Problem 45
Question
What effect does doubling the initial concentration of a reactant have on the half-life in a reaction that is second order in the reactant?
Step-by-Step Solution
Verified Answer
Answer: Doubling the initial concentration of a reactant in a second-order reaction will cause the half-life to decrease by half.
1Step 1: Write the rate law for a second-order reaction
For a second-order reaction, the rate law is given by:
Rate = k[A]²
where Rate is the reaction rate, k is the rate constant, and [A] is the concentration of the reactant A.
2Step 2: Write the integrated rate law for a second-order reaction
To find the integrated rate law, we need to integrate the rate law with respect to time. For second-order reactions, the integrated rate law is:
1/[A] - 1/[A]₀ = kt
where [A]₀ is the initial concentration of the reactant A, [A] is the concentration at time t and k is the rate constant.
3Step 3: Derive the half-life formula for a second-order reaction
Half-life (t₁/₂) is the time it takes for the concentration of a reactant to fall to half its initial value. Thus, at t = t₁/₂, [A] = [A]₀ / 2. We can substitute this into the integrated rate law equation to derive the half-life formula:
1/([A]₀/2) - 1/[A]₀ = kt₁/₂
4Step 4: Simplify the half-life formula and solve for t₁/₂
Now we will simplify the half-life formula:
2/[A]₀ - 1/[A]₀ = kt₁/₂
1/[A]₀ = kt₁/₂
t₁/₂ = 1/(k[A]₀)
The half-life formula is:
t₁/₂ = 1/(k[A]₀)
5Step 5: Analyze the effect of doubling the initial concentration on half-life
Now, let's see how the half-life changes when we double the initial concentration:
Original half-life: t₁/₂ = 1/(k[A]₀)
New half-life with doubled initial concentration: t₁/₂' = 1/(k(2[A]₀))
t₁/₂' = 1/(2k[A]₀)
Comparing the original half-life with the new half-life after doubling the initial concentration, we see that:
t₁/₂' = (1/2)t₁/₂
Thus, doubling the initial concentration of a reactant in a second-order reaction will cause the half-life to decrease by half.
Key Concepts
Rate LawIntegrated Rate LawHalf-LifeReaction Kinetics
Rate Law
In chemical kinetics, the rate law is a mathematical equation that describes the rate of a chemical reaction. For second-order reactions, the rate law takes the form:
- Rate = k[A]²
Integrated Rate Law
The integrated rate law combines the information from the rate law to describe how reactant concentrations change with time. For a second-order reaction, it is derived by integrating the rate law equation:
- 1/[A] - 1/[A]₀ = kt
Half-Life
The half-life of a reaction helps determine how long it takes for the concentration of a reactant to reduce to half its initial amount. For second-order reactions, the half-life formula is:
- t₁/₂ = 1/(k[A]₀)
Reaction Kinetics
Reaction kinetics involves the study of the speeds of chemical processes and how they change under different conditions. In second-order reactions, kinetics explores how variations in reactant concentration and other factors affect the rate and overall progress of a reaction.
- Factors such as temperature, concentration, and catalysts play a significant role in reaction kinetics.
- Kinetics provides a detailed map of how a reaction proceeds over time.
Other exercises in this chapter
Problem 43
Can the half-life of a second-order reaction have the same units as the half- life of a first-order reaction?
View solution Problem 44
How does the half-life in a first-order reaction depend on the concentration of the reactants?
View solution Problem 46
Two first-order decomposition reactions of the form \(A \rightarrow B+C\) have the same rate constant at a given temperature. Do the reactants in the two reacti
View solution Problem 47
For each of the following rate laws, determine the order with respect to each reactant and the overall reaction order. a. Rate \(=k[\mathrm{A}][\mathrm{B}]\) b.
View solution