Problem 45
Question
Let $$ \begin{aligned} A &=\left[\begin{array}{cc} {1} & {0} \\ {0} & {1} \end{array}\right], \quad B=\left[\begin{array}{rr} {1} & {0} \\ {0} & {-1} \end{array}\right], \quad C=\left[\begin{array}{rr} {-1} & {0} \\ {0} & {1} \end{array}\right] \\ D &=\left[\begin{array}{rr} {-1} & {0} \\ {0} & {-1} \end{array}\right] \end{aligned} $$ Find the product of the sum of A and B and the difference between C and D.
Step-by-Step Solution
Verified Answer
The product of the sum of matrix A and B and the difference between matrix C and D is a 2x2 zero matrix. \[\left[\begin{array}{cc} 0 & 0 \ 0 & 0\end{array}\right]\].
1Step 1: Compute the Sum of Matrices A and B
Adding two matrices involves adding the corresponding elements. The sum of A and B, denoted as A+B, is a new matrix whose element in the i-th row and j-th column can be calculated as: \((A+B)_{ij}=A_{ij}+B_{ij}\). Applying this method gives the following matrix: \[ A+B=\left[\begin{array}{cc} 1+1 & 0+0 \ 0+0 & 1+(-1) \end{array}\right]=\left[\begin{array}{cc} 2 & 0 \ 0 & 0 \end{array}\right]. \]
2Step 2: Compute the Difference between Matrices C and D
Subtracting two matrices involves subtracting the corresponding elements. The difference of C and D, denoted as C-D, is a new matrix whose element in the i-th row and j-th column can be calculated as: \((C-D)_{ij}=C_{ij}-D{ij}\). Applying this method gives the following matrix: \[ C-D=\left[\begin{array}{cc} -1-(-1) & 0-0 \ 0-0 & 1-(-1) \end{array}\right]=\left[\begin{array}{cc} 0 & 0 \ 0 & 2 \end{array}\right]. \]
3Step 3: Compute the Product of Matrices (A+B) and (C-D)
Multiplication of two matrices results in a new matrix in which each element is the dot product of the corresponding row of the first matrix and the column of the second matrix. Let’s multiply (A+B) and (C-D) to get our final output: \[(A+B) \times (C-D)=\left[\begin{array}{cc} 2 & 0 \ 0 & 0 \end{array}\right] \times \left[\begin{array}{cc} 0 & 0 \ 0 & 2 \end{array}\right]=\left[\begin{array}{cc} 0 & 0 \ 0 & 0 \end{array}\right].\]
Key Concepts
Matrix AdditionMatrix SubtractionIdentity Matrix
Matrix Addition
Matrix addition is a straightforward concept that involves adding corresponding elements from two different matrices. Imagine each matrix like a grid, where numbers sit in boxes lined up in neat rows and columns. To add them up, you simply go box by box, adding the numbers from the same position in each matrix.
- For this operation to work, the matrices must have the same dimensions. This means they should have the same number of rows and columns.
- Each element in the resulting matrix is the sum of the elements from the two matrices at the same position.
Matrix Subtraction
Matrix subtraction works much like matrix addition, but instead of adding, you subtract the matching elements of one matrix from those in the other.
- Here, again, the matrices must have the same dimensions for the operation to be valid.
- Each element in the resulting matrix is the difference between the elements from the two matrices at the same position.
Identity Matrix
An identity matrix is a special type of matrix that acts as the "1" in matrix multiplication, meaning that any matrix multiplied by the identity matrix remains unchanged. It's a square matrix, featuring ones on the main diagonal from the top left to the bottom right and zeros everywhere else.
- For a 2x2 identity matrix, it looks like this: \[I=\left[\begin{array}{cc} 1 & 0 \ 0 & 1 \end{array}\right].\]
- In multiplication, any matrix, say matrix A, multiplied by the identity matrix, I, will be A again: \[A \times I = A.\]
Other exercises in this chapter
Problem 44
Write the system of linear equations for which Cramer's Rule yields the given determinants. $$D=\left|\begin{array}{rr}{2} & {-3} \\\\{5} & {6}\end{array}\right
View solution Problem 44
Find \(A^{-1}\) and check. $$ A=\left[\begin{array}{cc} {e^{2 x}} & {-e^{x}} \\ {e^{3 x}} & {e^{2 x}} \end{array}\right] $$
View solution Problem 45
Consider the linear system. $$ \left\\{\begin{aligned} x+3 y+z &=a^{2} \\ 2 x+5 y+2 a z &=0 \\ x+y+a^{2} z &=-9 \end{aligned}\right. $$ For which values of a wi
View solution Problem 45
Solve each equation for x. $$ \left|\begin{array}{rr} {-2} & {x} \\ {4} & {6} \end{array}\right|=32 $$
View solution