Problem 45
Question
This set of exercises will draw on the ideas presented in this section and your general math background. One of the zeros of a certain quadratic polynomial with real coefficients is \(1+i .\) What is its other zero?
Step-by-Step Solution
Verified Answer
The other zero of the quadratic polynomial is \(1 - i .\)
1Step 1: Understanding the problem
Given that one of the zeros of a quadratic polynomial with real coefficients is \(1+i .\) A root of a polynomial is a value which when substituted into the polynomial, results in zero. Here, we are dealing with complex roots. And for quadratic polynomials with real coefficients, if one root is a complex number, then the other root is its conjugate. A conjugate of a complex number is obtained by changing the sign of its imaginary part.
2Step 2: Find the conjugate
The given root is a complex number \(1+i .\) So, its conjugate will be obtained by negating the imaginary part. The conjugate is therefore \(1-i .\)
3Step 3: Validate the result
The conjugate is obtained by changing the sign of the imaginary part of the given root which is \(1+i .\) The conjugate is \(1-i .\) It is known that if an equation has real coefficients and if a complex number is one root of that equation, then its conjugate will be another root. Therefore, \(1-i .\) is indeed the other zero of the quadratic polynomial.
Key Concepts
complex numbersconjugates in polynomialspolynomial roots
complex numbers
Complex numbers are a fascinating extension of the familiar real numbers, adding a whole new dimension to mathematical calculations. They're numbers that include a real part and an imaginary part. The standard form is written as
- \(a + bi\), where \(a\) is the real part and \(bi\) is the imaginary part.
- For instance, solving \(x^2 + 1 = 0\) yields \(x = i\) and \(x = -i\).
conjugates in polynomials
In the world of complex numbers, "conjugate" has a very specific meaning. For any complex number \(a + bi\), its conjugate is \(a - bi\). This is achieved by simply changing the sign of the imaginary part without touching the real part. Conjugates play a special role in polynomials, particularly those with real coefficients. When a polynomial has real coefficients, and one of its roots is complex, the other root must be the conjugate. This means:
- If \(1 + i\) is a root, \(1 - i\) must also be a root.
polynomial roots
The roots of a polynomial are the values that solve the polynomial equation, that is, where the polynomial evaluates to zero. For example, the roots of the quadratic polynomial \(x^2 + 2x + 1\) are the solutions to the equation \(x^2 + 2x + 1 = 0\).When dealing with quadratic polynomials, there are several possibilities for the roots:
- Both roots can be real and distinct, like in \(x^2 - 5x + 6 = 0\) with roots \(2\) and \(3\).
- The roots can be real and identical, known as repeated roots; for instance, \(x^2 - 4x + 4 = 0\) has root \(2\) twice.
- Roots can also be complex numbers. For real coefficients, these complex roots will be conjugates of each other.
Other exercises in this chapter
Problem 45
Use Descartes' Rule of Signs to determine the number of positive and negative zeros of \(p\). You need not find the zeros. $$p(x)=-2 x^{3}+x^{2}-x+1$$
View solution Problem 45
Sketch a graph of the rational function. Indicate any vertical and horizontal asymptote(s) and all intercepts. $$f(x)=\frac{3 x^{2}}{x^{2}-x-2}$$
View solution Problem 45
For what value(s) of \(k\) do you get a remainder of -2 when you divide \(x^{3}-x^{2}+k x+3\) by \(x+1 ?\)
View solution Problem 45
Find an expression for a polynomial function \(f(x)\) having the given properties. There can be more than one correct anstoer. Degree 5 ; zeros at -2 and \(-1,\
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