Problem 45
Question
Suppose that \(y\) varies directly as the square of \(x\). Does doubling the value of \(x\) also double the value of \(y\) ? Explain your answer.
Step-by-Step Solution
Verified Answer
No, doubling \( x \) quadruples \( y \), not doubles it.
1Step 1: Define Direct Variation
To solve the problem, first recognize that direct variation as a square means the relationship between two variables can be expressed as \( y = kx^2 \), where \( k \) is a constant.
2Step 2: Analyze the Effect of Doubling x
Now, suppose the value of \( x \) is doubled. The new value of \( x \) becomes \( 2x \). Substitute \( 2x \) into the equation \( y = kx^2 \), giving us \( y = k(2x)^2 \).
3Step 3: Simplify the Expression
Simplify \( y = k(2x)^2 \): \[ y = k(4x^2) = 4(kx^2) \] This shows that when \( x \) is doubled, \( y \) is multiplied by 4.
4Step 4: Conclude the Relationship
The expression \( y = 4(kx^2) \) shows that \( y \) becomes four times its original value, not double. Therefore, doubling \( x \) does not double \( y \); it quadruples it.
Key Concepts
Relationship Between VariablesQuadratic RelationshipProportionality Constant
Relationship Between Variables
In mathematics, direct variation describes a specific type of relationship between two variables where one variable is directly proportional to a function of another variable. This means that the value of one variable changes in direct relation to the other. For example, when variable \( x \) increases, variable \( y \) will also increase, provided they are directly related. In our exercise, we are given that \( y \) varies directly with the square of \( x \), which is expressed by the formula \( y = kx^2 \). Here, \( k \) is a constant that remains the same regardless of the values of \( x \) or \( y \). This highlights how changes in \( x \) influence changes in \( y \) consistently, following the equation.
Quadratic Relationship
A quadratic relationship is a type of polynomial relationship, specifically one where the highest exponent of the variable is 2. This is different from linear relationships (with their straight line graphs), as a quadratic relationship will form a parabolic curve when graphed. In the equation \( y = kx^2 \), the variable \( x \) is squared, representing a quadratic relationship between \( x \) and \( y \). If we double the value of \( x \) and substitute it into the equation, \( y = k(2x)^2 = k(4x^2) \). The simplification shows that \( y \) changes in a way that corresponds to the square of the scaling factor of \( x \), leading \( y \) to become four times larger rather than simply doubling. This illustrates the significant impact a quadratic relationship can have on the values of the involved variables.
Proportionality Constant
In the equation \( y = kx^2 \), the term \( k \) is known as the proportionality constant. It serves a crucial role in the relationship between \( x \) and \( y \). This constant determines the rate at which \( y \) changes as \( x \) changes. It effectively scales the value of \( x^2 \) to match the value of \( y \).Regardless of the value of \( x \), \( k \) remains unchanged, signifying that it provides a direct measure of how \( x \) and \( y \) are proportionally related. For instance, in our scenario, knowing \( k \) allows us to predict how \( y \) will change if \( x \) is altered. This constancy of \( k \) is what makes calculating potential changes in \( y \) straightforward when modifications to \( x \) occur, such as doubling \( x \), to determine that \( y \) becomes four times its original value.
Other exercises in this chapter
Problem 44
Use quadratic functions. Find two numbers whose sum is 50 and whose product is a maximum.
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If \(f(x)=\sqrt{x-1}\), find \(f(1), f(5), f(13)\), and \(f(26)\).
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(a) find the inverse of the given function, and (b) graph the given function and its inverse on the same set of axes. (Objective 4) $$f(x)=3 x-3$$
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Graph each of the functions. $$f(x)=\frac{x-1}{x}$$
View solution