Problem 45
Question
Find the speed of a particle whose relativistic kinetic energy is 50\(\%\) greater than the Newtonian value for the same speed.
Step-by-Step Solution
Verified Answer
The speed is \( v = c \sqrt{\frac{3}{7}} \).
1Step 1: Understand the Problem
The problem asks us to find the speed of a particle such that its relativistic kinetic energy is 50% greater than its non-relativistic (or Newtonian) kinetic energy.
2Step 2: Relativistic and Newtonian Kinetic Energy Comparison
The relativistic kinetic energy is given by \( K_r = \left( \gamma - 1 \right) mc^2 \) and the Newtonian kinetic energy is \( K_n = \frac{1}{2} mv^2 \), where \( \gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} \). We are given that \( K_r = 1.5 K_n \).
3Step 3: Relate the Energies with the Given Condition
Set up the equation based on the given condition: \( \left( \gamma - 1 \right) mc^2 = 1.5 \times \frac{1}{2} mv^2 \). Simplify the equation to get \( \gamma - 1 = \frac{0.75 v^2}{c^2} \).
4Step 4: Substitute Gamma and Solve for v
Substitute the expression for \( \gamma \): \( \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} - 1 = \frac{0.75 v^2}{c^2} \). Multiply throughout by \( \sqrt{1 - \frac{v^2}{c^2}} \) to eliminate the square root, then solve the resulting equation to find \( v \).
5Step 5: Algebraic Manipulation
After multiplying through, isolate \( v \) to get \( v = c \sqrt{\frac{3}{7}} \) by solving \( 1 - \frac{v^2}{c^2} = \left(\frac{3}{7} \right) \).
6Step 6: Conclusion
Therefore, the relativistic speed \( v \) of the particle when its kinetic energy is 50% greater than the Newtonian value is \( v = c \sqrt{\frac{3}{7}} \).
Key Concepts
Newtonian Kinetic EnergyLorentz FactorSpeed of Light
Newtonian Kinetic Energy
Newtonian kinetic energy describes the energy an object possesses due to its motion in classical mechanics. This concept is essential when dealing with objects moving at speeds much slower than the speed of light. In this regime, relativistic effects are negligible, and the kinetic energy (\[ K_n \]) is given by the familiar equation:\[ K_n = \frac{1}{2} mv^2 \]where:
- \( m \): mass of the object
- \( v \): velocity of the object
Lorentz Factor
The Lorentz factor, denoted as \( \gamma \), is crucial in understanding relativistic physics, especially when velocities are comparable to the speed of light. As an object's velocity increases and approaches the speed of light, the Lorentz factor quantifies the degree to which Newtonian predictions need correction. Mathematically, it is expressed as:\[ \gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} \]Where:
- \( v \): speed of the object
- \( c \): speed of light in a vacuum (~\( 3 \times 10^8 \) meters per second)
Speed of Light
The speed of light, represented by \( c \), is a fundamental constant in physics, valued at approximately \( 3 \times 10^8 \) meters per second. It embodies the maximum speed at which information or matter can travel through space in our universe. An essential concept in Einstein’s theory of relativity, the speed of light underpins the relativistic effects perceived at velocities nearing \( c \).A key implication of the speed of light in relativity is the prediction of time dilation and length contraction. Objects communicated or observed at this speed establish a universal speed limit. No material object can reach or exceed the speed of light due to principal constraints of energy and mass that arise in special relativity.This speed limit influences equations like those for relativistic kinetic energy, where calculations ensure that objects remain subluminal, avoiding paradoxes of exceeding this universal constant. Understanding \( c \) provides insights into the boundaries of classical mechanics and guides us in traversing the realm of high-speed physics.
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