Problem 46
Question
Find the product.\(\left(3 x^{2}-4 y^{2}\right)\left(3 x^{2}+4 y^{2}\right)\)
Step-by-Step Solution
Verified Answer
The product of \((3 x^{2}-4 y^{2})\) and \((3 x^{2}+4 y^{2})\) is \(9x^4 - 16y^4\).
1Step 1: Understand the basic concept
The difference of squares method states that \(a^2 - b^2 = (a+b)(a-b)\). In this case, \(a = 3x^2\) and \(b = 4y^2\). The given binomials \((3x^2 - 4y^2)\) and \((3x^2 + 4y^2)\) are in the form of \((a - b)\) and \((a + b)\) respectively.
2Step 2: Apply the formula
Now, substitute \(a\) and \(b\) in the formula \(a^2 - b^2 = (a+b)(a-b)\). Here, \(a+b = (3x^2 + 4y^2)\) and \(a-b = (3x^2 - 4y^2)\). Hence, the product is \(a^2 - b^2 = (3x^2)^2 - (4y^2)^2\).
3Step 3: Calculate the product
Calculate the square of \(3x^2\) and \(4y^2\) to get \(9x^4\) and \(16y^4\) respectively. So, \(a^2 - b^2 = 9x^4 - 16y^4\).
Key Concepts
Understanding AlgebraExploring BinomialsUnderstanding Polynomials
Understanding Algebra
Algebra is a branch of mathematics that deals with symbols and the rules for manipulating those symbols. It allows us to express relationships and patterns in a general form. In algebra, letters or symbols are used to represent numbers. This makes it easier to write and manipulate mathematical expressions.
A crucial aspect of algebra is understanding how to work with equations and expressions. By using algebraic methods, we can solve for unknown quantities and find out their relationships with others.
An important skill in algebra is recognizing patterns, such as the difference of squares. This pattern helps in simplifying expressions and solving equations efficiently.
A crucial aspect of algebra is understanding how to work with equations and expressions. By using algebraic methods, we can solve for unknown quantities and find out their relationships with others.
An important skill in algebra is recognizing patterns, such as the difference of squares. This pattern helps in simplifying expressions and solving equations efficiently.
Exploring Binomials
Binomials are algebraic expressions that consist of two terms separated by either a plus or a minus sign. Examples of binomials include
A particularly useful technique when multiplying binomials is the difference of squares. This arises when we have two binomials of the form
- \((a + b)\)
- \((x - y)\)
A particularly useful technique when multiplying binomials is the difference of squares. This arises when we have two binomials of the form
- \((a + b)\)
- \((a - b)\)
Understanding Polynomials
Polynomials are algebraic expressions that consist of multiple terms. These terms can include variables raised to whole number powers and constants. A simple example of a polynomial is
When working with polynomials, it's important to understand operations such as addition, subtraction, multiplication, and sometimes division. This involves combining like terms and using techniques such as the distributive property.
In our exercise, the difference of squares is a method that simplifies the multiplication of two binomials, resulting in a polynomial expression. The product of the given binomials is another polynomial, deduced using this method.
- \(3x^2 - 4y^2\)
- \(5x^3 + x - 6\)
When working with polynomials, it's important to understand operations such as addition, subtraction, multiplication, and sometimes division. This involves combining like terms and using techniques such as the distributive property.
In our exercise, the difference of squares is a method that simplifies the multiplication of two binomials, resulting in a polynomial expression. The product of the given binomials is another polynomial, deduced using this method.
Other exercises in this chapter
Problem 46
Perform the indicated operations and simplify.\(\frac{x+2}{5(x-3)} \div \frac{x-2}{5(x-3)}\)
View solution Problem 46
Completely factor the expression.\(12 x^{3}-48 x\)
View solution Problem 47
Rewrite the expression by rationalizing the denominator. Simplify your answer.\(\frac{3}{\sqrt{5}+\sqrt{6}}\)
View solution Problem 47
Rewrite the expression with positive exponents and simplify.\((y+2)^{-2}(y+2)^{-1}\)
View solution