Problem 45
Question
For the following exercises, evaluate the base \(b\) logarithmic expression without using a calculator. $$6 \log _{8}(4)$$
Step-by-Step Solution
Verified Answer
The value of the expression is 4.
1Step 1: Understanding the Logarithmic Expression
We need to evaluate the expression \(6 \log _{8}(4)\) without using a calculator. We will use logarithm properties and basic math calculations.
2Step 2: Rewrite the Logarithm in a Different Base
Notice that \(4 = 2^2\), so we can use the change of base formula. Write \(4\) as \(2^2\): \[\log_{8}(4) = \log_{8}(2^2).\]
3Step 3: Apply the Power Rule of Logarithms
Using the power rule \(\log_{b}(a^n) = n\cdot \log_{b}(a)\), we have:\[\log_{8}(2^2) = 2 \cdot \log_{8}(2).\]
4Step 4: Evaluate \(\log_{8}(2)\) Using Base Conversion
Since \(8 = 2^3\), we can write \(\log_{8}(2)\) as \(\log_{2^3}(2)\). Using the properties of logarithms, we know\[\log_{b^n}(a) = \frac{1}{n} \cdot \log_{b}(a),\]so \[\log_{2^3}(2) = \frac{1}{3} \cdot \log_{2}(2) = \frac{1}{3} \cdot 1 = \frac{1}{3}.\]
5Step 5: Calculate \(6 \log_{8}(4)\)
Now substitute back \(\log_{8}(4) = 2 \log_{8}(2) = 2 \times \frac{1}{3} = \frac{2}{3}\) into the original expression:\[6 \log_{8}(4) = 6 \times \frac{2}{3} = 4.\]
Key Concepts
Change of Base FormulaPower Rule of LogarithmsLogarithm Properties
Change of Base Formula
Logarithms can often seem complex at first, but they become much easier to manage when you understand the change of base formula. This formula is especially useful when you want to simplify a logarithmic expression or when you're working with bases that are not convenient for calculation by hand.
The change of base formula states that for any positive numbers \(a, b,\) and \(c\) where \(a eq 1\) and \(c eq 1\), you can convert a logarithm to a different base using the formula:
The change of base formula states that for any positive numbers \(a, b,\) and \(c\) where \(a eq 1\) and \(c eq 1\), you can convert a logarithm to a different base using the formula:
- \(\log_{b}(a) = \frac{\log_{c}(a)}{\log_{c}(b)}\)
Power Rule of Logarithms
The power rule of logarithms is a handy tool when dealing with expressions that involve exponents inside a logarithm. This rule states that if you have a logarithm of a number raised to a power, you can bring the power out in front of the logarithm. Specifically, for any positive number \(a\) and any real number \(n\), the power rule is written as:
It is essential to remember this rule, as it can take what appears to be an intimidating expression and simplify it into a straightforward multiplication problem.
- \(\log_{b}(a^n) = n \cdot \log_{b}(a)\)
It is essential to remember this rule, as it can take what appears to be an intimidating expression and simplify it into a straightforward multiplication problem.
Logarithm Properties
The properties of logarithms are foundational tools for manipulating and simplifying logarithmic expressions. Frequently, these properties allow us to turn a complex problem into a more manageable form. Understanding these properties can help you solve problems more efficiently and effectively.
Here are a few fundamental properties of logarithms every student should know:
Here are a few fundamental properties of logarithms every student should know:
- Product Rule: \(\log_{b}(xy) = \log_{b}(x) + \log_{b}(y)\). This helps in breaking down multiplication inside a logarithm into simple addition.
- Quotient Rule: \(\log_{b}(\frac{x}{y}) = \log_{b}(x) - \log_{b}(y)\). This rule is useful for converting division inside a logarithm to subtraction.
- Power Rule: As discussed earlier, \(\log_{b}(a^n) = n \cdot \log_{b}(a)\). It simplifies logarithms of powers by converting them to multiplications.
- Base Change Rule: This helps convert logarithms to simpler bases, especially when computation needs to be simplified.
Other exercises in this chapter
Problem 45
For the following exercises, evaluate the exponential functions for the indicated value of \(x\). $$ h(x)=-\frac{1}{2}\left(\frac{1}{2}\right)^{x}+6 \text { for
View solution Problem 45
For the following exercises, evaluate each function. Round answers to four decimal places, if necessary. $$f(x)=-4^{2 x+3}, \text { for } f(-1)$$
View solution Problem 46
For the following exercises, sketch the graph of the indicated function. $$g(x)=\log (4 x+16)+4$$
View solution Problem 46
Refer to Table. $$ \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|} \hline \boldsymbol{x} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline \boldsymbol{f}(\boldsymbol{x}
View solution