Problem 46
Question
Find \(b^{2}-4 a c\) and the number of real solutions to each equation. $$-6 x^{2}-5=0$$
Step-by-Step Solution
Verified Answer
Discriminant: \(-120\), Number of real solutions: 0.
1Step 1 - Identify coefficients
Rewrite the given equation in standard form, which is \(ax^2 + bx + c = 0\). The given equation is \(-6x^2 - 5 = 0\). This can be written as \(-6x^2 + 0x - 5 = 0\). Identify the coefficients: \(a = -6\), \(b = 0\), and \(c = -5\).
2Step 2 - Calculate the discriminant
The discriminant formula is \(b^2 - 4ac\). Substitute the values of \(a\), \(b\), and \(c\) into the formula: \[ b^2 - 4ac = 0^2 - 4(-6)(-5) \]Calculate the result step-by-step: \[ 0 - 4 \times -6 \times -5 = 0 - 120 = -120 \].So, the discriminant is \(-120\).
3Step 3 - Determine the number of real solutions
The number of real solutions of the equation depends on the value of the discriminant: - If the discriminant is positive, there are two distinct real solutions.- If the discriminant is zero, there is exactly one real solution.- If the discriminant is negative, there are no real solutions.Since the discriminant \(-120\) is negative, there are no real solutions.
Key Concepts
DiscriminantReal SolutionsApplication in Algebra
Discriminant
The discriminant is a key concept in algebra, particularly when solving quadratic equations in the form of \(ax^2 + bx + c = 0\). It is denoted by the formula \(b^2 - 4ac\) and helps to determine the nature of the roots of the equation. The coefficients \(a\), \(b\), and \(c\) are constants from the quadratic equation.
To better understand:
To better understand:
- First, rewrite your quadratic equation in the standard form: \(ax^2 + bx + c = 0\).
- Identify the coefficients \(a\), \(b\), and \(c\).
- Substitute the values into the discriminant formula \(b^2 - 4ac\).
Real Solutions
Real solutions are the values of \(x\) that satisfy the quadratic equation \(ax^2 + bx + c = 0\). The discriminant \(b^2 - 4ac\) plays an essential role in determining how many real solutions exist:
- If the discriminant is positive (> 0), the quadratic equation has two distinct real solutions.
- If the discriminant is zero (= 0), there is exactly one real solution.
- If the discriminant is negative (< 0), there are no real solutions, implying the solutions are complex or imaginary numbers.
Application in Algebra
Quadratic equations and their solutions have numerous applications in algebra and real-life scenarios. For instance:
- Projectile motion in physics often uses quadratic equations to predict the trajectory of objects.
- Optimization problems in economics and business can be solved using quadratic equations to find maximum or minimum values.
- In geometry, quadratic equations are used to calculate areas and volumes involving parabolic shapes.
Other exercises in this chapter
Problem 44
Find the vertex and intercepts for each quadratic function. Sketch the graph, and state the domain and range. $$f(x)=x^{2}+2 x-3$$
View solution Problem 45
Find the vertex and intercepts for each quadratic function. Sketch the graph, and state the domain and range. $$g(x)=x^{2}+2 x-8$$
View solution Problem 46
Find the vertex and intercepts for each quadratic function. Sketch the graph, and state the domain and range. $$g(x)=x^{2}+x-6$$
View solution Problem 47
Find \(b^{2}-4 a c\) and the number of real solutions to each equation. $$x^{2}=x$$
View solution