Problem 46
Question
Find an equation for the indicated half of the parabola. Lower half of \((y+4)^{2}=x-3\)
Step-by-Step Solution
Verified Answer
The lower half of the parabola is given by \(y = -4 - \sqrt{x-3}\).
1Step 1: Understand the Given Equation
The given equation \((y+4)^2 = x-3\) represents a parabola. This comes in the form of \((y-k)^2 = 4p(x-h)\) which opens to the right or left because \(y\) is squared. Here, \((h, k)\) is the vertex. Comparing, the vertex \((h, k)\) is \((3, -4)\).
2Step 2: Solving for x
Since we are looking for \(x\) as a function of \(y\), rearrange the equation: \((y+4)^2 + 3 = x\). This simplifies to \(x = (y+4)^2 + 3\).
3Step 3: Determine the Lower Half
The equation \((y+4)^{2}=x-3\) represents a parabola symmetric with respect to the line \(y = -4\). To get the lower half, we recognize that for a parabolic equation opening sideways, the 'lower' part corresponds to when \(y+4\) is non-positive, meaning \(y+4 ≤ 0\). Thus, take \(y+4 = -\sqrt{x-3}\), giving us \(x = (y+4)^2 + 3\) with \(y = -4 -\sqrt{x-3}\).
4Step 4: Final Equation
The equation that represents the lower half of the given parabola is \(y = -4 - \sqrt{x-3}\), ensuring \(y+4 ≤ 0\).
Key Concepts
Understanding the Vertex FormExploring Parabola SymmetryIdentifying Horizontal ParabolasApproach to Solving Quadratic Equations
Understanding the Vertex Form
Vertex form is an essential concept when dealing with parabolas. It's generally given by the equation \((y-k)^2 = 4p(x-h)\) for horizontal parabolas. Here, \(h\) and \(k\) represent the vertex coordinates of the parabola. This form is particularly useful because it tells us exactly where the vertex of the parabola is located, and it indicates the direction the parabola opens. For horizontal parabolas, the graph opens to the left or the right, not up or down.
- \(h\) is the x-coordinate of the vertex.
- \(k\) is the y-coordinate of the vertex.
- 4p indicates the distance that determines how "wide" or "narrow" the parabola will be.
Exploring Parabola Symmetry
Parabolas have a unique property: symmetry. For horizontal parabolas, this symmetry is about a horizontal line, specifically a line parallel to the x-axis. In the equation \((y+4)^2 = x-3\), the line of symmetry is given by \((k = -4)\). This means that the parabola is mirrored on either side of the horizontal line \(y = -4\).
This symmetry is significant because it allows us to separate the parabola into two halves.
This symmetry is significant because it allows us to separate the parabola into two halves.
- The upper half, where \(y > -4\), and
- The lower half, where \(y <= -4\).
Identifying Horizontal Parabolas
Unlike the more commonly visualized vertical parabolas, horizontal parabolas are defined by an equation where \(y\) is squared, such as in \((y-k)^2 = 4p(x-h)\).
- Horizontal parabolas open to the right if \(4p > 0\).
- They open to the left if \(4p < 0\).
Approach to Solving Quadratic Equations
To solve quadratic equations effectively, it is often useful to rearrange them into a form that makes finding the solutions straightforward. Here, with \((y+4)^2 = x-3\), we rearranged it to find \(x\) in terms of \(y\): \(x = (y+4)^2 + 3\). Doing this helps in clearly delineating the function and guides us towards solving for certain conditions, like the lower half of the parabola.
When dealing with parabolic splitting (upper and lower halves), understanding the domain and range conditions is vital. Since the task at hand was to determine the lower half, ensuring that \(y+4\leq 0\) was a crucial step to express it effectively. Thus, \(y = -4 - \sqrt{x-3}\) aligns perfectly with maintaining \(y \le -4\), giving us the needed section of the parabola.
When dealing with parabolic splitting (upper and lower halves), understanding the domain and range conditions is vital. Since the task at hand was to determine the lower half, ensuring that \(y+4\leq 0\) was a crucial step to express it effectively. Thus, \(y = -4 - \sqrt{x-3}\) aligns perfectly with maintaining \(y \le -4\), giving us the needed section of the parabola.
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