Problem 45
Question
Rationalize each denominator. See Example 4. $$ \frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}+\sqrt{3}} $$
Step-by-Step Solution
Verified Answer
The rationalized form is \(-5 + 2\sqrt{6}\).
1Step 1: Identify the Conjugate
To rationalize the denominator, we multiply the numerator and the denominator by the conjugate of the denominator. The conjugate of \( \sqrt{2} + \sqrt{3} \) is \( \sqrt{2} - \sqrt{3} \).
2Step 2: Multiply by the Conjugate
Multiply both the numerator and the denominator by the conjugate \( \sqrt{2} - \sqrt{3} \). This gives us: \[ \frac{(\sqrt{2} - \sqrt{3})(\sqrt{2} - \sqrt{3})}{(\sqrt{2} + \sqrt{3})(\sqrt{2} - \sqrt{3})} \]
3Step 3: Simplify the Numerator
Expand the numerator \((\sqrt{2} - \sqrt{3})(\sqrt{2} - \sqrt{3}) = (\sqrt{2})^2 - 2\sqrt{2}\sqrt{3} + (\sqrt{3})^2 = 2 - 2\sqrt{6} + 3 = 5 - 2\sqrt{6}.\)
4Step 4: Simplify the Denominator
Expand the denominator using the difference of squares: \((\sqrt{2} + \sqrt{3})(\sqrt{2} - \sqrt{3}) = (\sqrt{2})^2 - (\sqrt{3})^2 = 2 - 3 = -1.\)
5Step 5: Combine and Simplify
Combine the simplified numerator and denominator: \( \frac{5 - 2\sqrt{6}}{-1} = -5 + 2\sqrt{6}.\) This is the rationalized form of the expression.
Key Concepts
Understanding ConjugatesDeciphering Radical ExpressionsThe Power of Difference of Squares
Understanding Conjugates
In mathematics, a **conjugate** is a simple yet powerful tool, especially for dealing with radical expressions or complex numbers. When you have a binomial expression such as \(a + b\), its conjugate is \(a - b\). Essentially, this involves changing the sign of the second term. Conjugates are pivotal for rationalizing denominators, making expressions simpler and easier to handle.Why do we focus on conjugates when rationalizing denominators? Here's how:
- Conjugates help eliminate radicals from the denominator. This is crucial because expressions are often more manageable when radicals are not in the denominator.
- By multiplying by the conjugate, you leverage the **difference of squares** formula, which tidily eliminates both middle terms and results in rational numbers.
Deciphering Radical Expressions
Radical expressions include terms involving roots, such as square roots, cube roots, etc. These expressions can often look complicated but can be significantly simplified through some straightforward steps.Consider the radical expression \(\sqrt{2}+\sqrt{3}\). To break down these expressions:
- Identify the type of root involved—like a square root or cube root—that determines the fundamental behavior of the expression.
- When simplifying these, it can often involve operations such as multiplication, division, or finding conjugates.
The Power of Difference of Squares
The **difference of squares** is a crucial algebraic identity: \[(a + b)(a - b) = a^2 - b^2.\]This identity allows for easy simplification of expressions, particularly when working with conjugates. When we multiply a binomial expression by its conjugate, the middle terms cancel, simplifying the denominator dramatically when rationalizing. For instance, multiplying \(\sqrt{2} + \sqrt{3}\) by its conjugate \(\sqrt{2} - \sqrt{3}\) results in:
- The expression follows the difference of squares formula: \((\sqrt{2})^2 - (\sqrt{3})^2\).
- Calculating this results in \(2 - 3 = -1\).
Other exercises in this chapter
Problem 45
Write each quotient in the form \(a+b i .\) See Example 5. $$ \frac{3+5 i}{1+i} $$
View solution Problem 45
Use the properties of exponents to simplify each expression. Write with positive exponents. $$ 3^{1 / 4} \cdot 3^{3 / 8} $$
View solution Problem 46
Simplify. Assume that the variables represent any real number. $$ \sqrt[5]{(-7)^{5}} $$
View solution Problem 46
Solve. \(\sqrt{7 x-4}=\sqrt{4-7 x}\)
View solution