Problem 46
Question
A ladder 20 feet long leans against the side of a building, and the angle between the ladder and the building is \(22^{\circ}\) (a) Approximate the distance from the bottom of the ladder to the building. (b) If the distance from the bottom of the ladder to the building is increased by 3.0 feet, approximately how far does the top of the ladder move down the building?
Step-by-Step Solution
Verified Answer
(a) 18.544 feet, (b) 0.231 feet.
1Step 1: Understanding the Problem
The ladder forms a right triangle with the building and the ground. The ladder itself is the hypotenuse of this triangle, the distance from the ladder base to the building is the adjacent side, and the angle formed between the ladder and the building is given.
2Step 2: Apply the Cosine Formula
To find the distance from the bottom of the ladder to the building (the adjacent side), apply the cosine formula: \[\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}\]Plugging in the known values:\[\cos(22^\circ) = \frac{x}{20}\]where \(x\) is the distance from the bottom of the ladder to the building.
3Step 3: Solve for Adjacent Side
Rearrange the equation from Step 2 to solve for \(x\):\[x = 20 \times \cos(22^\circ)\]Calculate using a calculator: \[x \approx 20 \times 0.9272 \approx 18.544 ext{ feet}\]So, the distance from the bottom of the ladder to the building is approximately 18.544 feet.
4Step 4: Consider the Increase in Distance
If the distance from the bottom of the ladder to the building is increased by 3 feet, the new distance \(x'\) is:\[x' = 18.544 + 3 = 21.544 ext{ feet}\]This will change the angle of elevation of the ladder.
5Step 5: Recalculate the Height with Increased Distance
Now, use the Pythagorean theorem to find the new height \(y'\) when the distance from the bottom is 21.544 feet:\[\text{hypotenuse}^2 = (\text{opposite})^2 + (\text{adjacent})^2\]\[20^2 = (y')^2 + 21.544^2\]Solve for \(y'\):\[(y')^2 = 400 - 464.556\]\[y' = \sqrt{400 - 464.556} \approx \sqrt{335.444} \approx 18.313 ext{ feet}\]
6Step 6: Calculate the Change in Height
The change in height is the original height minus the new height:\[18.544 - 18.313 = 0.231 ext{ feet}\]So, the top of the ladder moves down approximately 0.231 feet.
Key Concepts
Cosine FunctionRight TrianglePythagorean Theorem
Cosine Function
The cosine function is a fundamental concept in trigonometry that relates the angles and sides of a right triangle. In our exercise, the cosine function helps us determine the distance from the base of the ladder to the building. We use the following formula to work it out: \[ \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \]Here:
- \( \theta \) is the angle between the ladder and the building, given as \( 22^{\circ} \).
- The hypotenuse is the length of the ladder, which is 20 feet.
- The adjacent side is the distance we need to find to the building from the ladder's base.
Right Triangle
Right triangles are unique because they include a 90-degree angle, which allows us to use specific trigonometric functions like sine, cosine, and tangent to solve for unknown sides and angles.
In this scenario, the ladder, ground, and the side of the building form a right triangle:
- The ladder acts as the hypotenuse, the longest side that is opposite the right angle.
- The adjacent side, which we've calculated using the cosine function, is the distance from the base of the ladder to the building.
- The opposite side is the height on the building where the ladder touches.
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in mathematics for dealing with right triangles. It states:\[ a^2 + b^2 = c^2 \]Where:
- \( a \) and \( b \) are the lengths of the triangle's shorter sides, referred to as legs.
- \( c \) is the length of the hypotenuse, the longest side.
Other exercises in this chapter
Problem 45
Find the period and sketch the graph of the equation. Show the asymptotes. $$y=2 \csc \left(2 x+\frac{\pi}{2}\right)$$
View solution Problem 46
Exer. \(45-46:\) A wheel of the given radius is rotating at the indicated rate. (a) Find the angular speed (in radians per minute). (b) Find the linear speed of
View solution Problem 46
Refer to the graph of \(y=\sin x\) or \(y=\cos x\) to find the exact values of \(x\) in the interval \([0,4 \pi]\) that satisfy the equation. $$\cos x=-\frac{1}
View solution Problem 46
Use fundamental Identities to write the first expression in terms of the second, for any acute angle \(\boldsymbol{\theta}\). $$\csc \theta, \cos \theta$$
View solution