Problem 46
Question
Evaluate the expression. $$ 1.3+(-1.3)-4.2 $$
Step-by-Step Solution
Verified Answer
-4.2
1Step 1: Add 1.3 and -1.3
When we add \(1.3\) and \(-1.3\), we obtain \(0\). This is because \(-1.3\) is the additive inverse of \(1.3\), so adding these two numbers together results in zero.
2Step 2: Subtract 4.2 from the Result
After obtaining \(0\) from step 1, we then subtract \(4.2\) from \(0\). Since subtracting a number is equivalent to adding its additive inverse, and the additive inverse of \(4.2\) is \(-4.2\), we add \(-4.2\) to \(0\) and get \(-4.2\).
Key Concepts
Understanding the Additive InverseSubtraction as Addition of the Additive InverseStep-by-Step Solutions and Their Role in Learning
Understanding the Additive Inverse
The additive inverse of a number is a fundamental concept in mathematics. Simply put, the additive inverse is what you would add to a number to get zero. For any given number, its additive inverse is the same number with the opposite sign.
For example:
For example:
- The additive inverse of 5 is \(-5\).
- The additive inverse of \(-2\) is 2.
Subtraction as Addition of the Additive Inverse
Subtraction is often thought of as a more challenging operation than addition. However, it can be simplified by viewing subtraction as the addition of an additive inverse. When you subtract a number, it's the same as adding the opposite of that number.
For instance, when we say we're subtracting 4.2, we're really adding \(-4.2\).
For instance, when we say we're subtracting 4.2, we're really adding \(-4.2\).
- Think of subtraction as the addition of the inverse.
- This makes calculations more uniform and easier to manage.
Step-by-Step Solutions and Their Role in Learning
Step-by-step solutions are a great way to break down complex problems into more manageable parts. By understanding each piece individually, students can gain a clearer picture of the entire process.
In the given exercise:
In the given exercise:
- Step 1 shows how the additive inverse simplifies two terms to zero.
- Step 2 demonstrates subtraction by converting it to an addition problem.
Other exercises in this chapter
Problem 46
Evaluate the expression. $$-4(|y-12|) \text { when } y=5$$
View solution Problem 46
Simplify the expression. $$3 \cdot\left(-\frac{y}{3}\right)$$
View solution Problem 46
Evaluate the expression. $$|0|+2$$
View solution Problem 47
DISTRIBUTIVE PROPERTY Use the distributive property to rewrite the expression without parentheses. $$ 5\left(\frac{1}{2} x-\frac{2}{3}\right) $$
View solution