Problem 46
Question
Exer. 11-46: Simplify. $$ a^{4 / 3} a^{-3 / 2} a^{1 / 6} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to 1.
1Step 1: Understanding Power Rules
To simplify expressions involving exponents, you need to remember the power rule: \( a^m \times a^n = a^{m+n} \). This means when you multiply powers with the same base, you add their exponents.
2Step 2: Adding the Exponents
Given the expression \( a^{4/3} \times a^{-3/2} \times a^{1/6} \), apply the power rule by adding the exponents: \( \frac{4}{3} + \left( -\frac{3}{2} \right) + \frac{1}{6} \).
3Step 3: Simplifying the Addition of Fractions
To add these fractions, we need a common denominator. The denominators are 3, 2, and 6. The least common denominator is 6. Convert each fraction:- \( \frac{4}{3} = \frac{8}{6} \) - \( -\frac{3}{2} = -\frac{9}{6} \) - \( \frac{1}{6} = \frac{1}{6} \).Now add them: \( \frac{8}{6} + (-\frac{9}{6}) + \frac{1}{6} = \frac{8 - 9 + 1}{6} = 0 \).
4Step 4: Final Expression with Zero Exponent
Since the sum of the exponents is 0, by the rule \( a^0 = 1 \) (for \( a eq 0 \)), the expression \( a^0 = 1 \).
Key Concepts
Power RuleFraction AdditionZero Exponent Rule
Power Rule
The Power Rule is a key concept in simplifying exponential expressions. It states that when you multiply two expressions with the same base, you simply add their exponents.
This rule can be summarized as:
In the original exercise, applying the Power Rule allows us to combine the three separate powers of \( a \) into a single power.
Remember, this rule only works when the bases are identical. This consistency with the base is crucial for the Power Rule to hold.
This rule can be summarized as:
- \( a^m \times a^n = a^{m+n} \)
In the original exercise, applying the Power Rule allows us to combine the three separate powers of \( a \) into a single power.
Remember, this rule only works when the bases are identical. This consistency with the base is crucial for the Power Rule to hold.
Fraction Addition
Adding fractions can be tricky at first, but it's much easier once you find a common denominator.
This denominator should be a number that all the individual denominators can divide evenly.
For example, if you're adding \( \frac{4}{3} \), \( -\frac{3}{2} \), and \( \frac{1}{6} \), the least common denominator is 6.
To convert each fraction:
This process results in: \[ \frac{8}{6} + (-\frac{9}{6}) + \frac{1}{6} = \frac{8 - 9 + 1}{6} = 0 \]Finding a common denominator makes fraction addition straightforward and simplifies the process of handling fractional exponents.
This denominator should be a number that all the individual denominators can divide evenly.
For example, if you're adding \( \frac{4}{3} \), \( -\frac{3}{2} \), and \( \frac{1}{6} \), the least common denominator is 6.
To convert each fraction:
- \( \frac{4}{3} \) becomes \( \frac{8}{6} \)
- \( -\frac{3}{2} \) becomes \( -\frac{9}{6} \)
- \( \frac{1}{6} \) stays \( \frac{1}{6} \)
This process results in: \[ \frac{8}{6} + (-\frac{9}{6}) + \frac{1}{6} = \frac{8 - 9 + 1}{6} = 0 \]Finding a common denominator makes fraction addition straightforward and simplifies the process of handling fractional exponents.
Zero Exponent Rule
The Zero Exponent Rule is a handy shortcut when working with powers.
This rule states that any non-zero number raised to the power of zero equals one.
Mathematically, it's shown as:
In our exercise, we ended up with \( a^0 \) after simplifying the exponent sum, resulting in the expression simplified to 1.
The Zero Exponent Rule is a powerful tool that often appears in algebra, easy to remember and often simplifies expressions quickly.
This rule states that any non-zero number raised to the power of zero equals one.
Mathematically, it's shown as:
- \( a^0 = 1 \)
- \( a^n / a^n = a^{n-n} = a^0 = 1 \)
In our exercise, we ended up with \( a^0 \) after simplifying the exponent sum, resulting in the expression simplified to 1.
The Zero Exponent Rule is a powerful tool that often appears in algebra, easy to remember and often simplifies expressions quickly.
Other exercises in this chapter
Problem 45
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