Problem 45
Question
How many megacoulombs of positive charge are in \(1.00 \mathrm{~mol}\) of neutral molecular-hydrogen gas \(\left(\mathrm{H}_{2}\right) ?\)
Step-by-Step Solution
Verified Answer
There are 0.1928 megacoulombs of positive charge in 1 mole of neutral \(\mathrm{H}_2\) gas.
1Step 1: Calculate the number of molecules in one mole
To find the number of molecules in one mole, use Avogadro's number, which is \(6.022 \times 10^{23}\) molecules per mole. Since there is 1 mole of \(\mathrm{H}_2\) gas, there are \(6.022 \times 10^{23}\) molecules of \(\mathrm{H}_2\).
2Step 2: Determine the number of protons in each molecule
Each \(\mathrm{H}_2\) molecule consists of 2 hydrogen atoms. Each hydrogen atom contains 1 proton. Therefore, a single molecule of \(\mathrm{H}_2\) contains 2 protons.
3Step 3: Calculate the total number of protons in the sample
Multiply the number of molecules by the number of protons per molecule: \[6.022 \times 10^{23} \text{ molecules} \times 2 \text{ protons/molecule} = 1.2044 \times 10^{24} \text{ protons}.\]
4Step 4: Convert protons to charge in coulombs
The charge of a single proton is approximately \(1.602 \times 10^{-19}\) coulombs. Multiply the total number of protons by the charge of one proton to get the net charge in coulombs:\[1.2044 \times 10^{24} \text{ protons} \times 1.602 \times 10^{-19} \text{ C/proton} = 1.928 \times 10^{5} \text{ C}.\]
5Step 5: Convert coulombs to megacoulombs
Divide the total charge in coulombs by \(10^6\) to convert to megacoulombs (since 1 megacoulomb = \(10^6\) coulombs):\[1.928 \times 10^{5} \text{ C} \div 10^6 = 0.1928 \text{ megacoulombs}.\]
Key Concepts
Mole conceptAvogadro's numberCharge of a proton
Mole concept
The mole is a fundamental concept in chemistry that answers the basic question: How many molecules or atoms are present in a given sample? This concept allows chemists to count particles directly by weighing.
- 1 mole is equivalent to 6.022 x 1023 particles. These particles can be atoms, molecules, ions, etc., depending on the context.
- The mole provides a bridge between the atomic scale and human-level measurements, allowing us to work with manageable amounts.
- The concept simplifies chemical equations and reactions, turning them into mole calculations that are more intuitive and practical.
Avogadro's number
Avogadro's number is a constant that is fundamental to the mole concept. It is named after the scientist Amedeo Avogadro and is defined as the number of constituent particles (usually atoms or molecules) in one mole of a given substance.
- Numerically, Avogadro's number is approximately 6.022 x 1023 particles per mole.
- This number is crucial for converting between the number of moles and the number of atoms or molecules.
- It helps in understanding the scale at which the chemical processes happen, explaining phenomena significantly at a macro and micro level.
Charge of a proton
Understanding the charge of a proton is fundamental when dealing with electricity and chemistry, as it explains the nature of atomic particles.
- A single proton carries a positive charge which is equal in magnitude to the negative charge of an electron, quantified as approximately 1.602 x 10-19 coulombs.
- This consistency in charge allows for neutral matter under normal conditions, as seen in our example with H2.
- In the case of the hydrogen molecule, knowing the charge of a proton is essential for calculating the total electric charge resulting from a sample quantity, such as one mole of H2 gas.
Other exercises in this chapter
Problem 38
Figure 21-37 shows four identical conducting spheres that are actually well separated from one another. Sphere \(W\) (with an initial charge of zero) is touched
View solution Problem 41
(a) What equal positive charges would have to be placed En Earth and on the Moon to neutralize their gravitational attraction? (b) Why don't you need to know th
View solution Problem 47
Point charges of \(+6.0 \mu \mathrm{C}\) and \(-4.0 \mu \mathrm{C}\) are placed on an \(x\) axis, at \(x=8.0 \mathrm{~m}\) and \(x=16 \mathrm{~m},\) respectivel
View solution Problem 49
A neutron consists of one "up" quark of charge \(+2 e / 3\) and two "down" quarks each having charge \(-e / 3 .\) If we assume that the down quarks are \(2.6 \t
View solution