Problem 46
Question
Factor by first grouping the appropriate terms. \(s^{2}-t^{2}+s-t\)
Step-by-Step Solution
Verified Answer
The expression factors to \(s(s+1) - t(t+1)\).
1Step 1: Rearrange the Expression
Start by rearranging the terms to: \[ (s^2 + s) - (t^2 + t) \]This rearrangement will help us see the common factors more easily when we group them.
2Step 2: Group the Terms
Group terms in pairs:\[ (s^2 + s) - (t^2 + t) \]This expression groups terms based on similar structures like \[ (s(s + 1)) - (t(t + 1)) \].
3Step 3: Factor Each Group
Now, factor out the common factors from each group:\[ s(s+1) - t(t+1) \]In each pair, the common factor is the variable term.
4Step 4: Use the Difference of Products
Notice that we now have a difference of two products:\[ s(s+1) - t(t+1) \]Keep the expression as it is since it is factored as a difference of products.
Key Concepts
Grouping TermsRearranging ExpressionsCommon Factors
Grouping Terms
Grouping terms is a pivotal technique in factoring algebraic expressions, especially when dealing with polynomials. This method involves organizing terms into pairs or groups, so they exhibit a common structure. It simplifies the process of identifying and extracting common factors from these groups.
Grouping is particularly useful when you cannot immediately spot a common factor across all elements of the expression. Instead, by separating terms into strategic groupings, you can find factors within each group, which might otherwise not be obvious.
Grouping is particularly useful when you cannot immediately spot a common factor across all elements of the expression. Instead, by separating terms into strategic groupings, you can find factors within each group, which might otherwise not be obvious.
- For example, in the given expression, \(s^2 - t^2 + s - t\), grouping similar structures can streamline the factoring process.
- By rearranging and grouping, you reorganize terms to allow for more straightforward identification of factors, leading to an easier simplification process.
Rearranging Expressions
Rearranging expressions is a fundamental skill in algebra that prepares an equation or expression for further manipulation, like factoring. Through rearrangement, you can highlight similarities between different parts of the expression, making it easier to apply various algebraic techniques.
Rearrangement typically involves changing the order of terms in a polynomial. The goal is to place terms with similar characteristics next to each other to readily spot patterns or common elements. For instance, rearranging the expression \(s^2 - t^2 + s - t\) as \((s^2 + s) - (t^2 + t)\) arranges the terms to help identify potential groupings based on their structures.
Rearrangement typically involves changing the order of terms in a polynomial. The goal is to place terms with similar characteristics next to each other to readily spot patterns or common elements. For instance, rearranging the expression \(s^2 - t^2 + s - t\) as \((s^2 + s) - (t^2 + t)\) arranges the terms to help identify potential groupings based on their structures.
- This organization is crucial as it reveals symmetries or similar patterns—steps that pave the way for efficient grouping and factoring.
- Beyond revealing common factors, rearranging can sometimes simplify the cognitive load by aligning terms in a visually manageable manner.
Common Factors
Identifying common factors in polynomial expressions is key to simplifying or factoring them. A common factor is any variable or coefficient that appears in all terms within a group you are examining.
Finding common factors involves:
Mastering the art of spotting and utilizing common factors paves the way to more advanced calculations and equation solving. It streamlines a seemingly complex expression into more manageable parts, significantly aiding in its simplification.
Finding common factors involves:
- Recognizing repeated numbers or variables across terms.
- Extracting these repeated elements to simplify the expression or prepare it for further factoring techniques.
Mastering the art of spotting and utilizing common factors paves the way to more advanced calculations and equation solving. It streamlines a seemingly complex expression into more manageable parts, significantly aiding in its simplification.
Other exercises in this chapter
Problem 46
Solve each problem by writing a variation model. The power (in watts) lost in a resistor (in the form of heat) varies directly as the square of the current (in
View solution Problem 46
Factor by grouping. $$ d^{2}+c d+c+d $$
View solution Problem 46
Solve each equation. \(15-|12 x+12|=15\)
View solution Problem 46
Solve each compound inequality, if possible. Graph the solution set (if one exists) and write it using interval notation. $$ 4.5 x-1
View solution