Problem 45
Question
Methane and sulfur vapor react to form carbon disulfide and hydrogen sulfide. Carbon disulfide reacts with \(\mathrm{Cl}_{2}(\mathrm{g})\) to form carbon tetrachloride and \(\mathrm{S}_{2} \mathrm{Cl}_{2}\) Further reaction of carbon disulfide and \(\overline{S_{2} C l_{2}}\) produces additional carbon tetrachloride and sulfur. Write a series of equations for the reactions described here.
Step-by-Step Solution
Verified Answer
The balanced reactions are: \( CH4(g) + 2S(g) \rightarrow CS2(g) + 2H2S(g) \) , \( CS2(g) + 3Cl2(g) \rightarrow CCl4(g) +S2Cl2(g) \) , \( CS2(g) + S2Cl2(g) \rightarrow CCl4(g) + 2S(g) \)
1Step 1: Formulate the first reaction
The first reaction is between Methane (CH4) and sulfur (S) to form Carbon disulfide (CS2) and Hydrogen Sulfide (H2S). This is represented by the equation: \(CH4(g) + 2S(g) \rightarrow CS2(g) + 2H2S(g) \)
2Step 2: Formulate the second reaction
The second reaction is between Carbon disulfide (CS2) and Chlorine gas (Cl2) to form Carbon tetrachloride (CCl4) and Disulfur dichloride (S2Cl2). This is represented by the equation: \(CS2(g) + 3Cl2(g) \rightarrow CCl4(g) +S2Cl2(g) \)
3Step 3: Formulate the third reaction
The third reaction is between Carbon disulfide (CS2) and Disulfur dichloride (S2Cl2) to form Carbon tetrachloride (CCl4) and sulfur (S). This is represented by the equation: \(CS2(g) + S2Cl2(g) \rightarrow CCl4(g) + 2S(g) \)
Key Concepts
Methane ReactionsReaction EquationsSulfur Compounds
Methane Reactions
Methane (\(\text{CH}_4\)) is a small molecule comprising one carbon atom bonded to four hydrogen atoms. It is the simplest alkane and an important component of the Earth's natural gas. Methane is highly flammable and is often used as a fuel source. However, it also reacts with other elements in a variety of chemical processes.
In the reactions outlined, methane reacts with sulfur vapor to produce carbon disulfide (\(\text{CS}_2\)) and hydrogen sulfide (\(\text{H}_2\text{S}\)). These are both sulfur compounds, which play crucial roles in industrial applications.
Here's a breakdown of what happens in this reaction:
In the reactions outlined, methane reacts with sulfur vapor to produce carbon disulfide (\(\text{CS}_2\)) and hydrogen sulfide (\(\text{H}_2\text{S}\)). These are both sulfur compounds, which play crucial roles in industrial applications.
Here's a breakdown of what happens in this reaction:
- \(\text{CH}_4\), a single carbon tetrahedrally bonded to four hydrogens, engages with sulfur vapor.
- Two sulfur atoms (\(2 \text{S}\)) contribute to the formation of \(\text{CS}_2\), replacing the hydrogen atoms.
- As a by-product, \(\text{H}_2\text{S}\), a gas with a distinct rotten egg smell, is also formed.
Reaction Equations
Reaction equations are symbolic representations of chemical reactions. They show the starting substances (reactants) and the substances formed (products) as a result of the reaction. These equations are fundamental to understanding chemical processes.
The steps provided give us a clear, systematic approach to forming balanced reaction equations:
The steps provided give us a clear, systematic approach to forming balanced reaction equations:
- The number of atoms for each element must be the same on both sides of the equation, adhering to the Law of Conservation of Mass.
- This is achieved by adjusting the coefficients before each molecular formula in the equation.
- Each reaction step in the sequence builds upon the previous ones, forming a logical chemical pathway.
Sulfur Compounds
Sulfur is an abundant non-metal element that readily forms compounds with various other elements, including hydrogen and carbon. It is essential in the production of different materials and chemicals.
In the provided reactions, sulfur forms critical compounds such as hydrogen sulfide (\(\text{H}_2\text{S}\)), carbon disulfide (\(\text{CS}_2\)), and disulfur dichloride (\(\text{S}_2\text{Cl}_2\)). Each has unique properties and uses:
In the provided reactions, sulfur forms critical compounds such as hydrogen sulfide (\(\text{H}_2\text{S}\)), carbon disulfide (\(\text{CS}_2\)), and disulfur dichloride (\(\text{S}_2\text{Cl}_2\)). Each has unique properties and uses:
- \(\text{H}_2\text{S}\) is a toxic, colorless gas with a characteristic rotten-egg odor, used in industrial processes.
- \(\text{CS}_2\) is a colorless, volatile liquid employed as a solvent in manufacturing rubber and other organic materials.
- \(\text{S}_2\text{Cl}_2\) is formed when \(\text{CS}_2\) reacts with chlorine, important for synthesizing other sulfur compounds.
Other exercises in this chapter
Problem 43
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Describe and explain the similarities and differences between the reaction of a silicate with an acid and that of a carbonate with an acid.
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Write plausible chemical equations for the (a) dissolving of lead(II) oxide in nitric acid; (b) heating of \(\operatorname{snCO}_{3}(\mathrm{s}) ;\) (c) reducti
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Write plausible chemical equations for preparing each compound from the indicated starting material: (a) \(\operatorname{SnCl}_{2}\) from \(\operatorname{SnO} ;
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