Problem 45
Question
Find the solutions of the equation $$ 4 x^{2}+x+3=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \( x = \frac{-1 + i\sqrt{47}}{8} \) and \( x = \frac{-1 - i\sqrt{47}}{8} \).
1Step 1: Identify the Quadratic Equation
The given equation is a quadratic equation: \( 4x^2 + x + 3 = 0 \). A quadratic equation is of the form \( ax^2 + bx + c = 0 \) where \( a \), \( b \), and \( c \) are constants.
2Step 2: Determine Coefficients
For the equation \( 4x^2 + x + 3 = 0 \), identify the coefficients: \( a = 4 \), \( b = 1 \), and \( c = 3 \). This information will be used in the quadratic formula.
3Step 3: Apply the Quadratic Formula
To find the roots of the quadratic equation, use the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
4Step 4: Calculate the Discriminant
The discriminant \( \Delta \) is given by \( b^2 - 4ac \). Substitute the values of \( a \), \( b \), and \( c \) into this formula: \( 1^2 - 4 \times 4 \times 3 = 1 - 48 = -47 \).
5Step 5: Evaluate the Discriminant
Since the discriminant \( \Delta = -47 \) is less than zero, the quadratic equation does not have real solutions but instead has two complex conjugate solutions.
6Step 6: Find the Complex Solutions
Since the discriminant is negative, use \( x = \frac{-b \pm i\sqrt{-\Delta}}{2a} \) to find the complex solutions. This becomes: \( x = \frac{-1 \pm i\sqrt{47}}{8} \). Thus, the solutions are \( x = \frac{-1 + i\sqrt{47}}{8} \) and \( x = \frac{-1 - i\sqrt{47}}{8} \).
Key Concepts
Complex SolutionsQuadratic FormulaDiscriminant
Complex Solutions
In some cases, quadratic equations may not have real solutions. This happens when the discriminant, a value calculated from the equation's coefficients, is less than zero. If the discriminant is negative, the solutions to the quadratic equation will be complex. Complex numbers go beyond the traditional number line. They include a real part and an imaginary part, the latter involving the imaginary unit, denoted as \(i\), where \(i^2 = -1\).
When the discriminant is negative, the solutions take the form of complex conjugates. These solutions are expressed as:
When the discriminant is negative, the solutions take the form of complex conjugates. These solutions are expressed as:
- \( x = \frac{-b + i\sqrt{-\Delta}}{2a} \)
- \( x = \frac{-b - i\sqrt{-\Delta}}{2a} \)
Quadratic Formula
The quadratic formula is an essential tool for finding the solutions to any quadratic equation of the form \(ax^2 + bx + c = 0\). This formula provides a straightforward path to uncover the solution, even when the coefficients and constants involved are hard to manage manually. The quadratic formula is given by:
In our problem, the quadratic equation \(4x^2 + x + 3 = 0\) makes use of coefficients \(a = 4\), \(b = 1\), and \(c = 3\). Applying these into the quadratic formula, we determine that the solutions are complex, owing to the negative discriminant value calculated from these coefficients.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
In our problem, the quadratic equation \(4x^2 + x + 3 = 0\) makes use of coefficients \(a = 4\), \(b = 1\), and \(c = 3\). Applying these into the quadratic formula, we determine that the solutions are complex, owing to the negative discriminant value calculated from these coefficients.
Discriminant
The discriminant is a component of the quadratic formula that reveals the nature of the solutions of a quadratic equation. It is calculated as \( \Delta = b^2 - 4ac \). The value of the discriminant can take one of three roles:
- If \( \Delta > 0\), there are two distinct real solutions.
- If \( \Delta = 0\), there is exactly one real solution (a repeated root).
- If \( \Delta < 0\), there are no real solutions, but instead two complex conjugate solutions.
Other exercises in this chapter
Problem 44
Exer. 11-46: Simplify. $$ \left(\frac{c^{-4}}{16 d^{8}}\right)^{3 / 4} $$
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Exer. 43-44: Approximate the real-number expression. Express the answer in scientific notation accurate to four significant figures. (a) \(\sqrt{\left|3.45-1.2
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Factor the polynomial. $$ r s+4 s t $$
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Exer. 11-46: Simplify. $$ \frac{\left(x^{6} y^{3}\right)^{-1 / 3}}{\left(x^{4} y^{2}\right)^{-1 / 2}} $$
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