Problem 46
Question
In the expansion of \((a+b)^{n}\) , the coefficient of \(a^{n-k} b^{k}\) is the same as the coefficient of which other term?
Step-by-Step Solution
Verified Answer
The coefficient of \(a^{n-k} b^{k}\) is the same as \(a^k b^{n-k}\).
1Step 1: Recognize the Binomial Coefficient
In the expansion of \((a+b)^n\), each term is in the form \(C(n, k) \cdot a^{n-k}b^k\), where \(C(n, k)\) is the binomial coefficient \(\binom{n}{k}\).
2Step 2: Find the Symmetric Term
The binomial coefficients have a property where \(\binom{n}{k} = \binom{n}{n-k}\). This means the coefficient of \(a^{n-k} b^{k}\) is the same as the coefficient of \(a^k b^{n-k}\).
3Step 3: Identify the Term
Thus, in the expansion of \((a+b)^n\), the term \(a^{n-k} b^k\) has the same coefficient as the term \(a^k b^{n-k}\).
Key Concepts
Binomial CoefficientPolynomial ExpansionSymmetry in Binomial Coefficients
Binomial Coefficient
When working with the expansion of expressions like \((a+b)^n\), the binomial coefficient plays a crucial role. It is denoted as \(C(n, k)\) or \(\binom{n}{k}\) and represents the number of ways to choose \(k\) elements from a set of \(n\) elements. This is calculated using the formula:\[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]where \(n!\) denotes the factorial of \(n\). In the binomial expansion, each term is accompanied by a binomial coefficient, which determines its weight or size within the polynomial. It helps in systematically organizing terms so that you get the correct expansion without missing or adding any extra terms.
Polynomial Expansion
The polynomial expansion resulting from the binomial theorem is a structured way to write powers of a binomial expression \((a+b)^n\). In this expansion:
- Each term is a combination of two variables, \(a\) and \(b\), raised to different powers that together sum up to \(n\).
- The general term in the expansion is expressed as \(C(n, k) \cdot a^{n-k} b^k\).
Symmetry in Binomial Coefficients
One fascinating property of binomial coefficients is their symmetry. In mathematical terms, this symmetry is represented by the equation:\[ \binom{n}{k} = \binom{n}{n-k} \]This means that in the expansion of \((a+b)^n\), the term \(a^{n-k} b^k\) has the same coefficient as the term \(a^k b^{n-k}\). This symmetric property is useful for simplifying problems and predicting terms without having to explicitly calculate each one.
By recognizing symmetry, you can often find corresponding terms or identify the structure of an expression intuitively. This reflects an underlying balance in combinatorial mathematics, where the choices for \(k\) elements can be naturally mirrored by selecting their complements in a set of \(n\). The symmetry not only helps in verification but also in finding patterns in mathematical problems.
By recognizing symmetry, you can often find corresponding terms or identify the structure of an expression intuitively. This reflects an underlying balance in combinatorial mathematics, where the choices for \(k\) elements can be naturally mirrored by selecting their complements in a set of \(n\). The symmetry not only helps in verification but also in finding patterns in mathematical problems.
Other exercises in this chapter
Problem 46
For the following exercises, write an explicit formula for each arithmetic sequence. $$ a=\\{-17,-217,-417, \ldots\\} $$
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For the following exercises, write the first four terms of the sequence. $$ a_{n}=\frac{100 \cdot n}{n(n-1) !} $$
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For the following exercises, use this scenario: a bag of M\&Ms contains 12 blue, 6 brown, 10 orange, 8 yellow, 8 red, and 4 green M\&Ms. Reaching into the bag,
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Determine the value of the annuity for the indicated monthly deposit amount, the number of deposits, and the interest rate. Deposit amount: \(\$ 150 ;\) total d
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