Problem 46
Question
Find the intersection points of the pair of ellipses. Sketch the graphs of each pair of equations on the same coordinate axes, and label the points of intersection. $$\left\\{\begin{array}{l} \frac{x^{2}}{16}+\frac{y^{2}}{9}=1 \\ \frac{x^{2}}{9}+\frac{y^{2}}{16}=1 \end{array}\right.$$
Step-by-Step Solution
Verified Answer
The coordinates of intersection points are (0, ±3) and (±4, 0).
1Step 1: Identify the Equations of the Ellipses
We have two equations representing two ellipses:1) \( \frac{x^2}{16} + \frac{y^2}{9} = 1 \)2) \( \frac{x^2}{9} + \frac{y^2}{16} = 1 \). The first equation represents an ellipse with its major axis along the x-direction, and the second one has its major axis along the y-direction.
2Step 2: Set Up the System to Find Intersection Points
To find the intersection points of the ellipses, we need to solve this system of equations simultaneously.Given:\[ \frac{x^2}{16} + \frac{y^2}{9} = 1 \]\[ \frac{x^2}{9} + \frac{y^2}{16} = 1 \].
3Step 3: Solve Using Subtraction of Equations
Subtract the second equation from the first:\[ \left( \frac{x^2}{16} + \frac{y^2}{9} \right) - \left( \frac{x^2}{9} + \frac{y^2}{16} \right) = 0 \].Simplify to find:\[ \frac{x^2}{16} - \frac{x^2}{9} + \frac{y^2}{9} - \frac{y^2}{16} = 0 \].
4Step 4: Simplify and Combine Terms
Factor the equation step by step:- Convert subtraction into a common denominator.- Combine the \(x^2\) terms: \( \frac{x^2}{144} (-9 + 16) = \frac{7x^2}{144} \).- Combine the \(y^2\) terms: \( \frac{y^2}{144} (16 - 9) = \frac{7y^2}{144} \).The equation becomes:\[ \frac{7x^2}{144} = \frac{7y^2}{144} \].
Key Concepts
EllipsesSystem of EquationsCoordinate Geometry
Ellipses
An ellipse is a geometric shape that looks like an elongated circle or an oval. It is defined by two main axes: the major axis and the minor axis. The major axis is the longest diameter of the ellipse, while the minor axis is the shortest.
When discussing ellipses in a coordinate plane, we often deal with standard equation forms. The general form for an ellipse centered at the origin is \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]where \(a\) and \(b\) are the lengths of the semi-major and semi-minor axes, respectively.
For the given problem, we have two specific ellipses:
When discussing ellipses in a coordinate plane, we often deal with standard equation forms. The general form for an ellipse centered at the origin is \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]where \(a\) and \(b\) are the lengths of the semi-major and semi-minor axes, respectively.
For the given problem, we have two specific ellipses:
- The first ellipse, \(\frac{x^2}{16} + \frac{y^2}{9} = 1\), has a major axis along the x-direction. The semi-major axis length is 4 (since \( \sqrt{16} = 4\)) and the semi-minor axis length is 3 (since \( \sqrt{9} = 3\)).
- The second ellipse, \(\frac{x^2}{9} + \frac{y^2}{16} = 1\), has its major axis along the y-direction. This means its semi-major axis length is 4, and its semi-minor axis length is 3.
System of Equations
Solving a system of equations involves finding values for variables that satisfy all equations in the system. In the context of finding intersection points of ellipses, we are dealing with a system of two equations.
For this exercise, the system consists of:
In this case, the subtraction method is employed where equation 2 is subtracted from equation 1 to simplify the terms and make it easier to solve for intersection points. This process involves careful handling of fractions and ensuring terms are aligned for combination.
For this exercise, the system consists of:
- Equation 1: \(\frac{x^2}{16} + \frac{y^2}{9} = 1\)
- Equation 2: \(\frac{x^2}{9} + \frac{y^2}{16} = 1\)
In this case, the subtraction method is employed where equation 2 is subtracted from equation 1 to simplify the terms and make it easier to solve for intersection points. This process involves careful handling of fractions and ensuring terms are aligned for combination.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, allows us to use algebraic equations to represent geometric shapes on a coordinate plane. This field of study bridges the gap between algebra and geometry, making it easier to visualize and solve geometric problems.
When we work with the intersection of ellipses, coordinate geometry helps us visualize these curves on a plane. The coordinate axes serve as reference points for plotting ellipses and determining where they intersect.
When we work with the intersection of ellipses, coordinate geometry helps us visualize these curves on a plane. The coordinate axes serve as reference points for plotting ellipses and determining where they intersect.
- Graphs of both ellipses are plotted based on their respective equations.
- The points where these graphs meet are the solutions to the system of equations: they represent the intersection points of the ellipses.
Other exercises in this chapter
Problem 46
(a) For the hyperbola $$\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$$ determine the values of \(a, b,\) and \(c,\) and find the coordinates of the foci \(F_{1}\) and \(F
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When we found polar equations for the conics, we placed one focus at the pole. It's easy to find the distance from that focus to any point on the conic. Explain
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Hyperbolas are called confocal if they have the same foci. (a) Show that the hyperbolas $$\frac{y^{2}}{k}-\frac{x^{2}}{16-k}=1 \quad \text { with } 0
View solution Problem 47
Find the intersection points of the pair of ellipses. Sketch the graphs of each pair of equations on the same coordinate axes, and label the points of intersect
View solution