Problem 45
Question
Nitrobenzene can be reduced to aniline by (i) \(\mathrm{H}_{2} / \mathrm{Ni}\) (ii) \(\mathrm{Sn} / \mathrm{HCl}\) (iii) \(\mathrm{Zn} / \mathrm{NaOH}\) (iv) \(\mathrm{LiAlH}_{4}\) (a) i, ii and iii (b) \(\mathrm{i}\) and ii (c) i, ii and iv (d) only ii
Step-by-Step Solution
Verified Answer
The correct answer is (c) i, ii, and iv.
1Step 1: Identify the Reaction Type
The reduction of nitrobenzene to aniline is a type of reduction reaction where the nitro group (-NO2) in nitrobenzene is reduced to an amino group (-NH2) in aniline.
2Step 2: Evaluate the Reducers
Analyze each potential reducing agent: 1. \( \mathrm{H}_2 / \mathrm{Ni} \)2. \( \mathrm{Sn} / \mathrm{HCl} \)3. \( \mathrm{Zn} / \mathrm{NaOH} \)4. \( \mathrm{LiAlH}_4 \)However, \( \mathrm{Zn} / \mathrm{NaOH} \) is not typically used for the reduction of nitro groups in nitrobenzene to aniline.
3Step 3: Match with Options
Reduce nitrobenzene to aniline:- \( \mathrm{H}_{2} / \mathrm{Ni} \)- \( \mathrm{Sn} / \mathrm{HCl} \)- \( \mathrm{LiAlH}_{4} \)Identify which list of reagents (\( i, ii, iii, iv \)) matches one of the provided options.
4Step 4: Select Correct Answer
Based on the evaluation, the suitable reducing agents are:- \( \mathrm{H}_{2} / \mathrm{Ni}, \mathrm{Sn} / \mathrm{HCl}, \mathrm{LiAlH}_{4} \).Thus, option (c) matches these reagents.
Key Concepts
Nitrobenzene to AnilineReduction ReactionsReducing Agents in Organic Chemistry
Nitrobenzene to Aniline
The transformation of nitrobenzene to aniline is an important reaction in organic chemistry. Nitrobenzene has a nitro group \((-NO_2)\) which is converted to an amino group \((-NH_2)\) in aniline during this process. This reaction is crucial in producing aniline, which is a valuable industrial chemical used in dyes, pharmaceuticals, and other important products.
This reaction is a reduction reaction where we aim to increase the hydrogen content in the compound. It's essential to understand that the nitro group's oxygen atoms are replaced by hydrogen atoms. This conversion allows nitrobenzene, an aromatic compound with relatively low reactivity, to become aniline, which is more reactive and can be used in various applications.
This reaction is a reduction reaction where we aim to increase the hydrogen content in the compound. It's essential to understand that the nitro group's oxygen atoms are replaced by hydrogen atoms. This conversion allows nitrobenzene, an aromatic compound with relatively low reactivity, to become aniline, which is more reactive and can be used in various applications.
Reduction Reactions
Reduction reactions are processes in chemistry where a molecule, atom, or ion gains electrons, leading to a decrease in oxidation state. In the context of organic chemistry, reduction often involves adding hydrogen or removing oxygen from a molecule. When we discuss reducing nitrobenzene to aniline, this process specifically involves reducing the nitro group \((-NO_2)\) to an amino group \((-NH_2)\).
The key points in reduction reactions include:
The key points in reduction reactions include:
- Identifying the group to be reduced.
- Selecting a suitable reducing agent or catalysts.
- Ensuring the reaction conditions favor reduction.
Reducing Agents in Organic Chemistry
Reducing agents are substances that facilitate reduction reactions. In organic chemistry, they are crucial for converting various functional groups, including \(NO_2\) to \(NH_2\), as seen in the reduction of nitrobenzene to aniline. Choosing the right reducing agent depends on several factors, such as the specific reaction conditions and the desired product.
Common reducing agents include:
Common reducing agents include:
- Hydrogen gas \((H_2)\) with a nickel catalyst, which offers a direct method of hydrogenation.
- Metal acid combinations like tin \((Sn)\) with hydrochloric acid \((HCl)\), often used for reducing nitro compounds.
- Lithium aluminum hydride \((LiAlH_4)\), a powerful reducing agent used for more demanding reductions.
Other exercises in this chapter
Problem 39
When sodium formate is heated with soda lime, we get (a) \(\mathrm{CH}_{4}\) (b) \(\mathrm{H}_{2}\) (c) sodium oxalate (d) no action
View solution Problem 40
Sodium formate is heated at \(360^{\circ} \mathrm{C}\) to give (a) \(\mathrm{CO}\) (b) \(\mathrm{CO}_{2}\) (c) sodium oxalate (d) no action
View solution Problem 46
1-Methylcyclopentene can be converted into 2-methylcyclopentanol by (a) acid-catalyzed hydration (b) hydroboration oxidation (c) epoxide formation followed by r
View solution Problem 48
Predict the nature of \(\mathrm{P}\) in the following reaction \(\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{CCH}_{3} \frac{\mathrm{NaNH}_{2} \text { /inert solve
View solution