Problem 46
Question
Find each product. $$(x-4)^{2}$$
Step-by-Step Solution
Verified Answer
The product of \((x-4)^{2}\) simplifies to \(x^{2} - 8x + 16\).
1Step 1: Rewrite the Problem to Visualize the Multiplication
Begin by rewriting the problem as \((x-4) * (x-4)\) to make it clear that there is a multiplication of two binomials.
2Step 2: Apply Distributive Property
Now use the FOIL method to multiply. Multiply the first terms in each binomial together to get \(x * x = x^{2}\). Multiply the outer terms together to get \(x * -4 = -4x\). Multiply the inner terms together to get \(-4 * x = -4x\). Lastly, multiply the last terms in each binomial together to get \(-4 * -4 = 16\).
3Step 3: Simplify the Expression
Now, add the multiplication terms together. This simplifies to \(x^{2} - 4x - 4x + 16\). When combining like terms, you will get \(x^{2} - 8x + 16\).
Key Concepts
Distributive PropertyFOIL MethodSimplification of Expressions
Distributive Property
The distributive property is a fundamental principle in algebra that allows us to distribute a single term across terms inside parentheses. For multiplying binomials, the distributive property is often applied in a structured way like the FOIL method.
When you have an expression like \(a(b + c)\), you use the distributive property to expand it:
For more complex expressions, especially those involving binomials like \(x - 4\), you apply the distributive property through each term within the parentheses. This is precisely what simplifies and systematizes the multiplication process, ensuring nothing is missed.
When you have an expression like \(a(b + c)\), you use the distributive property to expand it:
- Multiply \(a\) by \(b\) to get \(ab\).
- Multiply \(a\) by \(c\) to get \(ac\).
For more complex expressions, especially those involving binomials like \(x - 4\), you apply the distributive property through each term within the parentheses. This is precisely what simplifies and systematizes the multiplication process, ensuring nothing is missed.
FOIL Method
The FOIL method is a nifty technique for multiplying two binomials. It stands for First, Outer, Inner, and Last, representing the pairs of terms you multiply together.
Here's how it works for \( (x-4)(x-4) \):
Here's how it works for \( (x-4)(x-4) \):
- First: Multiply the first terms, \(x * x\), giving you \(x^2\).
- Outer: Multiply the outer terms, \(x * -4\), resulting in \(-4x\).
- Inner: Multiply the inner terms, \(-4 * x\), which gives \(-4x\).
- Last: Multiply the last terms, \(-4 * -4\), providing the result \(+16\).
Simplification of Expressions
Simplifying expressions is about combining like terms to make an expression easier to understand. After multiplying, as seen with \( (x-4)(x-4) \), you'll end up with terms like \( x^2 - 4x - 4x + 16 \).
To simplify:
To simplify:
- Combine like terms. Here, \(-4x\) and \(-4x\) are like terms since they both involve \(x\).
- Adding them gives you \(-8x\).
- The expression then becomes \(x^2 - 8x + 16\).
Other exercises in this chapter
Problem 46
evaluate each algebraic expression for the given value of the variable or variables. $$ \frac{7(x-3)}{2 x-16} ; x=9 $$
View solution Problem 46
Simplify each exponential expression $$ \left(11 x^{5}\right)\left(9 x^{12}\right) $$
View solution Problem 46
In Exercises \(39-48\), rationalize the denominator. $$\frac{5}{\sqrt{3}-1}$$
View solution Problem 46
In Exercises \(41-48,\) factor any perfect square trinomials, or state that the polynomial is prime. $$25 x^{2}+10 x+1$$
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