Problem 45
Question
For the following problems, perform the multiplications and divisions. $$ (x-2) \cdot \frac{x-1}{x-2} $$
Step-by-Step Solution
Verified Answer
Answer: The simplified form of the expression is `x-1`.
1Step 1: Identify common factors
The expression is given as
$$
(x-2) \cdot \frac{x-1}{x-2}
$$
Here, we can see that `(x-2)` is a common factor in both the numerator and the denominator.
2Step 2: Cancel out the common factors
Since `(x-2)` is a common factor in both the numerator and the denominator, we can cancel it out:
$$
(x-2) \cdot \frac{x-1}{x-2} = \cancel{(x-2)} \cdot \frac{x-1}{\cancel{x-2}}
$$
3Step 3: Perform the multiplication
After canceling out the common factor `(x-2)`, we are left with:
$$
1\cdot(x-1)
$$
Multiplying this, we get the final simplified expression:
$$
x-1
$$
Key Concepts
Canceling Common FactorsMultiplying ExpressionsSimplifying Algebraic Expressions
Canceling Common Factors
In algebra, one crucial skill is the ability to cancel common factors in a fraction or expression. This technique helps simplify expressions and solve problems efficiently. When you have a fraction, check if the same factor appears in both the numerator and the denominator. If it does, that factor can be removed or 'canceled' because it is common to both parts.
Consider the example from the exercise: \( (x-2) \cdot \frac{x-1}{x-2} \). Here, \((x-2)\) is present in both the numerator, as part of \((x-2)\cdot\), and in the denominator \(\frac{...}{x-2}\). As they appear on both top and bottom, they can be canceled out. This simplifies the expression and eliminates unnecessary complexity.
**Steps to Cancel Common Factors:**
Consider the example from the exercise: \( (x-2) \cdot \frac{x-1}{x-2} \). Here, \((x-2)\) is present in both the numerator, as part of \((x-2)\cdot\), and in the denominator \(\frac{...}{x-2}\). As they appear on both top and bottom, they can be canceled out. This simplifies the expression and eliminates unnecessary complexity.
**Steps to Cancel Common Factors:**
- Identify matching terms in both the numerator and the denominator.
- Cross out or remove the factor that appears in both places, treating it as multiplication by 1.
- Recalculate the expression without these terms.
Multiplying Expressions
Multiplying expressions is a fundamental aspect of algebra that involves combining several terms or factors into a single entity. It often eases problem-solving by converting complex expressions into more manageable forms. This process includes distributing terms and applying the basic rules of arithmetic.
**How Multiplication Works in the Example:**
**How Multiplication Works in the Example:**
- After canceling the common factor \((x-2)\), the problem simplifies to: \(1\cdot(x-1)\).
- Multiplying it, you follow the rule where anything multiplied by 1 stays the same.
- This highlights why multiplying doesn't alter the expression's core value: \((x-1)\).
Simplifying Algebraic Expressions
Simplifying algebraic expressions is all about making them easier to understand or work with. A simplified expression is clearer and often more straightforward to use in further calculations.
To simplify an expression, follow these general steps:
To simplify an expression, follow these general steps:
- Use any available opportunities to cancel out common factors or terms.
- Perform arithmetic operations, such as multiplication or division, to unify the parts of the expression.
- Rewrite the expression in its simplest form, free of unnecessary components.
Other exercises in this chapter
Problem 45
For the following problems, perform the divisions. $$ \frac{a^{3}-8}{a+2} $$
View solution Problem 45
For the following problems, solve the rational equations. $$ \frac{12}{a^{2}}-\frac{4}{a}=1 $$
View solution Problem 45
For the following problems, add or subtract the rational expressions. $$ \frac{2}{3 x}+\frac{4}{6 x^{2}} $$
View solution Problem 45
For the following problems, reduce each rational expression to lowest terms. $$ \frac{6 b^{2}-b}{6 b^{2}+11 b-2} $$
View solution