Problem 46
Question
Factor the difference of two squares. $$x^{4}-1$$
Step-by-Step Solution
Verified Answer
The factored form of \(x^{4}-1\) is \((x^{2}+1)(x+1)(x-1)\).
1Step 1: Identify the difference of two squares
The given expression is \(x^{4}-1\). Note that \(x^{4}\) can be written as \((x^{2})^{2}\) and 1 as \(1^{2}\). So the expression is in the form \(a^{2} - b^{2}\).
2Step 2: Apply the formula
Using the formula \(a^{2} - b^{2} = (a+b)(a-b)\), substitute \(a = x^{2}\) and \(b = 1\). By doing this, the expression \(x^{4}-1\) can be re-written to \((x^{2}+1)(x^{2}-1)\).
3Step 3: Refactor the second difference of squares
The term \(x^{2}-1\) can further be factored due to being a difference of squares. We have \(a = x\) and \(b = 1\), so the expression becomes \(x^{2}-1 = (x+1)(x-1)\).
4Step 4: Rewrite with all factors
Putting it all together, the expression \(x^{4}-1\) has been factored into \((x^{2}+1)(x+1)(x-1)\). This is the fully factored form of the expression.
Other exercises in this chapter
Problem 45
True or false. $$4 \geq-7$$
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add or subtract as indicated. $$ \frac{3 x}{x-3}-\frac{x+4}{x+2} $$
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Rationalize the denominator. $$ \frac{2}{\sqrt{10}} $$
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In Exercises 15–58, find each product. $$ (x-4)^{2} $$
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