Problem 45
Question
Let \(A\) and \(B\) be two events such that \(P(\overline{A \cup B})=\frac{1}{6}\), \(P(A \cap B)=\frac{1}{4}\) and \(P(\bar{A})=\frac{1}{4}\), where \(\bar{A}\) stands for complement of event \(A\). Then events \(A\) and \(B\) are [2005] (a) equally likely and mutually exclusive (b) equally likely but not independent (c) independent but not equally likely (d) mutually exclusive and independent
Step-by-Step Solution
Verified Answer
Events \(A\) and \(B\) are independent but not equally likely.
1Step 1: Identify Relevant Formulas
To solve this problem, we need three probability concepts: complement rules, probability addition rules, and independence. We know if events are independent, then \( P(A \cap B) = P(A) \cdot P(B) \). Also, we have \( P(\bar{A}) = 1 - P(A) \) and \( P(\overline{A \cup B}) = 1 - P(A \cup B) \).
2Step 2: Calculate \(P(A)\)
Given \(P(\bar{A}) = \frac{1}{4}\), use \(P(A) = 1 - P(\bar{A})\) to find \(P(A)\). So, \(P(A) = 1 - \frac{1}{4} = \frac{3}{4}\).
3Step 3: Calculate \(P(A \cup B)\) Using Complement
We know \(P(\overline{A \cup B}) = \frac{1}{6}\), therefore, \(P(A \cup B) = 1 - P(\overline{A \cup B}) = 1 - \frac{1}{6} = \frac{5}{6}\).
4Step 4: Use Probability Addition Formula
The formula for the union of two events is \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\). Plug in the known values: \(\frac{5}{6} = \frac{3}{4} + P(B) - \frac{1}{4}\).
5Step 5: Solve for \(P(B)\)
Rearrange the above equation to solve for \(P(B)\): \(P(B) = \frac{5}{6} - \frac{2}{4}\). Simplify the right side to get \(P(B) = \frac{1}{3}\).
6Step 6: Check Independence
For two events to be independent, \(P(A \cap B) = P(A) \cdot P(B)\). Check if \(\frac{1}{4} = \frac{3}{4} \cdot \frac{1}{3}\). The right side simplifies to \(\frac{3}{12} = \frac{1}{4}\), so they are independent.
7Step 7: Check if Events are Equally Likely
Two events are equally likely if \(P(A) = P(B)\). Since \(P(A) = \frac{3}{4}\) and \(P(B) = \frac{1}{3}\), they are not equally likely.
Key Concepts
Probability principlesEvent independenceProbability formulas
Probability principles
Probability is a measure of the likelihood that a particular event will occur. It relies on fundamental principles that help understand random events and their associated uncertainties. There are a few key principles to keep in mind:
- Complement Rule: For any event, the probability that it does not occur is called the complement of the event. If the probability that event \(A\) occurs is \(P(A)\), the probability that \(A\) does not occur, denoted as \(\bar{A}\), is \(1 - P(A)\).
- Addition Rule: This is used to determine the probability of the union of two events (\(A \cup B\)). For any two events \(A\) and \(B\), the probability that at least one of them occurs is \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\).
- Multiplication Rule: This principle helps determine the probability that two independent events occur together. If events \(A\) and \(B\) are independent, their joint probability is \(P(A \cap B) = P(A) \cdot P(B)\).
Event independence
In probability theory, two events are considered independent if the occurrence of one event does not affect the probability of the other. This concept is critical when analyzing event relationships.
- If events \(A\) and \(B\) are independent, it means \(P(A \cap B) = P(A) \cdot P(B)\).
- Independence implies that events do not influence each other.
- Checking independence often involves verifying this mathematical condition using given probabilities.
Probability formulas
There are key formulas in probability that help solve problems involving events and their likelihoods. These formulas allow us to compute probabilities systematically and with precision.
- Complement Formula: \(P(\bar{A}) = 1 - P(A)\) helps us find the chance that an event does not happen.
- Addition Formula: The formula \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\) calculates the probability that either of two events (or both) happen.
- Multiplication for Independence: \(P(A \cap B) = P(A) \cdot P(B)\) when \(A\) and \(B\) are independent shows joint probability.
Other exercises in this chapter
Problem 43
Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are \(0.3\) and \(0.2\), respectively. The second pla
View solution Problem 44
Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the
View solution Problem 46
The probability that \(A\) speaks truth is \(\frac{4}{5}\), while the probability for \(B\) is \(\frac{3}{4}\). The probability that they contradict each other
View solution Problem 47
A problem in mathematics is given to three students \(A, B\), \(C\) and their respective probability of solving the problem is \(\frac{1}{2}, \frac{1}{3}\) and
View solution