Problem 45
Question
For the following exercises, graph the polynomial functions. Note \(x\) - and \(y\) - intercepts, multiplicity, and end behavior. $$ k(x)=(x-3)^{3}(x-2)^{2} $$
Step-by-Step Solution
Verified Answer
The x-intercepts are at 3 and 2, with end behaviors (+∞, -∞) and y-intercept at -108.
1Step 1: Identify the x-intercepts
The x-intercepts occur where the function equals zero. For \(k(x)=(x-3)^3(x-2)^2\), set each factor equal to zero: \(x-3=0\) and \(x-2=0\). Thus, the x-intercepts are \(x=3\) and \(x=2\).
2Step 2: Determine the multiplicity of each root
The multiplicity of a root is the exponent of the factor. For \((x-3)^3\), the root \(x=3\) has a multiplicity of 3. For \((x-2)^2\), the root \(x=2\) has a multiplicity of 2.
3Step 3: Determine the y-intercept
The y-intercept occurs where \(x=0\). Substitute \(x=0\) into the function: \(k(0)=(0-3)^3(0-2)^2=(-3)^3(-2)^2=-27 \times 4=-108\). Thus, the y-intercept is at \(y=-108\).
4Step 4: Analyze end behavior
The end behavior is determined by the leading term when the polynomial is expanded. The highest degree term is \(x^5\), which is positive, so as \(x\to\infty\), \(k(x)\to\infty\), and as \(x\to -\infty\), \(k(x)\to -\infty\).
5Step 5: Sketch the graph using key features
Plot the x-intercepts \(x=3\) and \(x=2\), noting that \(x=3\) has odd multiplicity (graph passes through) and \(x=2\) has even multiplicity (graph touches at the axis). Plot the y-intercept at \(y=-108\) and draw the end behavior as described in Step 4.
Key Concepts
Understanding x-interceptsWhat is multiplicity?Finding the y-interceptExamining end behavior
Understanding x-intercepts
In polynomial functions, x-intercepts are the points where the graph crosses or touches the x-axis. These intercepts are found by setting the polynomial equation equal to zero and solving for the values of x. For the polynomial function \(k(x)=(x-3)^3(x-2)^2\), we find the x-intercepts by solving the equations \(x-3=0\) and \(x-2=0\). This gives us the x-intercepts at \(x=3\) and \(x=2\).
- At \(x=3\): The graph will either cross or touch the x-axis.
- At \(x=2\): Similarly, the graph will interact with the x-axis.
What is multiplicity?
Multiplicity refers to the number of times a particular x-intercept is repeated. It is indicated by the exponent of the factor in the polynomial. In \(k(x)=(x-3)^3(x-2)^2\), each factor's exponent tells us the multiplicity:
- \(x=3\) has multiplicity 3: This means the graph will cross the x-axis at \(x=3\), creating a visible curve due to the odd multiplicity.
- \(x=2\) has multiplicity 2: As this is an even multiplicity, the graph will "bounce" off the x-axis at \(x=2\), touching but not crossing.
Finding the y-intercept
The y-intercept occurs where the graph crosses the y-axis, or when \(x=0\). To find the y-intercept of \(k(x)\), we substitute \(x=0\) in the function: \[(0-3)^3(0-2)^2 = (-3)^3(-2)^2 = -27 \times 4 = -108.\]
Thus, the y-intercept is at \(y=-108\).
Thus, the y-intercept is at \(y=-108\).
- The y-intercept is a useful point to plot, helping anchor the graph vertically.
- It shows the function's value when all terms linked with x are at their simplest form.
Examining end behavior
The end behavior of a polynomial function describes how the graph behaves as \(x\) approaches positive or negative infinity. For \(k(x)=(x-3)^3(x-2)^2\), the leading term, which is derived from multiplying all the highest degree terms of each factor, is \(x^5\).
- The degree (5) being odd and the leading coefficient being positive means the graph will rise to infinity as \(x\) approaches positive infinity.
- Conversely, as \(x\) approaches negative infinity, the graph will fall to negative infinity.
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