- This equation shows that energy has a complex, inverse-square relationship with wavelength. As the denominator (wavelength squared) decreases, the overall energy contribution from this term increases.
- This relationship is essential in understanding phenomena in both macroscopic and quantum scales, indicating how energy propagates in waves.
Asymptotic behavior of energy
Asymptotic behavior refers to how functions behave as they approach certain limits, either approaching infinity or zero. In the given equation for energy, the asymptotic behavior is crucial in explaining the limits of energy as a function of wavelength \( \lambda \).
When considering large values of \( \lambda \) (wavelength approaching infinity):
When considering large values of \( \lambda \) (wavelength approaching infinity):
- The term \( \frac{h^{2} c^{2}}{\lambda^{2}} \) trends towards zero, simplifying the energy equation to \( E \approx m_{0}c^{2} \), which is the rest energy of a particle. This indicates that at large wavelengths, energy becomes primarily defined by its rest mass.
- The term \( \frac{h^{2} c^{2}}{\lambda^{2}} \) grows without bound, indicating that energy \( E \) increases significantly. This suggests an intense rise in energy, corresponding to scenarios such as particles moving close to light speed or demonstrating high-frequency characteristics.
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