Problem 46
Question
In the following pairs of binary compounds, determine which one is a molecular substance and which one is an ionic substance. Use the appropriate naming convention (for ionic or molecular substances) to assign a name to each compound: (a) \(\mathrm{TiCl}_{4}\) and \(\mathrm{CaF}_{2},(\mathbf{b}) \mathrm{ClF}_{3}\) and \(\mathrm{VF}_{3},(\mathbf{c}) \mathrm{SbCl}_{5}\) and \(\mathrm{AlF}_{3} .\)
Step-by-Step Solution
Verified Answer
(a) TiCl₄ is an ionic substance named titanium tetrachloride, and CaF₂ is an ionic substance named calcium fluoride. (b) ClF₃ is a molecular substance named chlorine trifluoride, and VF₃ is an ionic substance named vanadium trifluoride. (c) SbCl₅ is a molecular substance named antimony pentachloride, and AlF₃ is an ionic substance named aluminum fluoride.
1Step 1: (a) Identify the type of substance for TiCl4 and CaF2
In TiCl₄, we have titanium (Ti), which is a metal, and chlorine (Cl), a non-metal. This indicates that TiCl₄ is an ionic substance. In CaF₂, we have calcium (Ca), a metal, and fluorine (F), a non-metal, making it an ionic substance as well.
2Step 2: (a) Name TiCl4 and CaF2
For ionic substances, we use the metal name followed by the non-metal name with its ending changed to "-ide."
TiCl₄: Titanium tetrachloride
CaF₂: Calcium fluoride
3Step 3: (b) Identify the type of substance for ClF3 and VF3
In ClF₃, we have chlorine (Cl) and fluorine (F), both non-metals, making it a molecular substance. In VF₃, we have vanadium (V), a metal, and fluorine (F), a non-metal, making it an ionic substance.
4Step 4: (b) Name ClF3 and VF3
For molecular substances, we use prefixes to indicate the number of atoms of each element. For ionic substances, we use the metal name followed by the non-metal name with its ending changed to "-ide."
ClF₃: Chlorine trifluoride
VF₃: Vanadium trifluoride
5Step 5: (c) Identify the type of substance for SbCl5 and AlF3
In SbCl₅, we have antimony (Sb), a metalloid, and chlorine (Cl), a non-metal. Considering metalloids have properties of both metals and non-metals but mostly behave as non-metals in compounds, SbCl₅ would be a molecular substance. In AlF₃, we have aluminum (Al), a metal, and fluorine (F), a non-metal, making it an ionic substance.
6Step 6: (c) Name SbCl5 and AlF3
For molecular substances, we use prefixes to indicate the number of atoms of each element. For ionic substances, we use the metal name followed by the non-metal name with its ending changed to "-ide."
SbCl₅: Antimony pentachloride
AlF₃: Aluminum fluoride
Key Concepts
Molecular CompoundsIonic CompoundsNaming Chemical Compounds
Molecular Compounds
Molecular compounds are made up of non-metals that bond together by sharing electrons. This sharing of electrons is known as covalent bonding. The molecules that form from these bonds are distinct entities with specific arrangements of atoms.
An interesting aspect of molecular compounds is their naming convention, which involves using prefixes to indicate the number of atoms of each element present in the compound.
An interesting aspect of molecular compounds is their naming convention, which involves using prefixes to indicate the number of atoms of each element present in the compound.
- "Mono-" for one (often omitted for the first element)
- "Di-" for two
- "Tri-" for three
- "Tetra-" for four, and so on
Ionic Compounds
Ionic compounds are formed through the transfer of electrons from one atom to another, usually between a metal and a non-metal. This transfer creates ions: cations (positively charged ions) and anions (negatively charged ions). The attraction between these oppositely charged ions results in an ionic bond.
In ionic compounds, these ions form a repeating three-dimensional lattice structure rather than individual molecules. The naming of ionic compounds follows a straightforward pattern:
In ionic compounds, these ions form a repeating three-dimensional lattice structure rather than individual molecules. The naming of ionic compounds follows a straightforward pattern:
- The metal name is stated first.
- The non-metal is mentioned second with its ending changed to "-ide."
Naming Chemical Compounds
The naming of chemical compounds is a systematic process to ensure clear and consistent communication in chemistry. It varies depending on whether the compound is ionic or molecular. For ionic compounds, the name begins with the cation (metal) followed by the anion (non-metal), with the anion's suffix changing to "-ide." This pattern works well for simple ionic compounds, like aluminum fluoride (\( \text{AlF}_3 \)).
Naming molecular compounds, however, involves prefixes that denote the number of each type of atom. This method highlights the distinct nature of covalent bonding, where specific atom counts within molecules are important. For instance, antimony pentachloride (\( \text{SbCl}_5 \)) reflects the five chlorine atoms bonded to one antimony atom.
To accurately communicate chemical compositions, mastering these naming conventions is essential for students and professionals alike. It ensures the understanding of what elements are present and in what proportion, which is vital for studying chemical reactions and properties.
Naming molecular compounds, however, involves prefixes that denote the number of each type of atom. This method highlights the distinct nature of covalent bonding, where specific atom counts within molecules are important. For instance, antimony pentachloride (\( \text{SbCl}_5 \)) reflects the five chlorine atoms bonded to one antimony atom.
To accurately communicate chemical compositions, mastering these naming conventions is essential for students and professionals alike. It ensures the understanding of what elements are present and in what proportion, which is vital for studying chemical reactions and properties.
Other exercises in this chapter
Problem 42
Arrange the bonds in each of the following sets in order of increasing polarity: (a) \(\mathrm{C}-\mathrm{F}, \mathrm{O}-\mathrm{F}, \mathrm{Be}-\mathrm{F}\) ;
View solution Problem 45
In the following pairs of binary compounds, determine which one is a molecular substance and which one is an ionic substance. Use the appropriate naming convent
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Draw Lewis structures for the following: (a) \(\operatorname{SiH}_{4},\) (b) \(\mathrm{CO}\) \((\mathbf{c}) \mathrm{SF}_{2},(\mathbf{d}) \mathrm{H}_{2} \mathrm{
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Write Lewis structures for the following: (a) \(\mathrm{H}_{2} \mathrm{CO}\) (both \(\mathrm{H}\) atoms are bonded to \(\mathrm{C} ),(\mathbf{b}) \mathrm{H}_{2}
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