Problem 46
Question
Find the parametric equation of the line in the \(x-y\) plane that goes through the indicated point in the direction of the indicated vector. $$ (-1,4),\left[\begin{array}{l} 2 \\ 3 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
Parametric equations: \(x(t) = -1 + 2t\), \(y(t) = 4 + 3t\).
1Step 1: Understand the components of the problem
We are given a point (-1, 4)and a direction vector\[\begin{bmatrix}2 \3\end{bmatrix}\].The goal is to find the parametric equations of the line passing through the given point and following the direction of the vector.
2Step 2: Write the general form of the parametric equation
A line in two-dimensional space can be represented by the parametric equations\(x = x_0 + at\)and\(y = y_0 + bt\), where \((x_0, y_0)\)is a point on the line,\( a\)and \(b\) are the components of the direction vector, and \(t\)is the parameter.
3Step 3: Substitute the given point into the parametric equation
Use the given point (-1, 4)as \\((x_0, y_0))\):\(x = -1 + 2t\)\(y = 4 + 3t\).
4Step 4: Write the final parametric equations
Therefore, the parametric equations of the line are:\(x(t) = -1 + 2t\)and\(y(t) = 4 + 3t\)
Key Concepts
Direction VectorTwo-Dimensional SpaceLines in Geometry
Direction Vector
In the realm of parametric equations and lines, the direction vector plays a crucial role. It essentially determines the path that the line will take through space. Imagine you have a little arrow that points a specific way. That's what a direction vector does; it points the way your line will extend. In our exercise, the direction vector is \( \begin{bmatrix} 2 \ 3 \end{bmatrix} \). This means each step the line takes in the direction of the vector will move 2 units in the x-direction and 3 units in the y-direction. To construct a parametric equation, we attach this direction influence to a point.
- The direction vector provides the slope of the line.
- Each component of the vector demonstrates how far we move along each axis for every unit change in the parameter \(t\).
- This makes the line's path predictable and easy to follow.
Two-Dimensional Space
Two-dimensional space, commonly called the plane, is something we deal with every day, even if we don’t think about it. It's simply a flat surface that stretches endlessly in every direction.When dealing with points and lines in this space, we use coordinates to determine locations along the x and y axes. Each point on this plane is a combination of x and y values. In the current exercise, the point \((-1, 4)\) is such a point.
- The x-component tells us how far left or right the point is from the origin.
- The y-component tells us how far up or down the point is.
Lines in Geometry
Lines in geometry are fundamental concepts that seem simple but are quite profound. In essence, a line is a straight one-dimensional figure that extends indefinitely in both directions. It's defined by any two points or a point and a direction vector.In our exercise, the line is defined to pass through the point \((-1, 4)\) with a direction determined by the vector \( \begin{bmatrix} 2 \ 3 \end{bmatrix} \). To describe this line in terms of parametric equations:
- The x-component: \( x = -1 + 2t \)
- The y-component: \( y = 4 + 3t \)
Other exercises in this chapter
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Find the parametric equation of the line in the \(x-y\) plane that goes through the indicated point in the direction of the indicated vector. $$ (-1,-2),\left[\
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