Problem 46
Question
In Exercises 45-48, use vectors to find the interior angles of the triangle with the given vertices. \((-3, -4)\), \((1, 7)\), \((8, 2)\)
Step-by-Step Solution
Verified Answer
The interior angles of the triangle having vertices (-3, -4), (1, 7) and (8, 2) can be calculated using the above steps. Once the angles are computed, verify that they add up to 180 degrees to validate the solution.
1Step 1: Define the Vectors
The first step is to understand the triangle's vertices given and define the corresponding vector for each side. Here we have vertices at (-3, -4), (1, 7), (8, 2). Hence the vectors for AB, BC and CA can be defined as \(\vec{AB} = (1 - (-3), 7 - (-4))\), \(\vec{BC} = (8 - 1, 2 - 7)\) and \(\vec{CA} = (-3 - 8, -4 - 2)\) respectively.
2Step 2: Compute Dot Products
Compute the Dot product of the vectors which will be used in the next step to calculate the respective angles. The dot product of two vectors \(\vec{A}\) and \(\vec{B}\) can be found using the formula, \(\vec{A} \cdot \vec{B} = ||A|| ||B|| cos(Θ)\) where \(||A||\) and \(||B||\) are the magnitudes of \(\vec{A}\) and \(\vec{B}\) respectively. Therefore, the dot products of the vectors \(AB . BC\), \(BC . CA\) and \(CA . AB\) will be required next.
3Step 3: Calculate the Angles
The cosine of the angle between two vectors can be calculated using the formula \(\cos(Θ) = \frac{\vec{A} . \vec{B}}{||A|| ||B||}\). Hence, if \(Θ_{A}\), \(Θ_{B}\) and \(Θ_{C}\) are the angles at vertices A, B and C respectively, they can be calculated by rearranging the above formula to obtain the angles from the respective cosines.
4Step 4: Convert to Degrees
Since the above formula gives the result in radians, multiply it by \( \frac{180}{\pi} \) to convert the angles to degrees.
Key Concepts
Dot ProductInterior AnglesTriangle VerticesMagnitude of Vectors
Dot Product
The dot product is a crucial operation in vector mathematics. It helps in finding the angle between two vectors, which is essential for solving problems involving vector geometry. The dot product of two vectors \( \vec{A} = (a_1, a_2) \) and \( \vec{B} = (b_1, b_2) \) is calculated as:
- \( \vec{A} \cdot \vec{B} = a_1 \times b_1 + a_2 \times b_2 \)
Interior Angles
Interior angles of a triangle that are formed by the triangle's vertices can be determined using vectors. Each angle depends on the dot product between the two vectors that form the sides of the angle. To find an angle \( \Theta \) at vertex B for instance, you:
- Calculate the vectors for the sides joining at B, such as \( \vec{AB} \) and \( \vec{BC} \).
- Use the relationship \( \cos(\Theta) = \frac{\vec{AB} \cdot \vec{BC}}{||\vec{AB}|| ||\vec{BC}||} \).
Triangle Vertices
The vertices of a triangle are the points where two sides meet. In coordinate geometry, these vertices are represented with coordinates, for example, \( (-3, -4) \), \( (1, 7) \), and \( (8, 2) \). Defining each side of the triangle as a vector helps to analyze and solve various geometric problems.
- Vector \( \vec{AB} \) is derived from points A and B: \( (1 - (-3), 7 - (-4)) = (4, 11) \).
- Vector \( \vec{BC} \) from B to C is \( (8 - 1, 2 - 7) = (7, -5) \).
- Vector \( \vec{CA} \) from C to A is \( (-3 - 8, -4 - 2) = (-11, -6) \).
Magnitude of Vectors
The magnitude of a vector is a measure of its length. It is found using the formula derived from the Pythagorean Theorem. For a vector \( \vec{A} = (x, y) \), its magnitude \( ||\vec{A}|| \) is:
- \( ||\vec{A}|| = \sqrt{x^2 + y^2} \)
Other exercises in this chapter
Problem 45
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