Problem 45
Question
Write each logarithm as the sum and/or difference of logarithms of a single quantity. Then simplify, if possible. See Example 4. $$ \log \frac{10 x}{y} $$
Step-by-Step Solution
Verified Answer
\( 1 + \log x - \log y \)
1Step 1: Apply the Quotient Rule
The logarithm of a fraction can be expressed as the difference of the logarithms of the numerator and the denominator. For the expression \( \log \frac{10x}{y} \), use the quotient rule: \[ \log \frac{a}{b} = \log a - \log b \]. This results in: \[ \log (10x) - \log y \].
2Step 2: Apply the Product Rule
Now, consider \( \log (10x) \). The logarithm of a product can be expressed as the sum of the logarithms. For \( \log (10x) \), apply the product rule: \[ \log (ab) = \log a + \log b \]. This gives: \[ \log 10 + \log x \].
3Step 3: Combine the Expressions
Substitute \( \log (10x) = \log 10 + \log x \) into the earlier expression from Step 1 so that the expression becomes: \[ \log 10 + \log x - \log y \].
4Step 4: Simplify the Expression
Since \( \log 10 \) is a known value (equal to 1), substitute this into the expression: \[ 1 + \log x - \log y \]. This is the simplified form of the original logarithmic expression.
Key Concepts
Understanding the Quotient RuleDiving into the Product RuleMastering Simplification of Expressions
Understanding the Quotient Rule
The quotient rule is an essential tool in working with logarithms. When you have the logarithm of a fraction, you can break it down into a simpler form using the difference of two logarithms. This helps make calculations easier to handle. Consider the expression \( \log \frac{10x}{y} \). Here, you are working with a fraction where 10x is the numerator and y is the denominator.
Using the quotient rule, we can rewrite this as:
Using the quotient rule, we can rewrite this as:
- \( \log \frac{a}{b} = \log a - \log b \)
Diving into the Product Rule
The product rule is another vital part of simplifying logarithmic expressions. It allows you to take the logarithm of a product and express it as a sum of logarithms. Working with sum terms is typically more convenient, especially when simplifying expressions.
For the term \( \log (10x) \) from the expression \( \log (10x) - \log y \), apply the product rule to separate it further:
For the term \( \log (10x) \) from the expression \( \log (10x) - \log y \), apply the product rule to separate it further:
- \( \log (ab) = \log a + \log b \)
Mastering Simplification of Expressions
Simplification is the key to making complex expressions more manageable. Once you break down the problem using the quotient and product rules, the next step is to refine the expression. In our example, after applying these rules, we obtained:
\( \log 10 + \log x - \log y \).
This expression is almost complete, but there's one more simplification left. We know the value of \( \log 10 \) due to common logarithmic properties. Since \( \log 10 \) equals 1 when the base of the logarithm is 10, you can substitute it directly:
\( \log 10 + \log x - \log y \).
This expression is almost complete, but there's one more simplification left. We know the value of \( \log 10 \) due to common logarithmic properties. Since \( \log 10 \) equals 1 when the base of the logarithm is 10, you can substitute it directly:
- \( 1 + \log x - \log y \)
Other exercises in this chapter
Problem 44
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