Problem 46
Question
Decide whether the ordered pair is a solution of the inequality. $$y>3 x^{2}+50 x+500 ;(-6,100)$$
Step-by-Step Solution
Verified Answer
No, the ordered pair (-6,100) is not a solution of the inequality \(y > 3x^2 + 50x + 500\).
1Step 1: Identification
Identify the ordered pair (-6,100) where the first value is x = -6 and the second value is y = 100.
2Step 2: Substitution
Substitute these values into the inequality: 100 > 3(-6)^2 + 50(-6) + 500.
3Step 3: Simplification
Simplify the right side of the inequality: 100 > 3*36 + (-300) + 500, which simplifies further to 100 > 108 - 300 + 500 and finally to 100 > 308.
4Step 4: Comparison
Compare the left side (100) to the right side (308) and determine if the inequality stands: As 100 is not greater than 308, the provided ordered pair (-6,100) is not a solution to the inequality.
Key Concepts
Understanding Ordered PairsSolving InequalitiesUsing the Substitution MethodSimplification Process
Understanding Ordered Pairs
Ordered pairs are simply a set of two numbers written in a specific order. The first number refers to the value of \( x \), and the second number refers to the value of \( y \). For example, in the ordered pair \((-6, 100)\), \( x = -6 \) and \( y = 100 \). Ordered pairs are often used to represent points on a graph.
In context, they help us determine if specific values for \( x \) and \( y \) satisfy a given equation or inequality. By substituting these values into the equation, we can see if the ordered pair is a solution.
In context, they help us determine if specific values for \( x \) and \( y \) satisfy a given equation or inequality. By substituting these values into the equation, we can see if the ordered pair is a solution.
Solving Inequalities
Inequalities are mathematical statements that express a relationship of order between two expressions. In the inequality \( y > 3x^2 + 50x + 500 \), we are looking at whether \( y \) is greater than the expression on the right.
It's crucial to substitute the values of \( x \) and \( y \) from the ordered pair into the inequality to test if it holds true.
It's crucial to substitute the values of \( x \) and \( y \) from the ordered pair into the inequality to test if it holds true.
- If the statement is true, the ordered pair is a solution.
- If false, it's not a solution.
Using the Substitution Method
The substitution method involves replacing variables with specific values to see how an equation or inequality behaves. Here, we substitute \( x = -6 \) and \( y = 100 \) into the inequality:
\[100 > 3(-6)^2 + 50(-6) + 500\]
This substitution helps us quickly assess if our ordered pair satisfies the inequality.
By working through the steps, we systematically determine if \( y \) is indeed greater than the calculated result on the right side. This method is a direct way to check solutions, especially with inequalities.
\[100 > 3(-6)^2 + 50(-6) + 500\]
This substitution helps us quickly assess if our ordered pair satisfies the inequality.
By working through the steps, we systematically determine if \( y \) is indeed greater than the calculated result on the right side. This method is a direct way to check solutions, especially with inequalities.
Simplification Process
The simplification process involves breaking down equations to make comparisons easier. After substituting values, we have:
\[100 > 3 \times 36 - 300 + 500\]
Simplify step-by-step to ensure clarity and accuracy:
Finally, compare \(100 > 308\). As 100 is not greater, the ordered pair is not a solution.
Simplification is key in solving mathematical problems as it helps verify the accuracy of potential solutions.
\[100 > 3 \times 36 - 300 + 500\]
Simplify step-by-step to ensure clarity and accuracy:
- Perform multiplication: \( 3 \times 36 = 108 \)
- Add and subtract in sequence: \( 108 - 300 = -192 \) and \(-192 + 500 = 308 \)
Finally, compare \(100 > 308\). As 100 is not greater, the ordered pair is not a solution.
Simplification is key in solving mathematical problems as it helps verify the accuracy of potential solutions.
Other exercises in this chapter
Problem 45
Simplify the expression. $$\frac{\sqrt{3}}{\sqrt{3}-1}$$
View solution Problem 45
Solve the equation by completing the square. $$5 x^{2}-20 x-20=5$$
View solution Problem 46
Solve the equation. Check for extraneous solutions. $$\frac{1}{5} x=\sqrt{x-6}$$
View solution Problem 46
Find the domain and the range of the function. Then sketch the graph of the function. $$y=4 \sqrt{x}$$
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