Problem 46
Question
Determine the domains of (a) \(f,\) (b) \(g\) and (c) \(f \circ g .\) Use a graphing utility to verify your results. $$f(x)=\sqrt{x+3}, \quad g(x)=\frac{x}{2}$$
Step-by-Step Solution
Verified Answer
The domains of \(f(x)\), \(g(x)\), and \(f \circ g (x)\) are [-3, +\infty), (-\infty,+ \infty) and [-6, +\infty) respectively.
1Step 1: Find the Domain of \(f(x)\)
Set the expression inside the square root in \(f(x)\) to be greater or equal to zero, i.e., \(x+3 \geq 0\). Solving this inequality results in \(x \geq -3\). So, the domain of \(f(x)\) is \([-3, +\infty)\].
2Step 2: Find the Domain of \(g(x)\)
The function \(g(x) = \frac{x}{2}\) does not have any restrictions. It is defined for all real numbers, so its domain is \(-\infty, +\infty\).
3Step 3: Find the Domain of \(f \circ g (x)\)
Substitute \(g(x) = \frac{x}{2}\) into \(f(x) = \sqrt{x+3}\) to get \(f \circ g (x) = \sqrt{\frac{x}{2} + 3}\). The domain of this function is determined by setting the expression inside the square root to be greater than or equal to zero, i.e., \( \frac{x}{2} +3 \geq 0\). Solving this inequality gives \(x \geq -6\). So, the domain of \(f \circ g (x)\) is \([-6, +\infty)\]
Key Concepts
Composite FunctionsInequalitiesSquare Root Function
Composite Functions
Composite functions are an essential concept in mathematics where you combine two functions to form a new one. When dealing with composite functions, the notation \( f \circ g \) is used, which means you first apply function \( g \) to a variable and then apply function \( f \) to the result of \( g \).
To determine the value of a composite function at a particular point \( x \), you:
To determine the value of a composite function at a particular point \( x \), you:
- Substitute \( x \) into the function \( g \).
- Take the result from \( g(x) \) and substitute it into the function \( f \).
Inequalities
Inequalities involve expressions that use symbols such as \( >, <, \geq, \) and \( \leq \) to denote relationships between quantities. Understanding inequalities is crucial in solving domain problems, particularly in determining which values a variable can take.
In the example, the function \( f(x) = \sqrt{x+3} \) required setting up an inequality \( x+3 \geq 0 \) to determine the allowed values for \( x \). Solving this inequality gives \( x \geq -3 \), indicating that \( x \) must be greater than or equal to \(-3\), reflecting the domain of the function \( f(x) \).
In the example, the function \( f(x) = \sqrt{x+3} \) required setting up an inequality \( x+3 \geq 0 \) to determine the allowed values for \( x \). Solving this inequality gives \( x \geq -3 \), indicating that \( x \) must be greater than or equal to \(-3\), reflecting the domain of the function \( f(x) \).
- To solve inequalities: isolate the variable on one side through valid algebraic operations.
- Keep track of the inequality's direction; it stays the same unless both sides are multiplied or divided by a negative number.
Square Root Function
The square root function plays a significant role in many mathematical contexts and must meet specific criteria to be defined properly. The function \( f(x) = \sqrt{x} \) is defined only for non-negative values of \( x \) because the square root of a negative number is not real under standard mathematical operations.
To determine the domain for a square root function like \( f(x) = \sqrt{x+3} \):
To determine the domain for a square root function like \( f(x) = \sqrt{x+3} \):
- Ensure that the expression inside the square root (here, \( x+3 \)) is non-negative by setting up the inequality \( x+3 \geq 0 \).
- Solving this gives \( x \geq -3 \), meaning the domain begins from \(-3\) and extends to positive infinity.
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