Problem 46
Question
For Exercises \(45-50,\) write out the first three terms and the last term. Then use the formula for the sum of the first n terms of an arithmetic sequence to find the indicated sum. $$\sum_{i=1}^{20}(6 i-4)$$
Step-by-Step Solution
Verified Answer
The sum of the first 20 terms of the sequence is 1180.
1Step 1: Find the first three terms
Substitute 1, 2, and 3 into the expression for i to find the first three terms of the sequence: \(T_1 = 6*1 - 4 = 2, T_2 = 6*2 - 4 = 8, T_3 = 6*3 - 4 = 14\).
2Step 2: Find the last term
The formula for the arithmetic sequence is \(6i - 4\). Given that there are 20 terms, substitute 20 for i to find the last term: \(T_{20} = 6*20 - 4 =116\).
3Step 3: Use the formula for sum of an arithmetic sequence
Plugging the obtained values into the formula for the sum of an arithmetic sequence, \(S = \frac{n}{2} * (a + l)\), and simplifying, we get \(S = \frac{20}{2} * (2 + 116) = 10 * 118 = 1180\).
Key Concepts
Sum of Arithmetic SequenceFirst Three TermsLast TermFormula for Arithmetic Sequence Sum
Sum of Arithmetic Sequence
An arithmetic sequence is a sequence of numbers in which the difference between any two successive members is a constant. This difference is known as the common difference. When you're asked to find the sum of an arithmetic sequence, you're essentially summing up all the terms in this sequence from the first term to the last.
For example, if you have 20 terms in your sequence, you need to add the first term, the second term, all the way through to the 20th term. Calculating each one individually would be tedious, but thankfully, there's a very convenient formula. This formula makes it much simpler to find the total sum without having to add up each number manually.
For example, if you have 20 terms in your sequence, you need to add the first term, the second term, all the way through to the 20th term. Calculating each one individually would be tedious, but thankfully, there's a very convenient formula. This formula makes it much simpler to find the total sum without having to add up each number manually.
First Three Terms
To find the first three terms of an arithmetic sequence, you use the general expression for the sequence. This exercise provides the expression as \(6i-4\). By substituting different values for \(i\), typically starting from \(i = 1\), you can find the first few terms.
- For \(i = 1\), the first term \(T_1 = 6 \times 1 - 4 = 2\).
- For \(i = 2\), the second term \(T_2 = 6 \times 2 - 4 = 8\).
- For \(i = 3\), the third term \(T_3 = 6 \times 3 - 4 = 14\).
Last Term
The last term in an arithmetic sequence can be found using the same expression by substituting the last sequential position number. If you're looking at the 20th term, plug in \(i = 20\) into the formula \(6i-4\).
Doing this calculation, you get \(T_{20} = 6 \times 20 - 4 = 116\). The last term is vital because it's used in the formula to find the sum of the entire sequence. Identifying the last term helps in efficiently applying the sum formula.
Doing this calculation, you get \(T_{20} = 6 \times 20 - 4 = 116\). The last term is vital because it's used in the formula to find the sum of the entire sequence. Identifying the last term helps in efficiently applying the sum formula.
Formula for Arithmetic Sequence Sum
The formula to find the sum \(S\) of an arithmetic sequence is \(S = \frac{n}{2}(a + l)\), where:
\[ S = \frac{20}{2}(2 + 116) = 10 \times 118 = 1180 \]
This formula significantly simplifies the process of finding the total sum of terms in an arithmetic sequence, saving both time and effort compared to manual addition.
- \(n\) is the number of terms in the sequence.
- \(a\) is the first term.
- \(l\) is the last term.
\[ S = \frac{20}{2}(2 + 116) = 10 \times 118 = 1180 \]
This formula significantly simplifies the process of finding the total sum of terms in an arithmetic sequence, saving both time and effort compared to manual addition.
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