Problem 45
Question
Solve each inequality. Check your solution. $$ 3^{n-2}>27 $$
Step-by-Step Solution
Verified Answer
The solution is \(n > 5\).
1Step 1: Express 27 as a Power of 3
The goal is to express the number 27 as a power of 3. Since \(27 = 3^3\), the inequality \(3^{n-2} > 27\) becomes \(3^{n-2} > 3^3\).
2Step 2: Simplify the Exponent Inequality
Since the bases are the same (both are 3), we can simplify the inequality by comparing the exponents: \(n-2 > 3\).
3Step 3: Solve for n
Solve the equation \(n-2 > 3\) by adding 2 to both sides of the inequality: \(\begin{align*}n-2 &> 3 &> 5\end{align*}\)
4Step 4: Check the Solution
Choose a value for \(n\) that is greater than 5 and plug it back into the original inequality to verify. For example, let \(n = 6\). Then \(3^{6-2} = 3^4 = 81\) and since \(81 > 27\), our solution is verified.
Key Concepts
Exponent RulesSolving InequalitiesChecking SolutionsAlgebraic Expressions
Exponent Rules
Exponents represent repeated multiplication. For example, when we see a number like \(3^4\), it means we are multiplying 3 by itself four times: \(3 \times 3 \times 3 \times 3\). Understanding exponent rules can simplify our mathematical tasks. There are several key exponent rules:
- **Product of Powers Rule**: \(a^m \times a^n = a^{m+n}\).
- **Quotient of Powers Rule**: \( \frac{a^m}{a^n} = a^{m-n} \) when \(a eq 0\).
- **Power of a Power Rule**: \((a^m)^n = a^{m \cdot n}\).
- **Zero Exponent Rule**: \(a^0 = 1\) when \(a eq 0\).
- **Negative Exponent Rule**: \(a^{-n} = \frac{1}{a^n}\).
Solving Inequalities
Solving inequalities is similar to solving equations, but with one key difference: inequalities express a relationship of greater than or less than between expressions. Here’s how you solve a simple inequality:
- **Isolate the variable**: Just like in an equation, you often start by isolating the variable on one side.
- **Perform the same operation on both sides**: You can add, subtract, multiply, or divide both sides of the inequality by the same number (just be careful with multiplication or division by negative numbers; this reverses the inequality symbol).
Checking Solutions
After solving an inequality, it’s crucial to check your solution to ensure it’s correct. Verification helps to confirm the result is accurate, and it follows these steps:
- **Choose a test value**: Select a number greater than the found solution. In the example, if \(n > 5\), take \(n = 6\) for verification.
- **Substitute back into the original inequality**: Substitute the chosen test value back into the original inequality to see if the statement holds true.
- **Evaluate the result**: If the inequality holds true with your test value, your solution is likely correct.
Algebraic Expressions
Algebraic expressions consist of variables, numbers, and operation symbols that represent a mathematical relationship. They are a key part of many types of math problems, including inequalities like the one in our example. Here’s a breakdown of key concepts:
- **Variables**: Symbols used to represent unknown values. In our example, \(n\) is the variable.
- **Constants**: Known numbers in the expression, like 3 and 27 in the inequality.
- **Operations**: Include addition, subtraction, multiplication, and division.
Understanding these components helps in creating, simplifying, and solving expressions effectively.
Other exercises in this chapter
Problem 45
Solve each equation. Round to four decimal places. $$ 2^{x^{2}-3}=15 $$
View solution Problem 45
Solve each equation. Check your solutions. \(\log _{25} n=\frac{3}{2}\)
View solution Problem 46
REASONING Use the properties of Logarithms to prove that \(\log _{a} \frac{1}{x}=-\log _{a} x\)
View solution Problem 46
Solve each equation. Round to four decimal places. $$ 2^{2 x+3}=3^{3 x} $$
View solution