Problem 45
Question
Show that \(\lim _{t \rightarrow a} \mathbf{r}(t)=\mathbf{b}\) if and only if for every \(\varepsilon>0\) there is a number \(\delta>0\) such that if $$0<|t-a|<\delta\( then \)|\mathbf{r}(t)-\mathbf{b}|<\varepsilon$$
Step-by-Step Solution
Verified Answer
The limit definition is satisfied: \\( \lim_{t \rightarrow a} \mathbf{r}(t) = \mathbf{b} \\\) if and only if for every \\( \varepsilon > 0 \\\), there exists \\( \delta > 0 \\\) such that \\( 0<|t-a|<\delta \\\) implies \\( |\mathbf{r}(t)-\mathbf{b}|<\varepsilon \\\).
1Step 1: Understand the Limit Definition
The limit definition states that the limit of a function \( \mathbf{r}(t) \) as \( t \) approaches \( a \) is equal to \( \mathbf{b} \) if for every \( \varepsilon > 0 \), there exists a corresponding \( \delta > 0 \) such that whenever \( 0 < |t - a| < \delta \), it follows that \( |\mathbf{r}(t) - \mathbf{b}| < \varepsilon \). We need to prove this bidirectional implication.
2Step 2: Prove the 'If' Direction
Assume that \( \lim_{t \rightarrow a} \mathbf{r}(t) = \mathbf{b} \). By definition, for every \( \varepsilon > 0 \), there exists a \( \delta > 0 \) such that if \( 0 < |t-a| < \delta \), then the condition \( |\mathbf{r}(t) - \mathbf{b}| < \varepsilon \) is satisfied. This directly fulfills the given condition of the limit definition, confirming the 'if' portion of the statement.
3Step 3: Prove the 'Only If' Direction
Next, assume that for every \( \varepsilon > 0 \), there exists a \( \delta > 0 \) ensuring \( 0 < |t-a| < \delta \) implies \( |\mathbf{r}(t) - \mathbf{b}| < \varepsilon \). This matches the condition needed for \( \lim_{t \rightarrow a} \mathbf{r}(t) = \mathbf{b} \) according to the standard \( \varepsilon-\delta \) definition of limits. Therefore, this assumption implies that \( \lim_{t \rightarrow a} \mathbf{r}(t) = \mathbf{b} \), proving the 'only if' portion.
4Step 4: Conclusion
Both directions have been proved: 1) Assuming the limit exists leads to the \( \varepsilon-\delta \) condition, and 2) Assuming the \( \varepsilon-\delta \) condition leads to the existence of the limit. Thus, this is an 'if and only if' statement, establishing that the conditions are equivalent as required.
Key Concepts
Understanding Limits in CalculusExploring Vector-Valued FunctionsConceptualizing Continuity
Understanding Limits in Calculus
A limit in calculus is a fundamental concept that describes the behavior of a function as its input approaches a specific value. In simple terms, when we talk about \( \lim_{t \to a} \mathbf{r}(t) = \mathbf{b} \), we mean that as \( t \) gets closer to \( a \), the value of the function \( \mathbf{r}(t) \) gets closer to \( \mathbf{b} \). This concept of limits allows mathematicians to understand how functions behave near specific points and is essential for defining concepts like derivatives and integrals.
Some key ideas to remember about limits include:
Some key ideas to remember about limits include:
- Limits can be approached from either direction of a point \( a \). These are called one-sided limits.
- A limit exists if the function approaches the same value no matter the side from which \( t \) approaches \( a \).
- The \( \varepsilon-\delta \) definition rigorously verifies the limit's existence through the concept of distance and closeness.
Exploring Vector-Valued Functions
Vector-valued functions are an intriguing concept in calculus where the output is not a single real number, but a vector. When we look at functions like \( \mathbf{r}(t) \), we are interested in how the components of the vector change with respect to the input variable \( t \). These functions are critical in fields like physics and engineering, where objects have multiple degrees of freedom.
Some features of vector-valued functions include:
Some features of vector-valued functions include:
- These functions take a scalar input and return a vector, often represented as \( \mathbf{r}(t) = \langle r_1(t), r_2(t), \, r_3(t) \rangle \).
- Each component function (\( r_1(t), r_2(t), \text{etc.} \)) is a real-valued function itself.
- Limits and continuity can be examined component-wise, reducing the complexity of analysis.
Conceptualizing Continuity
Continuity is a fundamental concept that follows closely from limits. In simple words, a function is continuous at a point \( a \) if the limit of the function as \( t \) approaches \( a \) is the same as the function's value at \( a \), i.e., \( \lim_{t \to a} \mathbf{r}(t) = \mathbf{r}(a) \).
To grasp the idea of continuity:
To grasp the idea of continuity:
- A continuous function has no jumps, breaks, or holes at the point \( a \).
- Continuity can be examined through the epsilon-delta definition, where for a function \( f \) to be continuous at \( a \), for every \( \varepsilon > 0 \), there must be a \( \delta > 0 \) such that whenever \( |t-a| < \delta \), \(|f(t) - f(a)| < \varepsilon \).
- Continuity across an interval means the function is continuous at every point within that interval.
Other exercises in this chapter
Problem 43
Suppose \(\mathbf{u}\) and \(\mathbf{v}\) are vector functions that possess limits as \(t \rightarrow a\) and let \(c\) be a constant. Prove the following prope
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Find equations of the normal plane and osculating plane of the curve at the given point. \(x=2 \sin 3 t, y=t, z=2 \cos 3 t ; \quad(0, \pi,-2)\)
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Find equations of the normal plane and osculating plane of the curve at the given point. \(x=t, y=t^{2}, z=t^{3} ; \quad(1,1,1)\)
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Show that if \(r\) is a vector function such that \(r^{\prime \prime}\) exists, then $$ \frac{d}{d t}\left[\mathbf{r}(t) \times \mathbf{r}^{\prime}(t)\right]=\m
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