Problem 45
Question
Solve the inequality and sketch the solution on the real number line. Use a graphing utility to verify your solutions graphically. $$10|1-x|<5$$
Step-by-Step Solution
Verified Answer
The solution to the inequality \(10|1-x|<5\) is 0.5 <= x <= 1.5.
1Step 1: Simplify the inequality
Firstly, we want to simplify the inequality by isolating the absolute value term. To do this, we divide both sides by 10 to result in \(|1-x|<0.5\).
2Step 2: Write positive and negative equations
Remembering the definition of absolute value, we set up two equations to solve, one for the positive equivalence and the other for the negative, resulting in two inequalities 1 - x = 0.5 (where we assume x < 1) and 1 - x = -0.5 (where we assume x > 1).
3Step 3: Solve both inequalities
Solving the inequalities (1-x = 0.5 and 1 - x = -0.5) respectively gives two solutions x = 0.5, and x = 1.5.
4Step 4: Check and confirm the solutions
We then confirm the solutions by substituting these values for x back into the original inequality. For values 0.5<= x <=1.5, the inequality \(|1-x|<0.5\) holds true.
5Step 5: Graphically confirm the solutions
To graphically confirm the solution, plot the line y = 1 - x (the absolute value has been omitted for simplicity) and the line y = 0.5 in the same graph. The region between these two lines represents the solutions. In a graphing utility, the x-values where y = 0.5 is below y = 1 - x coincide with the solution interval identified previously, confirming the solution.
6Step 6: Final Solution
Therefore, the solution for the inequality \(10|1-x|<5\) is 0.5 <= x <= 1.5.
Key Concepts
Absolute Value InequalityReal Number LineGraphing UtilityInterval Notation
Absolute Value Inequality
An absolute value inequality involves an expression within an absolute value bracket, indicating how far a number is from zero on the number line. In this case, we are working with the inequality \( |1-x| < 0.5 \). The absolute value notation \(|...|\) means you consider both positive and negative scenarios. Hence, solving \( |1-x| < 0.5 \) requires solving two different inequalities:
- \( 1-x < 0.5 \)
- \( 1-x > -0.5 \)
Real Number Line
The real number line is a straight line that represents all possible real numbers. In mathematics, this concept is used to visually represent solutions to inequalities. For the inequality \( 10|1-x|<5 \), the solution represents all values of \(x\) that satisfy the condition when plotted on this line.
Here's how you do it:
Here's how you do it:
- You solve the inequality to get the range of solutions (\(0.5 \leq x \leq 1.5\)).
- Plot these values on the number line.
Graphing Utility
A graphing utility is a tool, such as a graphing calculator or computer software, which helps visualize mathematical equations and their solutions. For the inequality \(10|1-x|<5\), a graphing utility can plot the function \(y = |1-x|\) and the line \(y = 0.5\) (after simplifying the inequality to \(|1-x|<0.5\)).
By graphing these, you seek the intervals where the graph of \(y = |1-x|\) is below the horizontal line \(y = 0.5\). This visual check confirms the solution range we found algebraically (\(0.5 \leq x \leq 1.5\)). Graphing utilities are powerful for verifying the accuracy of your algebraic solutions.
By graphing these, you seek the intervals where the graph of \(y = |1-x|\) is below the horizontal line \(y = 0.5\). This visual check confirms the solution range we found algebraically (\(0.5 \leq x \leq 1.5\)). Graphing utilities are powerful for verifying the accuracy of your algebraic solutions.
Interval Notation
Interval notation is a succinct way of describing ranges of valid solutions. For the inequality \(10|1-x|<5\), once solved, we find the solution in terms of \(x\) to be between 0.5 and 1.5, inclusive. In interval notation, this is expressed as \([0.5, 1.5]\).
Here's how interval notation works:
Here's how interval notation works:
- Brackets \([\cdot, \cdot]\) are used to include the endpoints of the interval, indicating that they are part of the solution.
- If endpoints were not included, parentheses \((\cdot, \cdot)\) would be used.
Other exercises in this chapter
Problem 44
Perform the operation and write the result in standard form. $$(5-4 i)^{2}$$
View solution Problem 45
Solving an Equation Involving Rational Exponents Find all solutions of the equation algebraically. Check your solutions. $$3 x(x-1)^{1 / 2}+2(x-1)^{3 / 2}=0$$
View solution Problem 45
Solve the quadratic equation by completing the square. Verify your answer graphically. $$2 x^{2}+5 x-8=0$$
View solution Problem 45
Use a graphing utility to approximate any solutions of the equation. [Remember to write the equation in the form \(f(x)=0.1\) $$2 x^{3}-x^{2}-18 x+9=0$$
View solution