Problem 45
Question
Use identities to write each equation in terms of the single angle \(\theta .\) Then solve the equation for \(0 \leq \theta<2 \pi .\) $$ \cos 2 \theta=-2 \cos ^{2} \theta $$
Step-by-Step Solution
Verified Answer
The solutions are \( \theta = \pi/3, 2 \pi/3, 4 \pi/3, 5 \pi/3 \).
1Step 1: Use the Double-Angle Identity for Cosine
The double-angle identity for cosine is \( \cos 2 \theta = 1 - 2 \sin^2 \theta \) or \( \cos 2 \theta = 2 \cos^2 \theta - 1 \). For this exercise, the second form of the identity makes the equation easier to solve. So, rewrite the equation using the identity \( \cos 2 \theta = 2 \cos^2 \theta - 1 \), you have: \( 2 \cos^2 \theta - 1 = -2 \cos ^2\theta \).
2Step 2: Simplify the equation
Combine like terms to simplify the equation. Add \( 2 \cos ^2\theta \) to both sides to get \( 4 \cos^2 \theta = 1 \). Then, divide by 4 to isolate \( \cos^2 \theta \) which gives: \( \cos^2 \theta = \frac{1}{4} \).
3Step 3: Use the identity for Cosine Squared
The identity for \( \cos^2 \theta \) is \( \cos \theta = \pm \sqrt{\cos^2 \theta} \). Therefore, \( \cos \theta = \pm \frac{1}{2} \).
4Step 4: Solve for theta
Using the unit circle or cosine table, solve for \( \theta \) where \( 0 \leq \theta < 2 \pi \). The solutions are \( \theta = \pi/3, 5 \pi/3 \) for \( \cos \theta = 1/2 \) and \( \theta = 2 \pi/3, 4 \pi/3 \) for \( \cos \theta = -1/2 \).
Key Concepts
Double-Angle IdentityCosine FunctionUnit CircleAngle Solving
Double-Angle Identity
The double-angle identity is a trigonometric formula that helps simplify expressions where angles are doubled. In the context of the cosine function, it allows us to express \( \cos 2\theta \) in two main forms:
- \( \cos 2\theta = 1 - 2 \sin^2 \theta \)
- \( \cos 2\theta = 2 \cos^2 \theta - 1 \)
Cosine Function
The cosine function, denoted as \( \cos \theta \), is one of the fundamental trigonometric functions. It relates the angle \( \theta \) to the x-coordinate of a point on the unit circle. Specifically, the cosine of any angle \( \theta \) is the horizontal distance from the origin to the point on the unit circle at angle \( \theta \).
This function is periodic, with a period of \( 2\pi \), meaning it repeats its values every \( 2\pi \) radians. This periodic nature is vital when solving trigonometric equations, as it helps identify all possible solutions within a specified interval. In this exercise, recognizing that \( \cos(\theta) = \pm 1/2 \) allows us to explore multiple angles within a \( 0 \leq \theta < 2\pi \) range.
This function is periodic, with a period of \( 2\pi \), meaning it repeats its values every \( 2\pi \) radians. This periodic nature is vital when solving trigonometric equations, as it helps identify all possible solutions within a specified interval. In this exercise, recognizing that \( \cos(\theta) = \pm 1/2 \) allows us to explore multiple angles within a \( 0 \leq \theta < 2\pi \) range.
Unit Circle
The unit circle is a circle with a radius of one. It's a powerful tool for visualizing and understanding trigonometric functions like sine and cosine. Each point on the unit circle corresponds to an angle \( \theta \), with the coordinates \((\cos \theta, \sin \theta)\) giving the cosine and sine values for that angle.
To solve the equation using the unit circle, we identify angles that produce specific cosine values, such as \( \cos \theta = \frac{1}{2} \) and \( \cos \theta = -\frac{1}{2} \). For these values, common angles are \( \theta = \pi/3, 5\pi/3, 2\pi/3, \) and \( 4\pi/3 \). By referencing these locations on the unit circle, we find all solutions within one full cycle of \( 0 \leq \theta < 2\pi \).
To solve the equation using the unit circle, we identify angles that produce specific cosine values, such as \( \cos \theta = \frac{1}{2} \) and \( \cos \theta = -\frac{1}{2} \). For these values, common angles are \( \theta = \pi/3, 5\pi/3, 2\pi/3, \) and \( 4\pi/3 \). By referencing these locations on the unit circle, we find all solutions within one full cycle of \( 0 \leq \theta < 2\pi \).
Angle Solving
Solving for angles in trigonometric equations involves identifying all possible solutions within a given interval. It requires a clear understanding of how angles on the unit circle translate to specific trigonometric values.
- First, use identities to express the equation in a simpler form.
- Second, determine the trigonometric values for which the equation holds true.
- Finally, identify all angles that produce these trigonometric values within the specified interval.
Other exercises in this chapter
Problem 44
Writing Suppose you know the measures of all three angles of a triangle. Can you use the Law of Sines to find the lengths of the sides? Explain.
View solution Problem 44
Express the first trigonometric function in terms of the second. $$ \sec \theta, \tan \theta $$
View solution Problem 45
In \(\Delta R S T, t=7 \mathrm{ft}\) and \(s=13 \mathrm{ft}\) . Find each value to the nearest tenth. Find \(m \angle S\) for \(m \angle R=87^{\circ}\)
View solution Problem 45
Rewrite each expression as a trigonometric function of a single angle measure. $$ \sin 3 \theta \cos 2 \theta+\cos 3 \theta \sin 2 \theta $$
View solution