Problem 45
Question
Find the inverse of the matrix. For what value(s) of x, if any, does the matrix have no inverse? $$ \left[\begin{array}{rrr}{1} & {e^{x}} & {0} \\ {e^{x}} & {-e^{2 x}} & {0} \\\ {0} & {0} & {2}\end{array}\right] $$
Step-by-Step Solution
Verified Answer
The matrix is invertible for all real \(x\), as the determinant is never zero.
1Step 1: Determine the Determinant
To find the inverse of a matrix, first compute its determinant. For this 3x3 matrix, \[\text{det}(A) = 1 \cdot \left( -e^{2x} \cdot 2 - 0 \right) - e^x \cdot \left(e^x \cdot 2 - 0 \right) + 0 \cdot \left(e^x \cdot 0 - (-e^{2x}) \cdot 0\right) = -2e^{2x} - 2(e^x)^2.\] This simplifies to \[\text{det}(A) = -2e^{2x} - 2e^{2x} = -4e^{2x}.\] Since the determinant is zero when \[-4e^{2x} = 0,\] this occurs when \[e^{2x} = 0.\] However, \(e^{2x}\) is never zero for any real \(x\). Therefore, the matrix has a determinant of zero for no real value of \(x\).
2Step 2: Find the Inverse Matrix Condition
Since the determinant is never zero for real \(x\), the matrix is always invertible. To find the inverse, use the formula for the inverse of a 3x3 matrix: \[A^{-1} = \frac{1}{\text{det}(A)} \cdot \text{adj}(A),\] where \(\text{adj}(A)\) is the adjugate of \(A\). However, calculating \(A^{-1}\) requires a nonzero determinant, so we confirm invertibility.
3Step 3: Conclusion on Invertibility
As we previously found, \[\text{det}(A) = -4e^{2x},\] which is never zero for real \(x\), indicating that the matrix has an inverse for all real \(x\) values, since the exponential function never yields zero.
Key Concepts
Determinant of a MatrixAdjugate of a MatrixInvertibility of Matrices
Determinant of a Matrix
The determinant of a matrix is a special number calculated from its elements. It plays a crucial role in understanding whether a matrix is invertible. For any 2x2 or 3x3 matrix, the determinant can indicate important properties about the matrix.
When dealing with a 3x3 matrix, to find the determinant, we use a specific formula that involves multiplying and adding or subtracting the elements and their cofactors. For the given matrix:
When dealing with a 3x3 matrix, to find the determinant, we use a specific formula that involves multiplying and adding or subtracting the elements and their cofactors. For the given matrix:
- The element combinations are used in a cross-multiplying fashion, similar to a mix of multiplication and addition involving all rows.
- This complexity is why understanding how to arrange and handle cofactors is important for solving the determinant.
Adjugate of a Matrix
The adjugate of a matrix is intimately connected to finding a matrix inverse. The adjugate is essentially the transpose of the cofactor matrix derived from the original matrix.
Here's how you find it:
Here's how you find it:
- First, calculate the cofactors for each element of the matrix, which involves the determinant of the submatrix formed by removing the row and column of the specific element.
- The cofactor matrix is then formed by applying the right signs according to a checkerboard pattern of positives and negatives.
- After forming the cofactor matrix, you take its transpose – this matrix becomes the adjugate.
Invertibility of Matrices
Invertibility is a core concept in linear algebra. A matrix is invertible if there exists another matrix that when multiplied results in the identity matrix, much like how with regular numbers, every number has a reciprocal except zero.
For matrices, invertibility hinges on the determinant:
This concept of invertibility has widespread applications, such as solving systems of linear equations, where the presence of an inverse matrix can simplify solutions significantly.
For matrices, invertibility hinges on the determinant:
- If a matrix has a determinant of zero, then the matrix does not have an inverse. It is called "singular".
- If a matrix's determinant is anything but zero, it is called "nonsingular" or "invertible". It assures that an inverse matrix exists.
This concept of invertibility has widespread applications, such as solving systems of linear equations, where the presence of an inverse matrix can simplify solutions significantly.
Other exercises in this chapter
Problem 45
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