Problem 45
Question
Solve for \(x\) and \(y\). $$2\left[\begin{array}{cc}x & y \\ x+y & x-y\end{array}\right]=\left[\begin{array}{rr}2 & -4 \\ -2 & 6\end{array}\right]$$
Step-by-Step Solution
Verified Answer
\(x = 1\) and \(y = -2\).
1Step 1: Understand the Equation
The provided matrix equation is \( 2\begin{bmatrix}x & y \ x+y & x-y \end{bmatrix} = \begin{bmatrix}2 & -4 \ -2 & 6 \end{bmatrix} \). We need to solve for \(x\) and \(y\) such that both matrices are equal.
2Step 2: Equate Elements of the Matrices
For two matrices to be equal, their corresponding elements must be equal. So, from the equation \( 2\begin{bmatrix}x & y \ x+y & x-y \end{bmatrix} = \begin{bmatrix}2 & -4 \ -2 & 6 \end{bmatrix} \), we get:1. \(2x = 2\)2. \(2y = -4\)3. \(2(x+y) = -2\)4. \(2(x-y) = 6\)
3Step 3: Solve the First Pair
Solve the equations \(2x = 2\) and \(2y = -4\) to find \(x\) and \(y\).- Dividing the first equation by 2: \[x = \frac{2}{2} = 1\]- Dividing the second equation by 2: \[y = \frac{-4}{2} = -2\]
4Step 4: Verify with the Remaining Conditions
Substitute \(x = 1\) and \(y = -2\) into the remaining equations to verify the solution:- For \(2(x+y) = -2\): \[2(1 + (-2)) = 2(-1) = -2 \text{ (True)}\]- For \(2(x-y) = 6\): \[2(1 - (-2)) = 2(3) = 6 \text{ (True)}\]
5Step 5: Conclude the Solution
Since both conditions are met and all calculations check out, the solution to the matrix equation is \( x = 1 \) and \( y = -2 \).
Key Concepts
Solving Systems of EquationsMatrix EqualityPrecalculus
Solving Systems of Equations
When tackling systems of equations, we seek values for variables that simultaneously satisfy multiple equations. In the realm of matrices, this concept extends naturally. Here, we engage with a system represented not just by equations but by matrices. The goal is to find the right values of our variables that make each matrix element pair equal. For instance, given a matrix equation:\[2\begin{bmatrix}x & y\x+y & x-y\end{bmatrix} = \begin{bmatrix}2 & -4\-2 & 6\end{bmatrix}\]To find solutions for \(x\) and \(y\), break the task into smaller parts based on matrix cells:
- Solve \(2x = 2\) to find \(x\)
- Solve \(2y = -4\) to find \(y\)
- Check with \(2(x+y) = -2\) and \(2(x-y) = 6\)
Matrix Equality
Matrix equality is a straightforward yet powerful concept. Two matrices are considered equal when all of their corresponding elements are identical. Consequently, this principle allows us to derive relationships between unknowns within a mathematical or real-world context from matrix representations.Consider the current problem's matrices:\[2\begin{bmatrix}x & y\x+y & x-y\end{bmatrix} = \begin{bmatrix}2 & -4\-2 & 6\end{bmatrix}\]We equate corresponding elements:
- First row, first column: \(2x = 2\)
- First row, second column: \(2y = -4\)
- Second row, first column: \(2(x+y) = -2\)
- Second row, second column: \(2(x-y) = 6\)
Precalculus
Precalculus typically serves as the foundation for calculus, involving a range of mathematical concepts, including functions, series, and, crucially, matrices. In this context, matrices aren't simply static collections of numbers; they're dynamic tools that model systems encountered in calculus and beyond.
Matrix equations interconnect different areas of precalculus—like algebra and geometry—by offering a structured way to solve multiple equations simultaneously. In preparation for calculus, students learn to:
- Manipulate matrices similar to arithmetic operations
- Solve matrix equations as in algebraic contexts
- Apply matrix equality properties across varied problems
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