Problem 46
Question
For the following exercises, graph the polynomial functions. Note \(x\) - and \(y\) - intercepts, multiplicity, and end behavior. $$ m(x)=-2 x(x-1)(x+3) $$
Step-by-Step Solution
Verified Answer
The intercepts are \(x = 0, 1, -3\); \(y\)-intercept is 0. The graph falls to the right and rises to the left.
1Step 1: Identify the Degree of the Polynomial
The polynomial is given by \(m(x) = -2x(x-1)(x+3)\). Multiply out the terms \[ m(x) = -2(x)(x-1)(x+3) = -2(x^3 + 2x^2 - 3x) \] The degree of the polynomial is 3, as it is the highest exponent of \(x\).
2Step 2: Identify End Behavior
For a polynomial of degree 3 with a negative leading coefficient (\(-2\)), the end behavior is as follows:- As \(x \to \infty\), \(m(x) \to -\infty\).- As \(x \to -\infty\), \(m(x) \to \infty\).This is because, for an odd degree polynomial with a negative leading coefficient, the function falls to the right and rises to the left.
3Step 3: Find x-intercepts and Their Multiplicities
To find the \(x\)-intercepts, set \(m(x) = 0\): \[-2x(x-1)(x+3) = 0\] Therefore, the \(x\)-intercepts are at \(x = 0, 1, -3\). Each factor appears once, so each intercept has a multiplicity of 1.
4Step 4: Find y-intercept
The \(y\)-intercept occurs where \(x = 0\). Substitute \(x = 0\) into the function to find the \(y\)-intercept:\[ m(0) = -2(0)(0 - 1)(0 + 3) = 0 \] So, the \(y\)-intercept is at \((0, 0)\).
5Step 5: Graph the Function
Plot the \(x\)-intercepts \((0,0), (1,0), (-3,0)\) on a coordinate plane. Note the \(y\)-intercept is also \((0,0)\). Sketch the curve considering the end behavior. The graph starts from the second quadrant, hits the \(x\)-intercept at \((-3,0)\), rises to a local max, crosses the \(x\)-axis at \((1,0)\), and falls as \(x\) increases beyond this point. Label all intercepts and indicate end behavior on the graph.
Key Concepts
Polynomial DegreeEnd BehaviorX-interceptsMultiplicity
Polynomial Degree
The degree of a polynomial is the highest power of the variable, typically represented by the symbol\( x \), which dictates the shape of the polynomial graph. For the given polynomial \( m(x) = -2x(x-1)(x+3) \), the degree is calculated by multiplying the degrees of each factor:
- The factor \( x \) is of degree 1.
- The factor \( (x-1) \) is also of degree 1.
- The factor \( (x+3) \) carries a degree of 1 too.
End Behavior
The end behavior of a polynomial function describes how the function behaves as \( x \) approaches positive or negative infinity. It’s significantly influenced by the degree and the leading coefficient of the polynomial. For the polynomial \( m(x) = -2x(x-1)(x+3) \), having a degree of 3, it's an odd-degree polynomial.Due to its negative leading coefficient (-2), the end behavior can be characterized as follows:
- As \( x \to \infty \), the function \( m(x) \to -\infty \). This means the graph descends on the right side.
- As \( x \to -\infty \), the function \( m(x) \to \infty \). Consequently, the graph ascends on the left side.
X-intercepts
X-intercepts are points where the graph of the polynomial crosses the x-axis, which occur when the output of the function is zero. For the polynomial \( m(x) = -2x(x-1)(x+3) \), the x-intercepts can be found by setting the equation to zero:\[-2x(x-1)(x+3) = 0\]Solving for \( x \) gives:
- \( x = 0 \)
- \( x = 1 \)
- \( x = -3 \)
Multiplicity
Multiplicity of a root refers to how many times a particular factor occurs in the polynomial. It directly influences the graph's behavior at the intercept corresponding to that root. For \( m(x) = -2x(x-1)(x+3) \):
- Each factor \( x \), \( x-1 \), and \( x+3 \) appears only once.
- Thus, each x-intercept \( x = 0, 1, -3 \) has a multiplicity of 1.
- An odd multiplicity (like 1) means the graph crosses the x-axis at this point.
- An even multiplicity implies the graph touches and rebounds back from the x-axis at this point without crossing it.
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